In this example we shall show you how to parse aURL. Class URL represents a Uniform Resource Locator, a pointer to a “resource” on the World Wide Web. A resource can be something as simple as a file or a directory, or it can be a reference to a more complicated object, such as a query to a database or to a search engine. To parse a URL one should perform the following steps:

• Create aURL object from the String representation. 
• UsegetProtocol() API method to get the protocol name of this URL, that is HTTP protocol.
• UsegetHost() API method to get the host name of this URL, if applicable.
• UsegetPort() API method to get the port number of this URL. 
• UsegetPath() API method to get the path part of this URL,

as described in the code snippet below.

package com.javacodegeeks.snippets.core;import java.net.MalformedURLException;import java.net.URL;public class ParseURLExample {public static void main(String[] args) {// Create a URLtry {URL url = new URL("http://www.javacodegeeks.com:80/");String protocol = url.getProtocol();    String host = url.getHost();    int port = url.getPort();    String path = url.getPath();        System.out.println("URL created: " + url);    System.out.println("protocol: " + protocol);    System.out.println("host: " + host);    System.out.println("port: " + port);    System.out.println("path: " + path);    }catch (MalformedURLException e) {System.out.println("Malformed URL: " + e.getMessage());}}}

Output:

URL created: http://www.javacodegeeks.com:80/protocol: httphost: www.javacodegeeks.comport: 80path: /

  
This was an example of how to parse a URL in Java.

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