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Rate equation

From Wikipedia, the free encyclopedia
Relation between chemical reaction rate and concentrations of the reactants

Inchemistry, therate equation (also known as therate law orempirical differential rate equation) is anempiricaldifferentialmathematical expression for thereaction rate of a given reaction in terms of concentrations of chemical species and constant parameters (normally rate coefficients and partial orders of reaction) only.[1] For many reactions, the initial rate is given by a power law such as

v0=k[A]x[B]y{\displaystyle v_{0}\;=\;k[\mathrm {A} ]^{x}[\mathrm {B} ]^{y}}

where[A]{\displaystyle [\mathrm {A} ]} and[B]{\displaystyle [\mathrm {B} ]} are themolar concentrations of the speciesA{\displaystyle \mathrm {A} } andB,{\displaystyle \mathrm {B} ,} usually inmoles perliter (molarity,M{\displaystyle M}). The exponentsx{\displaystyle x} andy{\displaystyle y} are the partialorders of reaction forA{\displaystyle \mathrm {A} } andB{\displaystyle \mathrm {B} }, respectively, and theoverall reaction order is the sum of the exponents. These are often positive integers, but they may also be zero, fractional, or negative. Theorder of reaction is a number which quantifies the degree to which the rate of a chemical reaction depends on concentrations of the reactants.[2] In other words, the order of reaction is the exponent to which the concentration of a particular reactant is raised.[2] The constantk{\displaystyle k} is thereaction rate constant orrate coefficient and at very few placesvelocity constant orspecific rate of reaction. Its value may depend on conditions such as temperature, ionic strength, surface area of anadsorbent, or lightirradiation. If the reaction goes to completion, the rate equation for thereaction ratev=k[A]x[B]y{\displaystyle v\;=\;k[{\ce {A}}]^{x}[{\ce {B}}]^{y}} applies throughout the course of the reaction.

Elementary (single-step) reactions andreaction steps have reaction orders equal to thestoichiometric coefficients for each reactant. The overall reaction order, i.e. the sum of stoichiometric coefficients of reactants, is always equal to themolecularity of the elementary reaction. However,complex (multi-step) reactions may or may not have reaction orders equal to their stoichiometric coefficients. This implies that the order and the rate equation of a given reaction cannot be reliably deduced from the stoichiometry and must be determined experimentally, since an unknownreaction mechanism could be either elementary or complex. When the experimental rate equation has been determined, it is often of use for deduction of thereaction mechanism.

In highly dilute solutions, such as at concentrations below the micromolar level, molecular collisions are primarily governed bydiffusion. Under these conditions, the apparent reaction order deviates from the stoichiometric expectation because reactant molecules require additional time to traverse longer distances before encountering one another. This behavior can be described byFick's laws of diffusion and is consistent with fractal reaction kinetics, which yield fractional reaction orders.

The rate equation of a reaction with an assumed multi-step mechanism can often be derived theoretically usingquasi-steady state assumptions from the underlying elementary reactions, and compared with the experimental rate equation as a test of the assumed mechanism. The equation may involve afractional order, and may depend on the concentration of anintermediate species.

A reaction can also have anundefined reaction order with respect to a reactant if the rate is not simply proportional to some power of the concentration of that reactant; for example, one cannot talk about reaction order in the rate equation for a bimolecular reaction betweenadsorbed molecules:

v0=kK1K2CACB(1+K1CA+K2CB)2.{\displaystyle v_{0}=k{\frac {K_{1}K_{2}C_{A}C_{B}}{(1+K_{1}C_{A}+K_{2}C_{B})^{2}}}.}

Definition

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Main article:Reaction rate

Consider a typicalchemical reaction in which tworeactants A and B combine to form aproduct C:

A+2B3C.{\displaystyle {\ce {{A}+ {2B}-> {3C}}}.}

This can also be written

A2B+3C=0.{\displaystyle -\mathrm {A} -2\mathrm {B} +3\mathrm {C} =0.}

The prefactors −1, −2 and 3 (with negative signs for reactants because they are consumed) are known asstoichiometric coefficients. One molecule of A combines with two of B to form 3 of C, so if we use the symbol [X] for themolar concentration of chemical X,[3]

d[A]dt=12d[B]dt=13d[C]dt.{\displaystyle -{\frac {d[\mathrm {A} ]}{dt}}=-{\frac {1}{2}}{\frac {d[\mathrm {B} ]}{dt}}={\frac {1}{3}}{\frac {d[\mathrm {C} ]}{dt}}.}

If the reaction takes place in aclosed system at constant temperature and volume, without a build-up ofreaction intermediates, thereaction ratev{\displaystyle v} is defined as

v=1νid[Xi]dt,{\displaystyle v={\frac {1}{\nu _{i}}}{\frac {d[\mathrm {X} _{i}]}{dt}},}

whereνi is the stoichiometric coefficient for chemical Xi, with a negative sign for a reactant.[4]

The initial reaction ratev0=vt=0{\displaystyle v_{0}=v_{t=0}} has some functional dependence on the concentrations of the reactants,

v0=f([A],[B],),{\displaystyle v_{0}=f\left([\mathrm {A} ],[\mathrm {B} ],\ldots \right),}

and this dependence is known as therate equation orrate law.[5] This law generally cannot be deduced from the chemical equation and must be determined by experiment.[6]

Power laws

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A common form for the rate equation is a power law:[6]

v0=k[A]x[B]y{\displaystyle v_{0}=k[{\ce {A}}]^{x}[{\ce {B}}]^{y}\cdots }

The constantk{\displaystyle k} is called therate constant. The exponents, which can be fractional,[6] are calledpartial orders of reaction and their sum is the overall order of reaction.[7]

In a dilute solution, anelementary reaction (one having a single step with a singletransition state) is empirically found to obey thelaw of mass action. This predicts that the rate depends only on the concentrations of the reactants, raised to the powers of their stoichiometric coefficients.[8]

Thedifferential rate equation for an elementary reaction usingmathematical product notation is:

ddt[Reactants]=ki[Reactantsi]{\displaystyle -{d \over dt}[{\text{Reactants}}]=k\prod _{i}[{\text{Reactants}}_{i}]}

Where:

Determination of reaction order

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Method of initial rates

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Thenatural logarithm of the power-law rate equation is

lnv0=lnk+xln[A]+yln[B]+{\displaystyle \ln v_{0}=\ln k+x\ln[{\ce {A}}]+y\ln[{\ce {B}}]+\cdots }

This can be used to estimate the order of reaction of each reactant. For example, the initial rate can be measured in a series of experiments at different initial concentrations of reactantA{\displaystyle {\rm {A}}} with all other concentrations[B],[C],{\displaystyle [{\rm {B],[{\rm {C],\dots }}}}} kept constant, so that

lnv0=xln[A]+constant.{\displaystyle \ln v_{0}=x\ln[{\ce {A}}]+{\textrm {constant}}.}

Theslope of a graph oflnv{\displaystyle \ln v} as a function ofln[A]{\displaystyle \ln[{\ce {A}}]} then corresponds to the orderx{\displaystyle x} with respect to reactantA{\displaystyle {\rm {A}}}.[9][10]

However, this method is not always reliable because

  1. measurement of the initial rate requires accurate determination of small changes in concentration in short times (compared to the reactionhalf-life) and is sensitive to errors, and
  2. the rate equation will not be completely determined if the rate also depends on substances not present at the beginning of the reaction, such as intermediates or products.

Integral method

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The tentative rate equation determined by the method of initial rates is therefore normally verified by comparing the concentrations measured over a longer time (several half-lives) with the integrated form of the rate equation; this assumes that the reaction goes to completion.

For example, the integrated rate law for a first-order reaction is

ln[A]=kt+ln[A]0,{\displaystyle \ln {[{\ce {A}}]}=-kt+\ln {[{\ce {A}}]_{0}},}

where[A]{\displaystyle [{\rm {A]}}} is the concentration at timet{\displaystyle t} and[A]0{\displaystyle [{\rm {A]_{0}}}} is the initial concentration at zero time. The first-order rate law is confirmed ifln[A]{\displaystyle \ln {[{\ce {A}}]}} is in fact a linear function of time. In this case therate constantk{\displaystyle k} is equal to the slope with sign reversed.[11][12]

Method of flooding

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The partial order with respect to a given reactant can be evaluated by the method of flooding (or of isolation) ofOstwald. In this method, the concentration of one reactant is measured with all other reactants in large excess so that their concentration remains essentially constant. For a reactiona·A +b·B →c·C with rate lawv0=k[A]x[B]y,{\displaystyle v_{0}=k\cdot [{\rm {A}}]^{x}\cdot [{\rm {B}}]^{y},} the partial orderx{\displaystyle x} with respect toA{\displaystyle {\rm {A}}} is determined using a large excess ofB{\displaystyle {\rm {B}}}. In this case

v0=k[A]x{\displaystyle v_{0}=k'\cdot [{\rm {A}}]^{x}} withk=k[B]y,{\displaystyle k'=k\cdot [{\rm {B}}]^{y},}

andx{\displaystyle x} may be determined by the integral method. The ordery{\displaystyle y} with respect toB{\displaystyle {\rm {B}}} under the same conditions (withB{\displaystyle {\rm {B}}} in excess) is determined by a series of similar experiments with a range of initial concentration[B]0{\displaystyle [{\rm {B]_{0}}}} so that the variation ofk{\displaystyle k'} can be measured.[13]

Zero order

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For zero-order reactions, the reaction rate is independent of the concentration of a reactant, so that changing its concentration has no effect on the rate of the reaction. Thus, the concentration changes linearly with time. The rate law for zero order reaction is

d[A]dt=k[A]0=k,{\displaystyle -{d[A] \over dt}=k[A]^{0}=k,}

The unit ofk ismol dm−3 s−1.[14] This may occur when there is a bottleneck which limits the number of reactant molecules that can react at the same time, for example if the reaction requires contact with anenzyme or acatalytic surface.[15]

Many enzyme-catalyzed reactions are zero order, provided that the reactant concentration is much greater than the enzyme concentration which controls the rate, so that the enzyme issaturated. For example, the biological oxidation ofethanol toacetaldehyde by the enzymeliver alcohol dehydrogenase (LADH) is zero order in ethanol.[16]

Similarly, reactions withheterogeneous catalysis can be zero order if the catalytic surface is saturated. For example, the decomposition ofphosphine (PH3) on a hottungsten surface at high pressure is zero order in phosphine, which decomposes at a constant rate.[15]

Inhomogeneous catalysis zero order behavior can come about from reversible inhibition. For example,ring-opening metathesis polymerization usingthird-generation Grubbs catalyst exhibits zero order behavior in catalyst due to the reversibleinhibition that occurs betweenpyridine and the ruthenium center.[17]

First order

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Afirst order reaction depends on the concentration of only one reactant (aunimolecular reaction). Other reactants can be present, but their concentration has no effect on the rate. The rate law for a first order reaction is

d[A]dt=k[A],{\displaystyle -{\frac {d[{\ce {A}}]}{dt}}=k[{\ce {A}}],}

The unit ofk iss−1.[14] Although not affecting the above math, the majority of first order reactions proceed via intermolecular collisions. Such collisions, which contribute the energy to the reactant, are necessarily second order. However according to theLindemann mechanism the reaction consists of two steps: the bimolecular collision which is second order and the reaction of the energized molecule which is unimolecular and first order. The rate of the overall reaction depends on the slowest step, so the overall reaction will be first order when the reaction of the energized reactant is slower than the collision step.

Thehalf-life is independent of the starting concentration and is given byt1/2=ln(2)k{\textstyle t_{1/2}={\frac {\ln {(2)}}{k}}}. Themean lifetime isτ = 1/k.[18]

Examples of such reactions are:

In organic chemistry, the class ofSN1 (nucleophilic substitution unimolecular) reactions consists of first-order reactions. For example, in the reaction ofaryldiazonium ions withnucleophiles in aqueous solution,ArN+2 + X → ArX + N2, the rate equation isv0=k[ArN2+],{\displaystyle v_{0}=k[{\ce {ArN2+}}],} where Ar indicates anaryl group.[22]

Second order

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A reaction is said to be second order when the overall order is two. The rate of a second-order reaction may be proportional to one concentration squared,v0=k[A]2,{\displaystyle v_{0}=k[{\ce {A}}]^{2},} or (more commonly) to the product of two concentrations,v0=k[A][B].{\displaystyle v_{0}=k[{\ce {A}}][{\ce {B}}].} As an example of the first type, the reactionNO2 + CO → NO + CO2 is second-order in the reactantNO2 and zero order in the reactant CO. The observed rate is given byv0=k[NO2]2,{\displaystyle v_{0}=k[{\ce {NO2}}]^{2},} and is independent of the concentration of CO.[23]

For the rate proportional to a single concentration squared, the time dependence of the concentration is given by

1[A]=1[A]0+kt.{\displaystyle {\frac {1}{{\ce {[A]}}}}={\frac {1}{{\ce {[A]0}}}}+kt.}

The unit ofk ismol−1 dm3 s−1.[14]

The time dependence for a rate proportional to two unequal concentrations is

[A][B]=[A]0[B]0e([A]0[B]0)kt;{\displaystyle {\frac {{\ce {[A]}}}{{\ce {[B]}}}}={\frac {{\ce {[A]0}}}{{\ce {[B]0}}}}e^{\left({\ce {[A]0}}-{\ce {[B]0}}\right)kt};}

if the concentrations are equal, they satisfy the previous equation.

The second type includes nucleophilicaddition-elimination reactions, such as thealkalinehydrolysis ofethyl acetate:[22]

CH3COOC2H5+OHCH3COO+C2H5OH{\displaystyle {\ce {CH3COOC2H5 + OH- -> CH3COO- + C2H5OH}}}

This reaction is first-order in each reactant and second-order overall:

v0=k[CH3COOC2H5][OH]{\displaystyle v_{0}=k[{\ce {CH3COOC2H5}}][{\ce {OH-}}]}

If the same hydrolysis reaction iscatalyzed byimidazole, the rate equation becomes[22]

v0=k[imidazole][CH3COOC2H5].{\displaystyle v_{0}=k[{\text{imidazole}}][{\ce {CH3COOC2H5}}].}

The rate is first-order in one reactant (ethyl acetate), and also first-order in imidazole, which as a catalyst does not appear in the overall chemical equation.

Another well-known class of second-order reactions are theSN2 (bimolecular nucleophilic substitution) reactions, such as the reaction ofn-butyl bromide withsodium iodide inacetone:

CH3CH2CH2CH2Br+NaICH3CH2CH2CH2I+NaBr{\displaystyle {\ce {CH3CH2CH2CH2Br + NaI -> CH3CH2CH2CH2I + NaBr(v)}}}

This same compound can be made to undergo a bimolecular (E2)elimination reaction, another common type of second-order reaction, if the sodium iodide and acetone are replaced withsodium tert-butoxide as the salt andtert-butanol as the solvent:

CH3CH2CH2CH2Br+NaOtBuCH3CH2CH=CH2+NaBr+HOtBu{\displaystyle {\ce {{CH3CH2CH2CH2Br}+NaO{\mathit {t}}-Bu->{CH3CH2CH=CH2}+{NaBr}+HO{\mathit {t}}-Bu}}}

Pseudo-first order

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If the concentration of a reactant remains constant (because it is acatalyst, or because it is in great excess with respect to the other reactants), its concentration can be included in the rate constant, leading to apseudo–first-order (or occasionally pseudo–second-order) rate equation. For a typical second-order reaction with rate equationv0=k[A][B],{\displaystyle v_{0}=k[{\ce {A}}][{\ce {B}}],} if the concentration of reactant B is constant thenv0=k[A][B]=k[A],{\displaystyle v_{0}=k[{\ce {A}}][{\ce {B}}]=k'[{\ce {A}}],} where the pseudo–first-order rate constantk=k[B].{\displaystyle k'=k[{\ce {B}}].} The second-order rate equation has been reduced to a pseudo–first-order rate equation, which makes the treatment to obtain an integrated rate equation much easier.

One way to obtain a pseudo-first order reaction is to use a large excess of one reactant (say, [B]≫[A]) so that, as the reaction progresses, only a small fraction of the reactant in excess (B) is consumed, and its concentration can be considered to stay constant. For example, the hydrolysis of esters by dilute mineral acids follows pseudo-first order kinetics, where the concentration of water is constant because it is present in large excess:

CH3COOCH3+H2OCH3COOH+CH3OH{\displaystyle {\ce {CH3COOCH3 + H2O -> CH3COOH + CH3OH}}}

The hydrolysis of sucrose (C12H22O11) in acid solution is often cited as a first-order reaction with ratev0=k[C12H22O11].{\displaystyle v_{0}=k[{\ce {C12H22O11}}].} The true rate equation is third-order,v0=k[C12H22O11][H+][H2O];{\displaystyle v_{0}=k[{\ce {C12H22O11}}][{\ce {H+}}][{\ce {H2O}}];} however, the concentrations of both the catalystH+ and the solventH2O are normally constant, so that the reaction is pseudo–first-order.[24]

Summary for reaction orders 0, 1, 2, andn

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Elementary reaction steps with order 3 (calledternary reactions) arerare and unlikely to occur. However, overall reactions composed of several elementary steps can, of course, be of any (including non-integer) order.

ParameterZero orderFirst orderSecond ordernth order (g = 1−n)
Rate Lawd[A]/dt=k{\displaystyle -{d[{\ce {A}}]}/{dt}=k}d[A]/dt=k[A]{\displaystyle -{d[{\ce {A}}]}/{dt}=k[{\ce {A}}]}d[A]/dt=k[A]2{\displaystyle -{d[{\ce {A}}]}/{dt}=k[{\ce {A}}]^{2}}[25]d[A]/dt=k[A]n{\displaystyle -{d[{\ce {A}}]}/{dt}=k[{\ce {A}}]^{n}}
Integrated Rate Law[A]=[A]0kt{\displaystyle {\ce {[A] = [A]0}}-kt}[A]=[A]0ekt{\displaystyle {\ce {[A] = [A]0}}e^{-kt}}1[A]=1[A]0+kt{\displaystyle {\frac {1}{{\ce {[A]}}}}={\frac {1}{{\ce {[A]0}}}}+kt}[25][A]g=[A]0ggkt{\displaystyle [{\ce {A}}]^{g}={{\ce {[A]0}}^{g}}-gkt}

[Except first order]

Units of Rate Constant (k)Ms{\displaystyle {\rm {\frac {M}{s}}}}1s{\displaystyle {\rm {\frac {1}{s}}}}1Ms{\displaystyle {\rm {\frac {1}{M\cdot s}}}}Mgs{\displaystyle {\frac {{\rm {M}}^{g}}{\rm {s}}}}
Linear Plot to determinek[A] vs.tln([A]){\displaystyle {\ce {\ln([A])}}} vs.t1[A]{\displaystyle {\ce {{\frac {1}{[A]}}}}} vs.t[A]g{\displaystyle {\ce {{\rm {[A]}}^{g}}}} vs.t

[Except first order]

Half-lifet12=[A]02k{\displaystyle t_{\frac {1}{2}}={\frac {{\ce {[A]0}}}{2k}}}t12=ln(2)k{\displaystyle t_{\frac {1}{2}}={\frac {\ln(2)}{k}}}t12=1k[A]0{\displaystyle t_{\frac {1}{2}}={\frac {1}{k{\ce {[A]0}}}}}[25]t12=[A]0g(12g)gk{\displaystyle t_{\frac {1}{2}}={\frac {{\ce {[A]0}}^{g}(1-2^{-g})}{gk}}}

[Limit is necessary for first order]

HereM{\displaystyle {\rm {M}}} stands for concentration inmolarity (mol · L−1),t{\displaystyle t} for time, andk{\displaystyle k} for the reaction rate constant. The half-life of a first-order reaction is often expressed ast1/2 = 0.693/k (as ln(2)≈0.693).

Fractional order

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In fractional order reactions, the order is a non-integer, which often indicates achemical chain reaction or other complexreaction mechanism. For example, thepyrolysis ofacetaldehyde (CH3CHO) intomethane andcarbon monoxide proceeds with an order of 1.5 with respect to acetaldehyde:v0=k[CH3CHO]3/2.{\displaystyle v_{0}=k[{\ce {CH3CHO}}]^{3/2}.}[26] The decomposition ofphosgene (COCl2) to carbon monoxide andchlorine has order 1 with respect to phosgene itself and order 0.5 with respect to chlorine:v0=k[COCl2][Cl2]1/2.{\displaystyle v_{0}=k{\ce {[COCl2] [Cl2]}}^{1/2}.}[27]

The order of a chain reaction can be rationalized using thesteady state approximation for the concentration of reactive intermediates such asfree radicals. For the pyrolysis of acetaldehyde, the Rice-Herzfeld mechanism is

Initiation
CH3CHOCH3+CHO{\displaystyle {\ce {CH3CHO -> .CH3 + .CHO}}}
Propagation
CH3+CH3CHOCH3CO+CH4{\displaystyle {\ce {.CH3 + CH3CHO -> CH3CO. + CH4}}}
CH3COCH3+CO{\displaystyle {\ce {CH3CO. -> .CH3 + CO}}}
Termination
2CH3C2H6{\displaystyle {\ce {2 .CH3 -> C2H6}}}

where • denotes a free radical.[26][28] To simplify the theory, the reactions of the*CHO to form a second*CH3 are ignored.

In the steady state, the rates of formation and destruction of methyl radicals are equal, so that

d[CH3]dt=ki[CH3CHO]kt[CH3]2=0,{\displaystyle {\frac {d[{\ce {.CH3}}]}{dt}}=k_{i}[{\ce {CH3CHO}}]-k_{t}[{\ce {.CH3}}]^{2}=0,}

so that the concentration of methyl radical satisfies

[CH3][CH3CHO]12{\displaystyle {\ce {[.CH3]\quad \propto \quad [CH3CHO]^{1/2}.}}}

The reaction rate equals the rate of the propagation steps which form the main reaction productsCH4 and CO:

v0=d[CH4]dt|0=kp[CH3][CH3CHO][CH3CHO]32{\displaystyle v_{0}={\frac {d[{\ce {CH4}}]}{dt}}|_{0}=k_{p}{\ce {[.CH3][CH3CHO]}}\quad \propto \quad {\ce {[CH3CHO]^{3/2}}}}

in agreement with the experimental order of 3/2.[26][28]

In highly diluted solutions, such as at concentrations below the micromolar level, molecular collisions are primarily governed bydiffusion. Under these conditions, the apparent reaction order deviates from the stoichiometric expectation because reactant molecules require additional time to traverse longer distances before encountering one another. This behavior can be described byFick's laws of diffusion and is consistent with fractal reaction kinetics, which yield fractional reaction orders.

Complex laws

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Mixed order

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More complex rate laws have been described as beingmixed order if they approximate to the laws for more than one order at different concentrations of the chemical species involved. For example, a rate law of the formv0=k1[A]+k2[A]2{\displaystyle v_{0}=k_{1}[A]+k_{2}[A]^{2}} represents concurrent first order and second order reactions (or more often concurrent pseudo-first order and second order) reactions, and can be described as mixed first and second order.[29] For sufficiently large values of [A] such a reaction will approximate second order kinetics, but for smaller [A] the kinetics will approximate first order (or pseudo-first order). As the reaction progresses, the reaction can change from second order to first order as reactant is consumed.

Another type of mixed-order rate law has a denominator of two or more terms, often because the identity of therate-determining step depends on the values of the concentrations. An example is the oxidation of analcohol to aketone byhexacyanoferrate (III) ion [Fe(CN)63−] withruthenate (VI) ion (RuO42−) ascatalyst.[30] For this reaction, the rate of disappearance of hexacyanoferrate (III) isv0=[Fe(CN)6]2kα+kβ[Fe(CN)6]2{\displaystyle v_{0}={\frac {{\ce {[Fe(CN)6]^2-}}}{k_{\alpha }+k_{\beta }{\ce {[Fe(CN)6]^2-}}}}}

This is zero-order with respect to hexacyanoferrate (III) at the onset of the reaction (when its concentration is high and the ruthenium catalyst is quickly regenerated), but changes to first-order when its concentration decreases and the regeneration of catalyst becomes rate-determining.

Notable mechanisms with mixed-order rate laws with two-term denominators include:

  • Michaelis–Menten kinetics for enzyme-catalysis: first-order in substrate (second-order overall) at low substrate concentrations, zero order in substrate (first-order overall) at higher substrate concentrations; and
  • theLindemann mechanism for unimolecular reactions: second-order at low pressures, first-order at high pressures.

Negative order

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A reaction rate can have a negative partial order with respect to a substance. For example, the conversion ofozone (O3) tooxygen follows the rate equationv0=k[O3]2[O2]1{\displaystyle v_{0}=k{\ce {[O_3]^2}}{\ce {[O_2]^{-1}}}} in an excess of oxygen. This corresponds to second order in ozone and order (−1) with respect to oxygen.[31]

When a partial order is negative, the overall order is usually considered as undefined. In the above example, for instance, the reaction is not described as first order even though the sum of the partial orders is2+(1)=1{\displaystyle 2+(-1)=1}, because the rate equation is more complex than that of a simple first-order reaction.

Opposed reactions

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A pair of forward and reverse reactions may occur simultaneously with comparable speeds. For example, A and B react into products P and Q and vice versa (a, b, p, andq are thestoichiometric coefficients):

aA+bBpP+qQ{\displaystyle {\ce {{{\mathit {a}}A}+{{\mathit {b}}B}<=>{{\mathit {p}}P}+{{\mathit {q}}Q}}}}

The reaction rate expression for the above reactions (assuming each one is elementary) can be written as:

v=k1[A]a[B]bk1[P]p[Q]q{\displaystyle v=k_{1}[{\ce {A}}]^{a}[{\ce {B}}]^{b}-k_{-1}[{\ce {P}}]^{p}[{\ce {Q}}]^{q}}

where:k1 is the rate coefficient for the reaction that consumes A and B;k−1 is the rate coefficient for the backwards reaction, which consumes P and Q and produces A and B.

The constantsk1 andk−1 are related to the equilibrium coefficient for the reaction (K) by the following relationship (setv=0 in balance):

k1[A]a[B]b=k1[P]p[Q]qK=[P]p[Q]q[A]a[B]b=k1k1{\displaystyle {\begin{aligned}&k_{1}[{\ce {A}}]^{a}[{\ce {B}}]^{b}=k_{-1}[{\ce {P}}]^{p}[{\ce {Q}}]^{q}\\[8pt]&K={\frac {[{\ce {P}}]^{p}[{\ce {Q}}]^{q}}{[{\ce {A}}]^{a}[{\ce {B}}]^{b}}}={\frac {k_{1}}{k_{-1}}}\end{aligned}}}
Concentration of A (A0 = 0.25 mol/L) and B versus time reaching equilibriumk1 = 2 min−1 andk−1 = 1 min−1

Simple example

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In a simple equilibrium between two species:

AP{\displaystyle {\ce {A <=> P}}}

where the reaction starts with an initial concentration of reactant A,[A]0{\displaystyle {\ce {[A]0}}}, and an initial concentration of 0 for product P at timet=0.

Then theequilibrium constantK is expressed as:

K =def k1k1=[P]e[A]e{\displaystyle K\ {\stackrel {\mathrm {def} }{=}}\ {\frac {k_{1}}{k_{-1}}}={\frac {\left[{\ce {P}}\right]_{e}}{\left[{\ce {A}}\right]_{e}}}}

where[A]e{\displaystyle [{\ce {A}}]_{e}} and[P]e{\displaystyle [{\ce {P}}]_{e}} are the concentrations of A and P at equilibrium, respectively.

The concentration of A at timet,[A]t{\displaystyle [{\ce {A}}]_{t}}, is related to the concentration of P at timet,[P]t{\displaystyle [{\ce {P}}]_{t}}, by the equilibrium reaction equation:

[A]t=[A]0[P]t{\displaystyle {\ce {[A]_{\mathit {t}}=[A]0-[P]_{\mathit {t}}}}}

The term[P]0{\displaystyle {\ce {[P]0}}} is not present because, in this simple example, the initial concentration of P is 0.

This applies even when timet is at infinity; i.e., equilibrium has been reached:

[A]e=[A]0[P]e{\displaystyle {\ce {[A]_{\mathit {e}}=[A]0-[P]_{\mathit {e}}}}}

then it follows, by the definition ofK, that

[P]e=k1k1+k1[A]0{\displaystyle [{\ce {P}}]_{e}={\frac {k_{1}}{k_{1}+k_{-1}}}{\ce {[A]0}}}

and, therefore,

 [A]e=[A]0[P]e=k1k1+k1[A]0{\displaystyle \ [{\ce {A}}]_{e}={\ce {[A]0}}-[{\ce {P}}]_{e}={\frac {k_{-1}}{k_{1}+k_{-1}}}{\ce {[A]0}}}

These equations allow us to uncouple thesystem of differential equations, and allow us to solve for the concentration of A alone.

The reaction equation was given previously as:

v=k1[A]a[B]bk1[P]p[Q]q{\displaystyle v=k_{1}[{\ce {A}}]^{a}[{\ce {B}}]^{b}-k_{-1}[{\ce {P}}]^{p}[{\ce {Q}}]^{q}}

ForAP{\displaystyle {\ce {A <=> P}}} this is simply

d[A]dt=k1[A]tk1[P]t{\displaystyle -{\frac {d[{\ce {A}}]}{dt}}=k_{1}[{\ce {A}}]_{t}-k_{-1}[{\ce {P}}]_{t}}

The derivative is negative because this is the rate of the reaction going from A to P, and therefore the concentration of A is decreasing. To simplify notation, letx be[A]t{\displaystyle [{\ce {A}}]_{t}}, the concentration of A at timet. Letxe{\displaystyle x_{e}} be the concentration of A at equilibrium. Then:

d[A]dt=k1[A]tk1[P]tdxdt=k1xk1[P]t=k1xk1([A]0x)=(k1+k1)xk1[A]0{\displaystyle {\begin{aligned}-{\frac {d[{\ce {A}}]}{dt}}&={k_{1}[{\ce {A}}]_{t}}-{k_{-1}[{\ce {P}}]_{t}}\\[8pt]-{\frac {dx}{dt}}&={k_{1}x}-{k_{-1}[{\ce {P}}]_{t}}\\[8pt]&={k_{1}x}-{k_{-1}({\ce {[A]0}}-x)}\\[8pt]&={(k_{1}+k_{-1})x}-{k_{-1}{\ce {[A]0}}}\end{aligned}}}

Since:

k1+k1=k1[A]0xe{\displaystyle k_{1}+k_{-1}=k_{-1}{\frac {{\ce {[A]0}}}{x_{e}}}}

thereaction rate becomes:

dxdt=k1[A]0xe(xex){\displaystyle {\frac {dx}{dt}}={\frac {k_{-1}{\ce {[A]0}}}{x_{e}}}(x_{e}-x)}

which results in:

ln([A]0[A]e[A]t[A]e)=(k1+k1)t{\displaystyle \ln \left({\frac {{\ce {[A]0}}-[{\ce {A}}]_{e}}{[{\ce {A}}]_{t}-[{\ce {A}}]_{e}}}\right)=(k_{1}+k_{-1})t}.

A plot of the negativenatural logarithm of the concentration of A in time minus the concentration at equilibrium versus timet gives a straight line with slopek1 +k−1. By measurement of [A]e and [P]e the values ofK and the tworeaction rate constants will be known.[32]

Generalization of simple example

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If the concentration at the timet = 0 is different from above, the simplifications above are invalid, and a system of differential equations must be solved. However, this system can also be solved exactly to yield the following generalized expressions:

[A]=[A]01k1+k1(k1+k1e(k1+k1)t)+[P]0k1k1+k1(1e(k1+k1)t)[P]=[A]0k1k1+k1(1e(k1+k1)t)+[P]01k1+k1(k1+k1e(k1+k1)t){\displaystyle {\begin{aligned}&\left[{\ce {A}}\right]={\ce {[A]0}}{\frac {1}{k_{1}+k_{-1}}}\left(k_{-1}+k_{1}e^{-\left(k_{1}+k_{-1}\right)t}\right)+{\ce {[P]0}}{\frac {k_{-1}}{k_{1}+k_{-1}}}\left(1-e^{-\left(k_{1}+k_{-1}\right)t}\right)\\[8pt]&\left[{\ce {P}}\right]={\ce {[A]0}}{\frac {k_{1}}{k_{1}+k_{-1}}}\left(1-e^{-\left(k_{1}+k_{-1}\right)t}\right)+{\ce {[P]0}}{\frac {1}{k_{1}+k_{-1}}}\left(k_{1}+k_{-1}e^{-\left(k_{1}+k_{-1}\right)t}\right)\end{aligned}}}

When the equilibrium constant is close to unity and the reaction rates very fast for instance inconformational analysis of molecules, other methods are required for the determination of rate constants for instance by complete lineshape analysis inNMR spectroscopy.

Consecutive reactions

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If the rate constants for the following reaction arek1{\displaystyle k_{1}} andk2{\displaystyle k_{2}};ABC{\displaystyle {\ce {A -> B -> C}}}, then the rate equation is:

For reactant A:d[A]dt=k1[A]{\displaystyle {\frac {d[{\ce {A}}]}{dt}}=-k_{1}[{\ce {A}}]}
For reactant B:d[B]dt=k1[A]k2[B]{\displaystyle {\frac {d[{\ce {B}}]}{dt}}=k_{1}[{\ce {A}}]-k_{2}[{\ce {B}}]}
For product C:d[C]dt=k2[B]{\displaystyle {\frac {d[{\ce {C}}]}{dt}}=k_{2}[{\ce {B}}]}

With the individual concentrations scaled by the total population of reactants to become probabilities, linear systems of differential equations such as these can be formulated as amaster equation. The differential equations can be solved analytically and the integrated rate equations are

[A]=[A]0ek1t{\displaystyle [{\ce {A}}]={\ce {[A]0}}e^{-k_{1}t}}
[B]={[A]0k1k2k1(ek1tek2t)+[B]0ek2tk1k2[A]0k1tek1t+[B]0ek1totherwise{\displaystyle \left[{\ce {B}}\right]={\begin{cases}{\ce {[A]0}}{\frac {k_{1}}{k_{2}-k_{1}}}\left(e^{-k_{1}t}-e^{-k_{2}t}\right)+{\ce {[B]0}}e^{-k_{2}t}&k_{1}\neq k_{2}\\{\ce {[A]0}}k_{1}te^{-k_{1}t}+{\ce {[B]0}}e^{-k_{1}t}&{\text{otherwise}}\\\end{cases}}}
[C]={[A]0(1+k1ek2tk2ek1tk2k1)+[B]0(1ek2t)+[C]0k1k2[A]0(1ek1tk1tek1t)+[B]0(1ek1t)+[C]0otherwise{\displaystyle \left[{\ce {C}}\right]={\begin{cases}{\ce {[A]0}}\left(1+{\frac {k_{1}e^{-k_{2}t}-k_{2}e^{-k_{1}t}}{k_{2}-k_{1}}}\right)+{\ce {[B]0}}\left(1-e^{-k_{2}t}\right)+{\ce {[C]0}}&k_{1}\neq k_{2}\\{\ce {[A]0}}\left(1-e^{-k_{1}t}-k_{1}te^{-k_{1}t}\right)+{\ce {[B]0}}\left(1-e^{-k_{1}t}\right)+{\ce {[C]0}}&{\text{otherwise}}\\\end{cases}}}

Thesteady state approximation leads to very similar results in an easier way.

Parallel or competitive reactions

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Time course of two first order, competitive reactions with differing rate constants.

When a substance reacts simultaneously to give two different products, a parallel or competitive reaction is said to take place.

Two first order reactions

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AB{\displaystyle {\ce {A -> B}}} andAC{\displaystyle {\ce {A -> C}}}, with constantsk1{\displaystyle k_{1}} andk2{\displaystyle k_{2}} and rate equationsd[A]dt=(k1+k2)[A]{\displaystyle -{\frac {d[{\ce {A}}]}{dt}}=(k_{1}+k_{2})[{\ce {A}}]};d[B]dt=k1[A]{\displaystyle {\frac {d[{\ce {B}}]}{dt}}=k_{1}[{\ce {A}}]} andd[C]dt=k2[A]{\displaystyle {\frac {d[{\ce {C}}]}{dt}}=k_{2}[{\ce {A}}]}

The integrated rate equations are then[A]=[A]0e(k1+k2)t{\displaystyle [{\ce {A}}]={\ce {[A]0}}e^{-(k_{1}+k_{2})t}};[B]=k1k1+k2[A]0(1e(k1+k2)t){\displaystyle [{\ce {B}}]={\frac {k_{1}}{k_{1}+k_{2}}}{\ce {[A]0}}\left(1-e^{-(k_{1}+k_{2})t}\right)} and[C]=k2k1+k2[A]0(1e(k1+k2)t){\displaystyle [{\ce {C}}]={\frac {k_{2}}{k_{1}+k_{2}}}{\ce {[A]0}}\left(1-e^{-(k_{1}+k_{2})t}\right)}.

One important relationship in this case is[B][C]=k1k2{\displaystyle {\frac {{\ce {[B]}}}{{\ce {[C]}}}}={\frac {k_{1}}{k_{2}}}}

One first order and one second order reaction

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This can be the case when studying a bimolecular reaction and a simultaneous hydrolysis (which can be treated as pseudo order one) takes place: the hydrolysis complicates the study of the reaction kinetics, because some reactant is being "spent" in a parallel reaction. For example, A reacts with R to give our product C, but meanwhile the hydrolysis reaction takes away an amount of A to give B, a byproduct:A+H2OB{\displaystyle {\ce {A + H2O -> B}}} andA+RC{\displaystyle {\ce {A + R -> C}}}. The rate equations are:d[B]dt=k1[A][H2O]=k1[A]{\displaystyle {\frac {d[{\ce {B}}]}{dt}}=k_{1}{\ce {[A][H2O]}}=k_{1}'[{\ce {A}}]} andd[C]dt=k2[A][R]{\displaystyle {\frac {d[{\ce {C}}]}{dt}}=k_{2}{\ce {[A][R]}}}, wherek1{\displaystyle k_{1}'} is the pseudo first order constant.[33]

The integrated rate equation for the main product [C] is[C]=[R]0[1ek2k1[A]0(1ek1t)]{\displaystyle {\ce {[C]=[R]0}}\left[1-e^{-{\frac {k_{2}}{k_{1}'}}{\ce {[A]0}}\left(1-e^{-k_{1}'t}\right)}\right]}, which is equivalent toln[R]0[R]0[C]=k2[A]0k1(1ek1t){\displaystyle \ln {\frac {{\ce {[R]0}}}{{\ce {[R]0-[C]}}}}={\frac {k_{2}{\ce {[A]0}}}{k_{1}'}}\left(1-e^{-k_{1}'t}\right)}. Concentration of B is related to that of C through[B]=k1k2ln(1[C][R]0){\displaystyle [{\ce {B}}]=-{\frac {k_{1}'}{k_{2}}}\ln \left(1-{\frac {\ce {[C]}}{\ce {[R]0}}}\right)}

The integrated equations were analytically obtained but during the process it was assumed that[A]0[C][A]0{\displaystyle {\ce {[A]0}}-{\ce {[C]}}\approx {\ce {[A]0}}}. Therefore, previous equation for [C] can only be used for low concentrations of [C] compared to [A]0

Stoichiometric reaction networks

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The most general description of achemical reaction network considers a numberN{\displaystyle N} of distinct chemical species reacting viaR{\displaystyle R} reactions.[34][35] The chemical equation of thej{\displaystyle j}-th reaction can then be written in the generic form

r1jX1+r2jX2++rNjXNkj p1jX1+ p2jX2++pNjXN,{\displaystyle r_{1j}{\ce {X}}_{1}+r_{2j}{\ce {X}}_{2}+\cdots +r_{Nj}{\ce {X}}_{N}{\ce {->[k_{j}]}}\ p_{1j}{\ce {X}}_{1}+\ p_{2j}{\ce {X}}_{2}+\cdots +p_{Nj}{\ce {X}}_{N},}

which is often written in the equivalent form

i=1NrijXikji=1N pijXi.{\displaystyle \sum _{i=1}^{N}r_{ij}{\ce {X}}_{i}{\ce {->[k_{j}]}}\sum _{i=1}^{N}\ p_{ij}{\ce {X}}_{i}.}

Here

The rate of such a reaction can be inferred by thelaw of mass action

fj([X])=kjz=1N[Xz]rzj{\displaystyle f_{j}([\mathbf {X} ])=k_{j}\prod _{z=1}^{N}[{\ce {X}}_{z}]^{r_{zj}}}

which denotes the flux of molecules per unit time and unit volume. Here([X])=([X1],[X2],,[XN]){\displaystyle {\ce {([\mathbf {X} ])=([X1],[X2],\ldots ,[X_{\mathit {N}}])}}} is the vector of concentrations. This definition includes theelementary reactions:

zero order reactions
for whichrzj=0{\displaystyle r_{zj}=0} for allz{\displaystyle z},
first order reactions
for whichrzj=1{\displaystyle r_{zj}=1} for a singlez{\displaystyle z},
second order reactions
for whichrzj=1{\displaystyle r_{zj}=1} for exactly twoz{\displaystyle z}; that is, a bimolecular reaction, orrzj=2{\displaystyle r_{zj}=2} for a singlez{\displaystyle z}; that is, a dimerization reaction.

Each of these is discussed in detail below. One can define thestoichiometric matrix

Nij=pijrij,{\displaystyle N_{ij}=p_{ij}-r_{ij},}

denoting the net extent of molecules ofi{\displaystyle i} in reactionj{\displaystyle j}. The reaction rate equations can then be written in the general form

d[Xi]dt=j=1RNijfj([X]).{\displaystyle {\frac {d[{\ce {X}}_{i}]}{dt}}=\sum _{j=1}^{R}N_{ij}f_{j}([\mathbf {X} ]).}

This is the product of the stoichiometric matrix and the vector of reaction rate functions.Particular simple solutions exist in equilibrium,d[Xi]dt=0{\displaystyle {\frac {d[{\ce {X}}_{i}]}{dt}}=0}, for systems composed of merely reversible reactions. In this case, the rate of the forward and backward reactions are equal, a principle calleddetailed balance. Detailed balance is a property of the stoichiometric matrixNij{\displaystyle N_{ij}} alone and does not depend on the particular form of the rate functionsfj{\displaystyle f_{j}}. All other cases where detailed balance is violated are commonly studied byflux balance analysis, which has been developed to understandmetabolic pathways.[36][37]

General dynamics of unimolecular conversion

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For a general unimolecular reaction involving interconversion ofN{\displaystyle N} different species, whose concentrations at timet{\displaystyle t} are denoted byX1(t){\displaystyle X_{1}(t)} throughXN(t){\displaystyle X_{N}(t)}, an analytic form for the time-evolution of the species can be found. Let the rate constant of conversion from speciesXi{\displaystyle X_{i}} to speciesXj{\displaystyle X_{j}} be denoted askij{\displaystyle k_{ij}}, and construct a rate-constant matrixK{\displaystyle K} whose entries are thekij{\displaystyle k_{ij}}.

Also, letX(t)=(X1(t),X2(t),,XN(t))T{\displaystyle X(t)=(X_{1}(t),X_{2}(t),\ldots ,X_{N}(t))^{T}} be the vector of concentrations as a function of time.

LetJ=(1,1,1,,1)T{\displaystyle J=(1,1,1,\ldots ,1)^{T}} be the vector of ones.

LetI{\displaystyle I} be theN×N{\displaystyle N\times N} identity matrix.

Letdiag{\displaystyle \operatorname {diag} } be the function that takes a vector and constructs a diagonal matrix whose on-diagonal entries are those of the vector.

LetL1{\displaystyle {\mathcal {L}}^{-1}} be the inverse Laplace transform froms{\displaystyle s} tot{\displaystyle t}.

Then the time-evolved stateX(t){\displaystyle X(t)} is given by

X(t)=L1[(sI+diag(KJ)KT)1X(0)],{\displaystyle X(t)={\mathcal {L}}^{-1}[(sI+\operatorname {diag} (KJ)-K^{T})^{-1}X(0)],}

thus providing the relation between the initial conditions of the system and its state at timet{\displaystyle t}.

See also

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References

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  1. ^Gold, Victor, ed. (2019).The IUPAC Compendium of Chemical Terminology: The Gold Book (4 ed.). Research Triangle Park, NC: International Union of Pure and Applied Chemistry (IUPAC).doi:10.1351/goldbook.
  2. ^ab"14.3: Effect of Concentration on Reaction Rates: The Rate Law".Chemistry LibreTexts. 2015-01-18. Retrieved2023-04-10.
  3. ^Atkins & de Paula 2006, p. 794
  4. ^IUPAC,Compendium of Chemical Terminology, 5th ed. (the "Gold Book") (2025). Online version: (2006–) "Rate of reaction".doi:10.1351/goldbook.R05156
  5. ^Atkins & de Paula 2006, p. 795
  6. ^abcAtkins & de Paula 2006, p. 796
  7. ^Connors 1990, p. 13
  8. ^Connors 1990, p. 12
  9. ^Atkins & de Paula 2006, pp. 797–8
  10. ^Espenson 1987, pp. 5–8
  11. ^Atkins & de Paula 2006, pp. 798–800
  12. ^Espenson 1987, pp. 15–18
  13. ^Espenson 1987, pp. 30–31
  14. ^abcKapoor, K. L. (2007).A Textbook of physical chemistry. Vol. 5: Dynamics of chemical reactions, statistical thermodynamics and macromolecules. Vol. 5 (repr ed.). New Dehi: Macmillan India Ltd.ISBN 978-1-4039-2277-9.
  15. ^abAtkins & de Paula 2006, p. 796
  16. ^Tinoco & Wang 1995, p. 331
  17. ^Walsh, Dylan J.; Lau, Sii Hong; Hyatt, Michael G.; Guironnet, Damien (2017-09-25). "Kinetic Study of Living Ring-Opening Metathesis Polymerization with Third-Generation Grubbs Catalysts".Journal of the American Chemical Society.139 (39):13644–13647.Bibcode:2017JAChS.13913644W.doi:10.1021/jacs.7b08010.ISSN 0002-7863.PMID 28944665.
  18. ^Espenson, James H. (1981).Chemical Kinetics and Reaction Mechanisms. McGraw-Hill. p. 14.ISBN 0-07-019667-2.
  19. ^Atkins & de Paula 2006, pp. 813–4
  20. ^Keith J. Laidler,Chemical Kinetics (3rd ed., Harper & Row 1987), p.303-5ISBN 0-06-043862-2
  21. ^R.H. Petrucci, W.S. Harwood and F.G. Herring, General Chemistry (8th ed., Prentice-Hall 2002) p.588ISBN 0-13-014329-4
  22. ^abcConnors 1990
  23. ^Whitten K. W., Galley K. D. and Davis R. E.General Chemistry (4th edition, Saunders 1992), pp. 638–9ISBN 0-03-072373-6
  24. ^Tinoco & Wang 1995, pp. 328–9
  25. ^abcNDRL Radiation Chemistry Data Center. See also:Capellos, Christos; Bielski, Benon H. (1972).Kinetic systems: mathematical description of chemical kinetics in solution. New York: Wiley-Interscience.ISBN 978-0471134503.OCLC 247275.
  26. ^abcAtkins & de Paula 2006, p. 830
  27. ^Laidler 1987, p. 301
  28. ^abLaidler 1987, pp. 310–311
  29. ^Espenson 1987, pp. 34, 60
  30. ^Mucientes, Antonio E.; de la Peña, María A. (November 2006)."Ruthenium(VI)-Catalyzed Oxidation of Alcohols by Hexacyanoferrate(III): An Example of Mixed Order".Journal of Chemical Education.83 (11): 1643.Bibcode:2006JChEd..83.1643M.doi:10.1021/ed083p1643.ISSN 0021-9584.
  31. ^Laidler 1987, p. 305
  32. ^Rushton, Gregory T.; Burns, William G.; Lavin, Judi M.; Chong, Yong S.; Pellechia, Perry; Shimizu, Ken D. (September 2007)."Determination of the Rotational Barrier for Kinetically Stable Conformational Isomers via NMR and 2D TLC".Journal of Chemical Education.84 (9): 1499.doi:10.1021/ed084p1499.ISSN 0021-9584.
  33. ^Manso, José A.; Pérez-Prior, M. Teresa; García-Santos, M. del Pilar; Calle, Emilio; Casado, Julio (2005). "A Kinetic Approach to the Alkylating Potential of Carcinogenic Lactones".Chemical Research in Toxicology.18 (7):1161–1166.CiteSeerX 10.1.1.632.3473.doi:10.1021/tx050031d.PMID 16022509.
  34. ^Heinrich, Reinhart; Schuster, Stefan (2012).The Regulation of Cellular Systems. Springer Science & Business Media.ISBN 9781461311614.
  35. ^Chen, Luonan; Wang, Ruiqi; Li, Chunguang; Aihara, Kazuyuki (2010).Modeling Biomolecular Networks in Cells.doi:10.1007/978-1-84996-214-8.ISBN 978-1-84996-213-1.
  36. ^Szallasi, Z., and Stelling, J. and Periwal, V. (2006)System modeling in cell biology: from concepts to nuts and bolts. MIT Press Cambridge.
  37. ^Iglesias, Pablo A.; Ingalls, Brian P. (2010).Control theory and systems biology. MIT Press.ISBN 9780262013345.

Books cited

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External links

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Nucleophilic substitutions
Electrophilic substitutions
Elimination reactions
Addition reactions
Unimolecular reactions
Electron/Proton transfer reactions
Medium effects
Related topics
Chemical kinetics
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