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83. 删除排序链表中的重复元素 #63

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@Geekhyt

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@Geekhyt

原题链接

1.将 curr 指针指向链表头节点
2.遍历链表,注意边界条件
3.如果当前节点与它后面的节点值相等,则删除它后面与它重复的节点
4.不重复则继续遍历,最后返回头节点

constdeleteDuplicates=function(head){letcurr=headwhile(curr!==null&&curr.next!==null){if(curr.val===curr.next.val){curr.next=curr.next.next}else{curr=curr.next}}returnhead}
  • 时间复杂度: O(n)
  • 空间复杂度: O(1)

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