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Commit32750e1

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add 1270
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‎README.md

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@@ -885,6 +885,7 @@ _If you like this project, please leave me a star._ ★
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|1308|[Running Total for Different Genders](https://leetcode.com/problems/running-total-for-different-genders/)|[Solution](../master/database/_1308.sql)|| Medium|
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|1294|[Weather Type in Each Country](https://leetcode.com/problems/weather-type-in-each-country/)|[Solution](../master/database/_1294.sql)|| Easy|
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|1280|[Students and Examinations](https://leetcode.com/problems/students-and-examinations/)|[Solution](../master/database/_1280.sql)|[:tv:](https://www.youtube.com/watch?v=ThbkV4Fs7iE)| Easy|
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|1270|[All People Report to the Given Manager](https://leetcode.com/problems/all-people-report-to-the-given-manager/)|[Solution](../master/database/_1270.sql)|| Medium|
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|1251|[Average Selling Price](https://leetcode.com/problems/average-selling-price/)|[Solution](../master/database/_1251.sql)|| Easy|
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|1241|[Number of Comments per Post](https://leetcode.com/problems/number-of-comments-per-post/)|[Solution](../master/database/_1241.sql)|| Easy|
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|1179|[Reformat Department Table](https://leetcode.com/problems/reformat-department-table/)|[Solution](../master/database/_1179.sql)|| Easy|

‎database/_1270.sql

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--1270. All People Report to the Given Manager
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--
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--Table: Employees
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--
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--+---------------+---------+
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--| Column Name | Type |
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--+---------------+---------+
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--| employee_id | int |
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--| employee_name | varchar |
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--| manager_id | int |
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--+---------------+---------+
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--employee_id is the primary key for this table.
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--Each row of this table indicates that the employee with ID employee_id and name employee_name reports his work to his/her direct manager with manager_id
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--The head of the company is the employee with employee_id = 1.
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--
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--
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--Write an SQL query to find employee_id of all employees that directly or indirectly report their work to the head of the company.
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--
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--The indirect relation between managers will not exceed 3 managers as the company is small.
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--
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--Return result table in any order without duplicates.
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--
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--The query result format is in the following example:
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--
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--Employees table:
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--+-------------+---------------+------------+
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--| employee_id | employee_name | manager_id |
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--+-------------+---------------+------------+
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--| 1 | Boss | 1 |
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--| 3 | Alice | 3 |
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--| 2 | Bob | 1 |
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--| 4 | Daniel | 2 |
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--| 7 | Luis | 4 |
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--| 8 | Jhon | 3 |
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--| 9 | Angela | 8 |
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--| 77 | Robert | 1 |
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--+-------------+---------------+------------+
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--
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--Result table:
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--+-------------+
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--| employee_id |
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--+-------------+
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--| 2 |
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--| 77 |
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--| 4 |
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--| 7 |
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--+-------------+
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--
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--The head of the company is the employee with employee_id 1.
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--The employees with employee_id 2 and 77 report their work directly to the head of the company.
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--The employee with employee_id 4 report his work indirectly to the head of the company 4 --> 2 --> 1.
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--The employee with employee_id 7 report his work indirectly to the head of the company 7 --> 4 --> 2 --> 1.
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--The employees with employee_id 3, 8 and 9 don't report their work to head of company directly or indirectly.
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--# Write your MySQL query statement below
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selecte3.employee_idfrom Employees e1, Employees e2, Employees e3
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wheree1.manager_id=1ande2.manager_id=e1.employee_idande3.manager_id=e2.employee_idande3.employee_id!=1

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