Let be the vector space equipped with the usualdot product (thus making it aninner product space), and let withthen its orthogonal complement can also be defined as being
The fact that everycolumn vector in is orthogonal to every column vector in can be checked by direct computation. The fact that the spans of these vectors are orthogonal then follows by bilinearity of the dot product. Finally, the fact that these spaces are orthogonal complements follows from the dimension relationships given below.
Let be a vector space over afield equipped with abilinear form We define to be left-orthogonal to, and to be right-orthogonal to, when For a subset of define the left-orthogonal complement to be
There is a corresponding definition of the right-orthogonal complement. For areflexive bilinear form, where, the left and right complements coincide. This will be the case if is asymmetric or analternating form.
If is any subset of an inner product space then itsorthogonal complement in is the vector subspacewhich is always aclosed subset (hence, a closed vector subspace) of[3][proof 1] that satisfies:
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If is a vector subspace of an inner product space then If is a closed vector subspace of a Hilbert space then[3]where is called theorthogonal decomposition of into and and it indicates that is acomplemented subspace of with complement
The orthogonal complement is always closed in themetric topology. In finite-dimensional spaces, that is merely an instance of the fact that all subspaces of a vector space are closed. In infinite-dimensionalHilbert spaces, some subspaces are not closed, but all orthogonal complements are closed. If is a vector subspace of aHilbert space the orthogonal complement of the orthogonal complement of is theclosure of that is,
Some other useful properties that always hold are the following. Let be a Hilbert space and let and be linear subspaces. Then:
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if then;
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if is a closed linear subspace of then;
if is a closed linear subspace of then the (inner)direct sum.
The orthogonal complement generalizes to theannihilator, and gives aGalois connection on subsets of the inner product space, with associatedclosure operator the topological closure of the span.
For a finite-dimensional inner product space of dimension, the orthogonal complement of a-dimensional subspace is an-dimensional subspace, and the double orthogonal complement is the original subspace:
There is a natural analog of this notion in generalBanach spaces. In this case one defines the orthogonal complement of to be a subspace of thedual of defined similarly as theannihilator
It is always a closed subspace of. There is also an analog of the double complement property. is now a subspace of(which is not identical to). However, thereflexive spaces have anaturalisomorphism between and. In this case we have
^If then which is closed in so assume Let where is the underlying scalar field of and define by which is continuous because this is true of each of its coordinates Then is closed in because is closed in and is continuous. If is linear in its first (respectively, its second) coordinate then is alinear map (resp. anantilinear map); either way, its kernel is a vector subspace ofQ.E.D.