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| 0019 |[Remove Nth Node From End of List](src/main/cpp/g0001_0100/s0019_remove_nth_node_from_end_of_list/Solution.cpp)| Medium | Top_100_Liked_Questions, Top_Interview_Questions, Two_Pointers, Linked_List, Big_O_Time_O(L)_Space_O(L) | 0 | 100.00
| 0019 |[Remove Nth Node From End of List](src/main/cpp/g0001_0100/s0019_remove_nth_node_from_end_of_list/Solution.cpp)| Medium | Top_100_Liked_Questions, Top_Interview_Questions, Two_Pointers, Linked_List, Big_O_Time_O(L)_Space_O(L) | 0 | 100.00
The string`"PAYPALISHIRING"` is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
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P A H N A P L S I I G Y I R
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And then read line by line:`"PAHNAPLSIIGYIR"`
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Write the code that will take a string and make this conversion given a number of rows:
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string convert(string s, int numRows);
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**Example 1:**
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**Input:** s = "PAYPALISHIRING", numRows = 3
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**Output:** "PAHNAPLSIIGYIR"
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**Example 2:**
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**Input:** s = "PAYPALISHIRING", numRows = 4
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**Output:** "PINALSIGYAHRPI"
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**Explanation:** P I N A L S I G Y A H R P I
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**Example 3:**
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**Input:** s = "A", numRows = 1
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**Output:** "A"
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**Constraints:**
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*`1 <= s.length <= 1000`
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*`s` consists of English letters (lower-case and upper-case),`','` and`'.'`.
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*`1 <= numRows <= 1000`
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To solve the Zigzag Conversion problem in Java using a`Solution` class, we'll follow these steps:
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1. Define a`Solution` class with a method named`convert`.
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2. Create an array of strings to represent each row of the zigzag pattern.
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3. Initialize variables to keep track of the current row (`row`) and the direction of traversal (`down`).
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4. Iterate through each character in the input string`s`.
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- Append the current character to the string representing the current row.
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- If we reach the first or last row, change the direction of traversal accordingly.
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- Update the current row based on the direction of traversal.
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5. Concatenate the strings representing each row to form the final zigzag conversion.
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6. Return the concatenated string.
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7. Handle edge cases where the number of rows is 1 or the input string is empty.
Given a signed 32-bit integer`x`, return`x`_with its digits reversed_. If reversing`x` causes the value to go outside the signed 32-bit integer range <code>[-2<sup>31</sup>, 2<sup>31</sup> - 1]</code>, then return`0`.
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**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).**
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**Example 1:**
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**Input:** x = 123
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**Output:** 321
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**Example 2:**
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**Input:** x = -123
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**Output:** -321
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**Example 3:**
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**Input:** x = 120
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**Output:** 21
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**Example 4:**
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**Input:** x = 0
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**Output:** 0
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**Constraints:**
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* <code>-2<sup>31</sup> <= x <= 2<sup>31</sup> - 1</code>
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To solve the Reverse Integer problem in Java using a`Solution` class, we'll follow these steps:
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1. Define a`Solution` class with a method named`reverse`.
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2. Initialize variables to keep track of the reversed integer (`rev`), the sign of the input integer (`sign`), and the absolute value of the input integer (`x`).
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3. Iterate through each digit of the input integer`x`:
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- Extract the least significant digit using the modulo operator.
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- Update the reversed integer`rev` by multiplying it by 10 and adding the extracted digit.
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- Update`x` by removing the least significant digit using integer division.
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4. Check if the reversed integer`rev` overflows the signed 32-bit integer range. If so, return 0.
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5. Return the reversed integer`rev` with the appropriate sign.