hibernate

Persist object with Hibernate

Photo of Byron KiourtzoglouByron KiourtzoglouNovember 11th, 2012Last Updated: September 25th, 2013
0 238 2 minutes read

This is an example of how to persist an object with Hibernate. To persist an object with Hibernate  we have set the example below:

  • InPersistOjectWithHibernate we use the Hibernate API to make the interface with the database.
  • We create a newConfiguration, that allows the application to specify properties and mapping documents to be used when creating aSessionFactory. Usually an application will create a singleConfiguration, build a single instance ofSessionFactory and then instantiate Sessions in threads servicing client requests.
  • Usingconfigure() API method we use the mappings and properties specified in an application resource namedhibernate.cfg.xml. Then, withbuildSessionFactory() we instantiate a newSessionFactory, using the properties and mappings in this configuration. TheSessionFactory will be immutable, so changes made to the Configuration after building theSessionFactory will not affect it. 
  • Use thegetCurrentSession() API method to obtain the current session.
  • Use thebeginTransaction() API method to begin a unit of work and return the associated Transaction object. If a new underlying transaction is required, begin the transaction. Otherwise continue the new work in the context of the existing underlying transaction.
  • Create a new object, here a newEmployee object and usesave(Object object) API method of Session to persist the given transient instance to the database.
  • UsegetTransaction() API method of Session andcommit() API method of Transaction to commit the Transaction.

In the code snippets that follow, you can see  thePersistOjectWithHibernate Class that applies all above steps. You can also take a look at thehibernate.cfg.xml file, that holds all configuration for Hibernate, such as JDBC connection settings, andemployee.hbm.xml file that holds the mapping configuration between theEmployee object and theEmployee table. 

package com.javacodegeeks.snippets.enterprise;import java.util.Date;import org.hibernate.HibernateException;import org.hibernate.Session;import org.hibernate.SessionFactory;import org.hibernate.cfg.Configuration;public class PersistOjectWithHibernate {private static SessionFactory sessionFactory;public static void main(String[] args) {sessionFactory = new Configuration().configure().buildSessionFactory();Session session = sessionFactory.getCurrentSession();Employee employee = new Employee();employee.setName("Jack");employee.setSurname("Thomson");employee.setTitle("QA Engineer");employee.setCreated(new Date());try {session.beginTransaction();session.save(employee);session.getTransaction().commit();}catch (HibernateException e) {e.printStackTrace();session.getTransaction().rollback();}}}

hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?><!DOCTYPE hibernate-configuration PUBLIC  "-//Hibernate/Hibernate Configuration DTD 3.0//EN"  "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">  <hibernate-configuration>    <session-factory>  <!-- JDBC connection settings -->  <property name="connection.driver_class">com.mysql.jdbc.Driver</property>  <property name="connection.url">jdbc:mysql://localhost/companydb</property>  <property name="connection.username">jcg</property>  <property name="connection.password">jcg</property>    <!-- JDBC connection pool, use Hibernate internal connection pool -->  <property name="connection.pool_size">5</property>  <!-- Defines the SQL dialect used in Hiberante's application -->  <property name="dialect">org.hibernate.dialect.MySQLDialect</property>  <!-- Enable Hibernate's automatic session context management -->  <property name="current_session_context_class">thread</property>  <!-- Disable the second-level cache  -->  <property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>  <!-- Display and format all executed SQL to stdout -->  <property name="show_sql">true</property>  <property name="format_sql">true</property>  <!-- Drop and re-create the database schema on startup -->  <property name="hbm2ddl.auto">update</property>    <!-- Mapping to hibernate mapping files -->  <mapping resource="Employee.hbm.xml" />      </session-factory>    </hibernate-configuration>

Employee.hbm.xml

<?xml version="1.0"?><!DOCTYPE hibernate-mapping PUBLIC  "-//Hibernate/Hibernate Mapping DTD 3.0//EN"  "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">  <hibernate-mapping>    <class name="com.javacodegeeks.snippets.enterprise.Employee" table="employee">  <id name="id" column="id"><generator/>  </id>  <property name="name" not-null="true" length="50" />  <property name="surname" not-null="true" length="50" />  <property name="title" length="50" />  <property name="created" type="timestamp" />    </class>    </hibernate-mapping>
CREATE TABLE `companydb`.`employee` (  `id` INTEGER UNSIGNED NOT NULL AUTO_INCREMENT,  `name` VARCHAR(45) NOT NULL,  `surname` VARCHAR(45) NOT NULL,  `title` VARCHAR(45) NOT NULL,  `created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,  PRIMARY KEY (`id`));

Output:

Hibernate:     insert     into  employee  (name, surname, title, created)     values  (?, ?, ?, ?)

 
This was an example of how to persist an object with Hibernate.

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Photo of Byron KiourtzoglouByron KiourtzoglouNovember 11th, 2012Last Updated: September 25th, 2013
0 238 2 minutes read
Photo of Byron Kiourtzoglou

Byron Kiourtzoglou

Byron is a master software engineer working in the IT and Telecom domains. He is an applications developer in a wide variety of applications/services. He is currently acting as the team leader and technical architect for a proprietary service creation and integration platform for both the IT and Telecom industries in addition to a in-house big data real-time analytics solution. He is always fascinated by SOA, middleware services and mobile development. Byron is co-founder and Executive Editor atJava Code Geeks.

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