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Inmathematical logic, and particularly in its subfieldmodel theory, asaturated modelM is one that realizes as manycomplete types as may be "reasonably expected" given its size. For example, anultrapower model of thehyperreals is-saturated, meaning that every descending nested sequence ofinternal sets has a nonempty intersection.[1]
Letκ be afinite orinfinitecardinal number andM a model in somefirst-order language. ThenM is calledκ-saturated if for all subsetsA ⊆M ofcardinality strictly less thanκ, the modelM realizes allcomplete types overA. The modelM is calledsaturated if it is |M|-saturated where |M| denotes the cardinality ofM. That is, it realizes all complete types over sets of parameters of size less than |M|. According to some authors, a modelM is calledcountably saturated if it is-saturated; that is, it realizes all complete types over countable sets of parameters.[2] According to others, it is countably saturated if it is countable and saturated.[3]
The seemingly more intuitive notion—that all complete types of the language are realized—turns out to be too weak (and is appropriately namedweak saturation, which is the same as 1-saturation). The difference lies in the fact that many structures contain elements that are not definable (for example, anytranscendental element ofR is, by definition of the word, not definable in the language offields). However, they still form a part of the structure, so we need types to describe relationships with them. Thus we allow sets of parameters from the structure in our definition of types. This argument allows us to discuss specific features of the model that we may otherwise miss—for example, a bound on aspecific increasing sequencecn can be expressed as realizing the type{x ≥cn :n ∈ ω}, which uses countably many parameters. If the sequence is not definable, this fact about the structure cannot be described using the base language, so a weakly saturated structure may not bound the sequence, while an ℵ1-saturated structure will.
The reason we only require parameter sets that are strictly smaller than the model is trivial: without this restriction, no infinite model is saturated. Consider a modelM, and the type{x ≠m :m ∈M}. Each finite subset of this type is realized in the (infinite) modelM, so by compactness it is consistent withM, but is trivially not realized. Any definition that is universally unsatisfied is useless; hence the restriction.
Saturated models exist for certain theories and cardinalities:
Both the theory ofQ and the theory of the countable random graph can be shown to beω-categorical through theback-and-forth method. This can be generalized as follows: the unique model of cardinalityκ of a countableκ-categorical theory is saturated.
However, the statement that every model has a saturatedelementary extension is not provable inZFC. In fact, this statement is equivalent to[citation needed] the existence of a proper class of cardinalsκ such thatκ<κ = κ. The latter identity is equivalent toκ =λ+ = 2λ for someλ, orκ isstrongly inaccessible.
The notion of saturated model is dual to the notion ofprime model in the following way: letT be a countable theory in a first-order language (that is, a set of mutually consistent sentences in that language) and letP be a prime model ofT. ThenP admits anelementary embedding into any other model ofT. The equivalent notion for saturated models is that any "reasonably small" model ofT is elementarily embedded in a saturated model, where "reasonably small" means cardinality no larger than that of the model in which it is to be embedded. Any saturated model is alsohomogeneous. However, while for countable theories there is a unique prime model, saturated models are necessarily specific to a particular cardinality. Given certain set-theoretic assumptions, saturated models (albeit of very large cardinality) exist for arbitrary theories. Forλ-stable theories, saturated models of cardinalityλ exist.