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Add solution to new list comprehension exercise

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Original file line number	Diff line number	Diff line change
`@@ -38,3 +38,11 @@`
`38`	`38`	`# Exercise 7`
`39`	`39`	`# Verify that breakfast has three items using len()`
`40`	`40`	`print(len(breakfast)==3)`
	`41`	`+`
	`42`	`+`
	`43`	`+# Exercise 8`
	`44`	+# Create a new list called `lengths` using a list
	`45`	`+# comprehension that contains the lengths of each`
	`46`	+# string in the `breakfast` list.
	`47`	`+lengths= [len(item)foriteminbreakfast]`
	`48`	`+print(lengths)`

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