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Measurable cardinal

From Wikipedia, the free encyclopedia
Set theory concept

Inmathematics, specifically inset theory, ameasurable cardinal is a certain kind oflarge cardinal number. In order to define the concept, one introduces a two-valuedmeasure on a cardinalκ{\displaystyle \kappa }, or more generally on any set. For a cardinalκ{\displaystyle \kappa }, it can be described as a subdivision of all of itssubsets into large and small sets such thatκ{\displaystyle \kappa } itself is large, theempty set and allsingletons{α}{\displaystyle \{\alpha \}} withακ{\displaystyle \alpha \in \kappa } are small,complements of small sets are large and vice versa. Theintersection of fewer thanκ{\displaystyle \kappa } large sets is again large.[1]

It turns out thatuncountable cardinals endowed with a two-valued measure are large cardinals whose existence cannot be proved fromZFC.[2]

The concept of a measurable cardinal was introduced byStanisław Ulam in 1930.[3]

Definition

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Formally, a measurable cardinal is an uncountablecardinal numberκ{\displaystyle \kappa } such that there exists aκ{\displaystyle \kappa }-additive, non-trivial, 0-1-valuedmeasureμ{\displaystyle \mu } on thepower set ofκ{\displaystyle \kappa }.

Here,κ{\displaystyle \kappa }-additive means that for everyλ<κ{\displaystyle \lambda <\kappa } and everyλ{\displaystyle \lambda }-sized collection{Aβ}β<λ{\displaystyle \{A_{\beta }\}_{\beta <\lambda }} of pairwise disjoint subsetsAβκ{\displaystyle A_{\beta }\subseteq \kappa }, we have

μ(β<λAβ)=β<λμ(Aβ){\displaystyle \mu {\Big (}\bigcup _{\beta <\lambda }A_{\beta }{\Big )}=\sum _{\beta <\lambda }\mu (A_{\beta })}.

Equivalently,κ{\displaystyle \kappa } is a measurable cardinal if and only if it is an uncountable cardinal with aκ{\displaystyle \kappa }-complete, non-principalultrafilter. This means that the intersection of anystrictly less thanκ{\displaystyle \kappa }-many sets in the ultrafilter is also in the ultrafilter.

Equivalently,κ{\displaystyle \kappa } is measurable if it is thecritical point of a non-trivialelementary embedding of theuniverseV{\displaystyle V} into atransitive classM{\displaystyle M}. This equivalence is due toJerome Keisler andDana Scott, and uses theultrapower construction frommodel theory. SinceV{\displaystyle V} is aproper class, a technical problem that is not usually present when considering ultrapowers needs to be addressed, by what is now calledScott's trick.

Properties

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It is trivial to note that ifκ{\displaystyle \kappa } admits a non-trivialκ{\displaystyle \kappa }-additive measure, thenκ{\displaystyle \kappa } must beregular: by non-triviality andκ{\displaystyle \kappa }-additivity, any subset of cardinality less thanκ{\displaystyle \kappa } must have measure 0, and then byκ{\displaystyle \kappa }-additivity again, this means that the entire set must not be a union of fewer thanκ{\displaystyle \kappa } sets of cardinality less thanκ{\displaystyle \kappa }. Finally, ifλ<κ{\displaystyle \lambda <\kappa } then it can't be the case thatκ2λ{\displaystyle \kappa \leq 2^{\lambda }}. If this were the case, we could identifyκ{\displaystyle \kappa } with some collection of 0-1 sequences of lengthκ{\displaystyle \kappa }. For each position in the sequence, either the subset of sequences with 1 in that position or the subset with 0 in that position would have to have measure 1. The intersection of theseλ{\displaystyle \lambda }-many measure 1 subsets would thus also have to have measure 1, but it would contain exactly one sequence, which would contradict the non-triviality of the measure. Thus, assuming theaxiom of choice, we can infer thatκ{\displaystyle \kappa } is astrong limit cardinal, which completes the proof of itsinaccessibility.

Although it follows fromZFC that every measurable cardinal isinaccessible (and isineffable,Ramsey, etc.), it is consistent withZF that a measurable cardinal can be asuccessor cardinal. It follows from ZF + AD thatω1{\displaystyle \omega _{1}} is measurable,[4] and that every subset ofω1{\displaystyle \omega _{1}} contains or is disjoint from aclosed and unbounded subset.

Ulam showed that the smallest cardinalκ{\displaystyle \kappa } that admits a non-trivial countably-additive two-valued measure must in fact admit aκ{\displaystyle \kappa }-additive measure. (If there were some collection of fewer thanκ{\displaystyle \kappa } measure-0 subsets whose union wasκ{\displaystyle \kappa }, then the induced measure on this collection would be a counterexample to the minimality ofκ{\displaystyle \kappa }.) From there, one can prove (with the axiom of choice) that the least such cardinal must be inaccessible.

Ifκ{\displaystyle \kappa } is measurable andpVκ{\displaystyle p\in V_{\kappa }} andM{\displaystyle M} (the ultrapower ofV{\displaystyle V}) satisfiesψ(κ,p){\displaystyle \psi (\kappa ,p)}, then the set ofα<κ{\displaystyle \alpha <\kappa } such thatV{\displaystyle V} satisfiesψ(α,p){\displaystyle \psi (\alpha ,p)} is stationary inκ{\displaystyle \kappa } (actually a set of measure 1). In particular, ifψ{\displaystyle \psi } is aΠ1{\displaystyle \Pi _{1}} formula andV{\displaystyle V} satisfiesψ(κ,p){\displaystyle \psi (\kappa ,p)}, thenM{\displaystyle M} satisfies it and thusV{\displaystyle V} satisfiesψ(α,p){\displaystyle \psi (\alpha ,p)} for a stationary set ofα<κ{\displaystyle \alpha <\kappa }. This property can be used to show thatκ{\displaystyle \kappa } is a limit of most types of large cardinals that are weaker than measurable. Notice that the ultrafilter or measure witnessing thatκ{\displaystyle \kappa } is measurable cannot be inM{\displaystyle M} since the smallest such measurable cardinal would have to have another such below it, which is impossible.

If one starts with an elementary embeddingj1{\displaystyle j_{1}} ofV{\displaystyle V} intoM1{\displaystyle M_{1}} withcritical pointκ{\displaystyle \kappa }, then one can define an ultrafilterU{\displaystyle U} onκ{\displaystyle \kappa } as{Sκκj1(S)}{\displaystyle \{S\subseteq \kappa \mid \kappa \in j_{1}(S)\}}. Then, taking an ultrapower ofV{\displaystyle V} overU{\displaystyle U}, we can get another elementary embeddingj2{\displaystyle j_{2}} ofV{\displaystyle V} intoM2{\displaystyle M_{2}}. However, it is important to remember thatj2j1{\displaystyle j_{2}\neq j_{1}}. Thus, other types of large cardinals such asstrong cardinals may also be measurable, but not using the same embedding. It can be shown that a strong cardinalκ{\displaystyle \kappa } is measurable and also hasκ{\displaystyle \kappa }-many measurable cardinals below it.

Every measurable cardinalκ{\displaystyle \kappa } is a 0-huge cardinal becauseκMM{\displaystyle ^{\kappa }M\subseteq M}, that is, every function fromκ{\displaystyle \kappa } toM{\displaystyle M}, is inM{\displaystyle M}. Consequently,Vκ+1M{\displaystyle V_{\kappa +1}\subseteq M}.

Implications of existence

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If a measurable cardinal exists, everyΣ21{\displaystyle \mathbf {\Sigma } _{2}^{1}} (with respect to theanalytical hierarchy) set of reals has aLebesgue measure.[4] In particular, anynon-measurable set of reals must not beΣ21{\displaystyle \mathbf {\Sigma } _{2}^{1}}.

Real-valued measurable

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A cardinalκ{\displaystyle \kappa } is calledreal-valued measurable if there is aκ{\displaystyle \kappa }-additiveprobability measure on the power set ofκ{\displaystyle \kappa } that vanishes on singletons. Real-valued measurable cardinals were introduced byStefan Banach (1930).Banach & Kuratowski (1929) showed that thecontinuum hypothesis implies thatc{\displaystyle {\mathfrak {c}}} is not real-valued measurable.Stanislaw Ulam (1930) showed (see below for parts of Ulam's proof) that real valued measurable cardinals are weakly inaccessible (they are in factweakly Mahlo). All measurable cardinals are real-valued measurable, and a real-valued measurable cardinalκ{\displaystyle \kappa } is measurable if and only ifκ{\displaystyle \kappa } is greater thanc{\displaystyle {\mathfrak {c}}}. Thus a cardinal is measurable if and only if it is real-valued measurable and strongly inaccessible. A real valued measurable cardinal less than or equal toc{\displaystyle {\mathfrak {c}}} exists if and only if there is acountably additive extension of theLebesgue measure to all sets of real numbers if and only if there is anatomless probability measure on the power set of some non-empty set.

Solovay (1971) showed that existence of measurable cardinals in ZFC, real-valued measurable cardinals in ZFC, and measurable cardinals in ZF, areequiconsistent.

Weak inaccessibility of real-valued measurable cardinals

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Letμ{\displaystyle \mu } be an outer measure on a setX{\displaystyle X}. Say that a cardinal numberα{\displaystyle \alpha } is anUlam number if whenever[5][nb 1]

μ(X){\displaystyle \mu (X)\leq \infty },1
μ({x})=0{\displaystyle \mu (\{x\})=0} for everyxX{\displaystyle x\in X},2
allAX{\displaystyle A\subseteq X} areμ-measurable,3

then|X|α{\displaystyle |X|\leq \alpha } impliesμ(X)=0{\displaystyle \mu (X)=0}.

Equivalently, ifF{\displaystyle F} is a set of pairwise disjoint subsets ofX{\displaystyle X},α{\displaystyle \alpha } is an Ulam number if whenever

  1. μ(F)<{\displaystyle \mu (\textstyle \bigcup F)<\infty },
  2. μ(A)=0{\displaystyle \mu (A)=0} forAF{\displaystyle A\in F},
  3. G{\displaystyle \textstyle \bigcup G} isμ{\displaystyle \mu }-measurable for everyGF{\displaystyle G\subset F},

then|F|α{\displaystyle |F|\leq \alpha } impliesμ(F)=0{\displaystyle \mu (\textstyle \bigcup F)=0}.

The smallest infinite cardinal0 is an Ulam number. The class of Ulam numbers is closed under thecardinal successor operation.[6] If an infinite cardinalβ{\displaystyle \beta } has an immediate predecessorα{\displaystyle \alpha } that is an Ulam number, assumeμ{\displaystyle \mu } satisfies properties (1)–(3) withX=β{\displaystyle X=\beta }. In thevon Neumann model of ordinals and cardinals, for eachxβ{\displaystyle x\in \beta }, choose aninjective functionfx:xα{\displaystyle f_{x}:x\to \alpha } and define the sets

U(b,a)={xβfx(b)=a}{\displaystyle U(b,a)=\{x\in \beta \mid f_{x}(b)=a\}}.

Since the functionsfx{\displaystyle f_{x}} are injective, the sets

{U(b,a)bβ}{\displaystyle \{U(b,a)\mid b\in \beta \}} withaα{\displaystyle a\in \alpha } fixed

and

{U(b,a)aα}{\displaystyle \{U(b,a)\mid a\in \alpha \}} withbβ{\displaystyle b\in \beta } fixed

are pairwise disjoint. By property (1) ofμ{\displaystyle \mu }, the set

{bβμ(U(b,a))>0}{\displaystyle \{b\in \beta \mid \mu (U(b,a))>0\}}

iscountable, and hence

|{(b,a)β×αμ(U(b,a))>0}|0α{\displaystyle {\big |}\{(b,a)\in \beta \times \alpha \mid \mu (U(b,a))>0\}{\big |}\leq \aleph _{0}\cdot \alpha }.

Thus, there is ab0β{\displaystyle b_{0}\in \beta } such that

μ(U(b0,a))=0{\displaystyle \mu (U(b_{0},a))=0} for allaα{\displaystyle a\in \alpha },

which implies, sinceα{\displaystyle \alpha } is an Ulam number and using the second definition, that

μ(aαU(b0,a))=0{\displaystyle \mu {\Big (}\bigcup _{a\in \alpha }U(b_{0},a){\Big )}=0}.

Ifb0<x<β{\displaystyle b_{0}<x<\beta } andfx(b0)=ax{\displaystyle f_{x}(b_{0})=a_{x}} thenxU(b0,ax){\displaystyle x\in U(b_{0},a_{x})}. Thus

β=b0{b0}aαU(b0,a){\displaystyle \beta =b_{0}\cup \{b_{0}\}\cup \bigcup _{a\in \alpha }U(b_{0},a)}.

By property (1),μ({b0})=0{\displaystyle \mu (\{b_{0}\})=0}, and since|b0|α{\displaystyle |b_{0}|\leq \alpha }, by (3), (1) and (2),μ(b0)=0{\displaystyle \mu (b_{0})=0}. It follows thatμ(β)=0{\displaystyle \mu (\beta )=0}. The conclusion is thatβ{\displaystyle \beta } is an Ulam number.

There is a similar proof[7] that the supremum of a setS{\displaystyle S} of Ulam numbers with|S|{\displaystyle |S|} an Ulam number is again a Ulam number. Together with the previous result, this implies that a cardinal that is not an Ulam number isweakly inaccessible.

See also

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Notes

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  1. ^The notion in the articleUlam number is different.

Citations

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  1. ^Maddy 1988
  2. ^Jech 2002
  3. ^Ulam 1930
  4. ^abT. Jech, "The Brave New World of Determinacy" (PDF download). Bulletin of the American Mathematical Society, vol. 5, number 3, November 1981 (pp.339--349).
  5. ^Federer 1996, Section 2.1.6
  6. ^Federer 1996, Second part of theorem in section 2.1.6.
  7. ^Federer 1996, First part of theorem in section 2.1.6.

References

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