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Djpark0115 (talk)07:00, 21 May 2009 (UTC)Q^-1 is necessary in the encoder/ecoder diagram of option2 ??[reply]

Yes, good catch; it's needed in the type 2 encoder as well. Maybe you can alert the editor who made the figure...Dicklyon (talk)17:19, 21 May 2009 (UTC)[reply]

Q^-1 is horribly wrong! Quantization is not invertible. Option 1 is only possible if no quantization is done and the compression algorithm is lossless. The whole article has a lot of errors.— Precedingunsigned comment added by188.155.108.64 (talk •contribs)

You were right to remove the bad figure from option 1. I edited the text to make it correct, I think.Dicklyon (talk)18:07, 8 January 2011 (UTC)[reply]

Please explain the roles of Z^-1, the circuitry.—Precedingunsigned comment added byPiotroxp (talk •contribs)06:51, 19 June 2009 (UTC)[reply]

I noted in the article that it represents a sample delay; it's obscure conventional DSP notation based on theZ transform.Dicklyon (talk)18:16, 8 January 2011 (UTC)[reply]

what does "local model" means in the option 2 section? --190.60.93.218 (talk)18:53, 29 May 2014 (UTC)[reply]

Hello,

the statement "because the entropy of the difference signal is much smaller than that of the original discrete signal" is wrong. The idea of a DPCM is to reduce the variance by building a difference signal. The entropy is not reduced (it is not changed at all by calculating the difference signal). Entropy is only reduced in the quantized signal (obviously).— Precedingunsigned comment added by130.75.31.216 (talk)09:21, 20 August 2018 (UTC)[reply]

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