static memberelseBranchHasWrongType(a0:System.String,a1:System.String)=(GetStringFunc("elseBranchHasWrongType",",,,%s,,,%s,,,") a0 a1)

static memberfollowingPatternMatchClauseHasWrongType(a0:System.String,a1:System.String)=(GetStringFunc("followingPatternMatchClauseHasWrongType",",,,%s,,,%s,,,") a0 a1)

missingElseBranch,"The 'if' expression is missing an 'else' branch. The 'then' branch has type '%s'. Because 'if' is an expression, and not a statement, add an 'else' branch which returns a value of the same type."

ifExpression,"The 'if' expression needs to have type '%s' to satisfy context type requirements. It currently has type '%s'."

elseBranchHasWrongType,"All branches of an 'if' expression must have the same type. This expression was expected to have type '%s', but here has type '%s'."

followingPatternMatchClauseHasWrongType,"All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '%s', buthere has type '%s'."

followingPatternMatchClauseHasWrongType,"All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '%s', butthis branch returned a value of type '%s'."

patternMatchGuardIsNotBool,"A pattern match guard must be of type 'bool', but this 'when' expression is of type '%s'."

commaInsteadOfSemicolonInRecord,"A ';' is used to separate field values in records. Consider replacing ',' with ';'."

derefInsteadOfNot,"The '!' operator is used to dereference a ref cell. Consider using 'not expr' here."

<note />

</trans-unit>

<trans-unitid="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<targetstate="translated">Všechny větve výrazu porovnání vzorů musí mít stejný typ. Očekávalo se, že tento výraz bude mít typ {0}, ale tady je typu {1}.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<targetstate="needs-review-translation">Všechny větve výrazu porovnání vzorů musí mít stejný typ. Očekávalo se, že tento výraz bude mít typ {0}, ale tady je typu {1}.</target>

<note />

</trans-unit>

<trans-unitid="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unitid="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<targetstate="translated">Alle Branches eines Musterabgleichsausdrucks müssen den gleichen Typ aufweisen. Es wurde erwartet, dass dieser Ausdruck den Typ "{0}" aufweist, hier liegt aber der Typ "{1}" vor.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<targetstate="needs-review-translation">Alle Branches eines Musterabgleichsausdrucks müssen den gleichen Typ aufweisen. Es wurde erwartet, dass dieser Ausdruck den Typ "{0}" aufweist, hier liegt aber der Typ "{1}" vor.</target>

<note />

</trans-unit>

<trans-unitid="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unitid="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<targetstate="new">All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<targetstate="new">All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</target>

<note />

</trans-unit>

<trans-unitid="patternMatchGuardIsNotBool">

</trans-unit>

</body>

</file>

</xliff>

</xliff>

<note />

</trans-unit>

<trans-unitid="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<targetstate="translated">Todas las ramas de una expresión de coincidencia de patrones deben tener el mismo tipo. Se esperaba que esta expresión tuviera el tipo "{0}", pero aquí tiene el tipo "{1}".</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<targetstate="needs-review-translation">Todas las ramas de una expresión de coincidencia de patrones deben tener el mismo tipo. Se esperaba que esta expresión tuviera el tipo "{0}", pero aquí tiene el tipo "{1}".</target>

<note />

</trans-unit>

<trans-unitid="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unitid="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<targetstate="translated">Toutes les branches d'une expression comportant des critères spéciaux doivent avoir le même type. Cette expression était censée avoir le type '{0}', mais elle a ici le type '{1}'.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<targetstate="needs-review-translation">Toutes les branches d'une expression comportant des critères spéciaux doivent avoir le même type. Cette expression était censée avoir le type '{0}', mais elle a ici le type '{1}'.</target>

<note />

</trans-unit>

<trans-unitid="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unit id="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<target state="translated">Il tipo di tutti i rami di un'espressione di criteri di ricerca deve essere lo stesso. Il tipo previsto di questa espressione è '{0}', ma quello effettivo è '{1}'.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<target state="needs-review-translation">Il tipo di tutti i rami di un'espressione di criteri di ricerca deve essere lo stesso. Il tipo previsto di questa espressione è '{0}', ma quello effettivo è '{1}'.</target>

<note />

</trans-unit>

<trans-unit id="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unit id="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<target state="translated">パターン マッチ式のすべてのブランチは同じ型である必要があります。この式に必要な型は '{0}' ですが、ここでは型 '{1}' になっています。</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<target state="needs-review-translation">パターン マッチ式のすべてのブランチは同じ型である必要があります。この式に必要な型は '{0}' ですが、ここでは型 '{1}' になっています。</target>

<note />

</trans-unit>

<trans-unit id="patternMatchGuardIsNotBool">

<note />

</trans-unit>

<trans-unit id="followingPatternMatchClauseHasWrongType">

<source>All branches of a pattern match expression musthavethe same type.This expression was expected to havetype '{0}', buthere has type '{1}'.</source>

<target state="translated">패턴 일치 식의 모든 분기는 동일한 형식이어야 합니다. 이 식에는 '{0}' 형식이 필요하지만 여기에서는 '{1}' 형식이 지정되었습니다.</target>

<source>All branches of a pattern match expression mustreturn values ofthe same type.The first branch returned a value oftype '{0}', butthis branch returned a value of type '{1}'.</source>

<target state="needs-review-translation">패턴 일치 식의 모든 분기는 동일한 형식이어야 합니다. 이 식에는 '{0}' 형식이 필요하지만 여기에서는 '{1}' 형식이 지정되었습니다.</target>

<note />

</trans-unit>

<trans-unit id="patternMatchGuardIsNotBool">