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An extensive literature list is available atTalk:Two envelopes problem/LiteratureParadoctor (talk)04:10, 8 October 2020 (UTC)[reply]
If the amount of money is odd, it's better to switch. Since it can't be the X2 enveloppe. If it's even, switching is slightly riskier since maybe one of the envelopes is odd amount of money and you want to avoid it...— Precedingunsigned comment added by70.48.133.1 (talk)11:00, 6 November 2017 (UTC)[reply]
My manuscript on TEP is now posted on arXiv (will appear on Tuesday) and submitted to a journal. Here is a sneak preview.https://www.math.leidenuniv.nl/~gill/tep.pdfRichard Gill (talk)10:08, 7 March 2020 (UTC)[reply]
A correspondent tells me that the following paper is not referenced and seems to them to be the definitive solution:The Two-Envelope Paradox Resolved.Author(s): Timothy J. McGrew, David Shier and Harry S. Silverstein.Source: Analysis , Jan., 1997, Vol. 57, No. 1 (Jan., 1997), pp. 28-33Published by: Oxford University Press on behalf of The Analysis Committee.Stable URL:http://www.jstor.com/stable/3328431Richard Gill (talk)07:50, 21 July 2020 (UTC)[reply]
I found an interesting list of inconsistencies of the articlehereiNic (talk)02:00, 25 November 2020 (UTC)[reply]
Although "the person stands to gain twice as much money if they switch, while the only risk is halving what they currently have", what this omits to mention is that they stand to double only the SMALL amount, but risk losing half the LARGE amount, so in fact the gains and losses even out, and the "paradox" evaporates. I think it would be useful to mention this up front, for the benefit of readers who maybe can't cope with the more mathematical explanations.2A00:23C8:7B0C:9A01:87F:AA06:BD33:A284 (talk)13:30, 15 April 2024 (UTC)[reply]
maybe put something about the monty hall problem in there? it's very similar.174.176.97.132 (talk)20:52, 22 August 2025 (UTC)[reply]