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Update 数组旋转问题.c

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`1`		`-#`
	`1`	`+//下面程序的功能是将一个 4×4 的数组进行逆时针旋转 90 度后输出，要求原始数组的数据随机输入，新数组以 4 行 4 列的方式输出。`
	`2`	`+`
	`3`	`+//主要涉及知识点：二维数组的输入及输出、循环嵌套与二维数组的结合、输出的格式控制。`
	`4`	`+`
	`5`	`+`
	`6`	`+#include<stdio.h>`
	`7`	`+intmain(){`
	`8`	`+inta[4][4],b[4][4],i,j;/a 存放原始数组数据，b 存放旋转后数组数据/`
	`9`	`+printf("input 16 numbers: ");`
	`10`	`+/输入一组数据存放到数组 a 中，然后旋转存放到 b 数组中/`
	`11`	`+for(i=0;i<4;i++){`
	`12`	`+for(j=0;j<4;j++){`
	`13`	`+scanf("%d",&a[i][j]);`
	`14`	`+printf("%6d",a[i][j]);`
	`15`	`+b[3-j][i]=a[i][j];`
	`16`	`+ }`
	`17`	`+printf("\n");`
	`18`	`+ }`
	`19`	`+printf("array b:\n");`
	`20`	`+for(i=0;i<4;i++){`
	`21`	`+for(j=0;j<4;j++)`
	`22`	`+printf("%6d",b[i][j]);`
	`23`	`+printf("\n");`
	`24`	`+ }`
	`25`	`+return0;`
	`26`	`+}`
	`27`	`+`
	`28`	`+//运行结果：`
	`29`	`+//input 16 numbers: 1 34 6 4 56 2 5 6 9 12 23 23 46 77 12 34`
	`30`	`+// 1 34 6 4`
	`31`	`+// 56 2 5 6`
	`32`	`+// 9 12 23 23`
	`33`	`+// 46 77 12 34`
	`34`	`+//array b:`
	`35`	`+// 4 6 23 34`
	`36`	`+// 6 5 23 12`
	`37`	`+// 34 2 12 77`
	`38`	`+// 1 56 9 46`

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