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Star of David theorem

From Wikipedia, the free encyclopedia
Mathematical result on arithmetic properties of binomial coefficients
TheStar of David theorem (the rows of the Pascal triangle are shown as columns here).

TheStar of David theorem is a mathematical result onarithmetic properties ofbinomial coefficients. It was discovered byHenry W. Gould in 1972.

Statement

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Thegreatest common divisors of the binomial coefficients forming each of the two triangles in theStar of David shape inPascal's triangle are equal:

gcd{(n1k1),(nk+1),(n+1k)}=gcd{(n1k),(nk1),(n+1k+1)}.{\displaystyle {\begin{aligned}&\gcd \left\{{\binom {n-1}{k-1}},{\binom {n}{k+1}},{\binom {n+1}{k}}\right\}\\[8pt]={}&\gcd \left\{{\binom {n-1}{k}},{\binom {n}{k-1}},{\binom {n+1}{k+1}}\right\}.\end{aligned}}}

Examples

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Rows 8, 9, and 10 of Pascal's triangle are

18285670562881
193684126126843691
1104512021025221012045101

Forn=9,k=3 orn=9,k=6, the element 84 (circled bold) is surrounded by, in sequence, the elements 28, 56, 126, 210, 120 and 36 (bold). Taking alternating values, we have gcd(28, 126, 120) = 2 = gcd(56, 210, 36).

The element 36 (circled italics) is surrounded by the sequence 8, 28, 84, 120, 45 and 9 (italics), and taking alternating values we have gcd(8, 84, 45) = 1 = gcd(28, 120, 9).

Generalization

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The above greatest common divisor also equalsgcd((n1k2),(n1k1),(n1k),(n1k+1)).{\displaystyle \gcd \left({n-1 \choose k-2},{n-1 \choose k-1},{n-1 \choose k},{n-1 \choose k+1}\right).}[1] Thus in the above example for the element 84 (in its rightmost appearance), we also have gcd(70, 56, 28, 8) = 2. This result in turn has further generalizations.

Related results

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The two sets of three numbers which the Star of David theorem says have equal greatest common divisors also have equal products.[1] For example, again observing that the element 84 is surrounded by, in sequence, the elements 28, 56, 126, 210, 120, 36, and again taking alternating values, we have 28×126×120 = 26×33×5×72 = 56×210×36. This result can be confirmed by writing out each binomial coefficient in factorial form, using

(ab)=a!(ab)!b!.{\displaystyle {a \choose b}={\frac {a!}{(a-b)!b!}}.}

See also

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References

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  1. ^abWeisstein, Eric W."Star of David Theorem".mathworld.wolfram.com. Retrieved2024-12-31.

External links

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Retrieved from "https://en.wikipedia.org/w/index.php?title=Star_of_David_theorem&oldid=1290377843"
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