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Logarithmic derivative

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Mathematical operation in calculus
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Calculus
abf(t)dt=f(b)f(a){\displaystyle \int _{a}^{b}f'(t)\,dt=f(b)-f(a)}

Inmathematics, specifically incalculus andcomplex analysis, thelogarithmic derivative of afunctionf is defined by the formulaff{\displaystyle {\frac {f'}{f}}}wheref′ is thederivative off.[1] Intuitively, this is the infinitesimalrelative change inf; that is, the infinitesimal absolute change inf, namelyf′ scaled by the current value off.

Whenf is a functionf(x) of a real variablex, and takesreal, strictlypositive values, this is equal to the derivative oflnf(x), or thenatural logarithm off. This follows directly from thechain rule:[1]ddxlnf(x)=1f(x)df(x)dx{\displaystyle {\frac {d}{dx}}\ln f(x)={\frac {1}{f(x)}}{\frac {df(x)}{dx}}}

Basic properties

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Many properties of the real logarithm also apply to the logarithmic derivative, even when the function doesnot take values in the positive reals. For example, since the logarithm of a product is the sum of the logarithms of the factors, we have(loguv)=(logu+logv)=(logu)+(logv).{\displaystyle (\log uv)'=(\log u+\log v)'=(\log u)'+(\log v)'.}So for positive-real-valued functions, the logarithmic derivative of a product is the sum of the logarithmic derivatives of the factors. But we can also use theLeibniz law for the derivative of a product to get(uv)uv=uv+uvuv=uu+vv.{\displaystyle {\frac {(uv)'}{uv}}={\frac {u'v+uv'}{uv}}={\frac {u'}{u}}+{\frac {v'}{v}}.}Thus, it is true forany function that the logarithmic derivative of a product is the sum of the logarithmic derivatives of the factors (when they are defined).

Acorollary to this is that the logarithmic derivative of the reciprocal of a function is the negation of the logarithmic derivative of the function:(1/u)1/u=u/u21/u=uu,{\displaystyle {\frac {(1/u)'}{1/u}}={\frac {-u'/u^{2}}{1/u}}=-{\frac {u'}{u}},}just as the logarithm of the reciprocal of a positive real number is the negation of the logarithm of the number.[citation needed]

More generally, the logarithmic derivative of a quotient is the difference of the logarithmic derivatives of the dividend and the divisor:(u/v)u/v=(uvuv)/v2u/v=uuvv,{\displaystyle {\frac {(u/v)'}{u/v}}={\frac {(u'v-uv')/v^{2}}{u/v}}={\frac {u'}{u}}-{\frac {v'}{v}},}just as the logarithm of a quotient is the difference of the logarithms of the dividend and the divisor.

Generalising in another direction, the logarithmic derivative of a power (with constant real exponent) is the product of the exponent and the logarithmic derivative of the base:(uk)uk=kuk1uuk=kuu,{\displaystyle {\frac {(u^{k})'}{u^{k}}}={\frac {ku^{k-1}u'}{u^{k}}}=k{\frac {u'}{u}},}just as the logarithm of a power is the product of the exponent and the logarithm of the base.

Finally, the logarithmic derivative of theexponential function ofu is just the derivative ofu:(eu)eu=ueueu=u,{\displaystyle {\frac {(e^{u})'}{e^{u}}}={\frac {u'e^{u}}{e^{u}}}=u',}just as the logarithm of the exponential function of a function is just the original function.

In summary, both derivatives and logarithms have aproduct rule, areciprocal rule, aquotient rule, and apower rule (compare thelist of logarithmic identities); each pair of rules is related through the logarithmic derivative.

Computing ordinary derivatives using logarithmic derivatives

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Main article:Logarithmic differentiation

Logarithmic derivatives can simplify the computation of derivatives requiring theproduct rule while producing the same result. The procedure is as follows: Suppose thatf(x) =u(x)v(x) and that we wish to computef′(x). Instead of computing it directly asf′ =u′v +v′u, we compute its logarithmic derivative. That is, we compute:ff=uu+vv.{\displaystyle {\frac {f'}{f}}={\frac {u'}{u}}+{\frac {v'}{v}}.}

Multiplying through byf computesf′:f=f(uu+vv).{\displaystyle f'=f\cdot \left({\frac {u'}{u}}+{\frac {v'}{v}}\right).}

This technique is most useful whenf is a product of a large number of factors. This technique makes it possible to computef′ by computing the logarithmic derivative of each factor, summing, and multiplying byf.

For example, we can compute the logarithmic derivative of(ex)2(x2)3(x3)(x1)1{\displaystyle (e^{x})^{2}(x-2)^{3}(x-3)(x-1)^{-1}}to be2+3x2+1x31x1.{\displaystyle 2+{\frac {3}{x-2}}+{\frac {1}{x-3}}-{\frac {1}{x-1}}.}

Integrating factors

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The logarithmic derivative idea is closely connected to theintegrating factor method forfirst-order differential equations. Inoperator terms, writeD=ddx{\displaystyle D={\frac {d}{dx}}} and letM denote the operator of multiplication by some given functionG(x). ThenM1DM{\displaystyle M^{-1}DM} can be written (by theproduct rule) asD+M{\displaystyle D+M^{*}} whereM{\displaystyle M^{*}} now denotes the multiplication operator by the logarithmic derivativeGG{\displaystyle {\frac {G'}{G}}}

In practice we are given an operator such asD+F=L{\displaystyle D+F=L}and wish to solve equationsL(h)=f{\displaystyle L(h)=f}for the functionh, givenf. This then reduces to solvingGG=F{\displaystyle {\frac {G'}{G}}=F}which has as solutionexp(F){\displaystyle \exp \textstyle (\int F)}with anyindefinite integral ofF.[citation needed]

Complex analysis

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See also:Argument principle

The formula as given can be applied more widely; for example iff(z) is ameromorphic function, it makes sense at all complex values ofz at whichf has neither azero nor a pole. Further, at a zero or a pole the logarithmic derivative behaves in a way that is easily analysed in terms of the particular case

zn

withn an integer,n ≠ 0. The logarithmic derivative is thenn/z{\displaystyle n/z}and one can draw the general conclusion that forf meromorphic, the singularities of the logarithmic derivative off are allsimple poles, withresiduen from a zero of ordern, residue −n from a pole of ordern. Seeargument principle. This information is often exploited incontour integration.[2][3][verification needed]

In the field ofNevanlinna theory, an important lemma states that the proximity function of a logarithmic derivative is small with respect to the Nevanlinna characteristic of the original function, for instancem(r,h/h)=S(r,h)=o(T(r,h)){\displaystyle m(r,h'/h)=S(r,h)=o(T(r,h))}.[4][verification needed]

The multiplicative group

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Behind the use of the logarithmic derivative lie two basic facts aboutGL1, that is, the multiplicative group ofreal numbers or otherfield. Thedifferential operatorXddX{\displaystyle X{\frac {d}{dX}}}isinvariant under dilation (replacingX byaX fora constant). And thedifferential formdxX{\displaystyle {\frac {dx}{X}}} is likewise invariant. For functionsF into GL1, the formuladFF{\displaystyle {\frac {dF}{F}}} is therefore apullback of the invariant form.[citation needed]

Examples

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See also

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References

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  1. ^ab"Logarithmic derivative - Encyclopedia of Mathematics".encyclopediaofmath.org. 7 December 2012. Retrieved12 August 2021.
  2. ^Gonzalez, Mario (1991-09-24).Classical Complex Analysis. CRC Press.ISBN 978-0-8247-8415-7.
  3. ^"Logarithmic residue - Encyclopedia of Mathematics".encyclopediaofmath.org. 7 June 2020. Retrieved2021-08-12.
  4. ^Zhang, Guan-hou (1993-01-01).Theory of Entire and Meromorphic Functions: Deficient and Asymptotic Values and Singular Directions. American Mathematical Soc. p. 18.ISBN 978-0-8218-8764-6. Retrieved12 August 2021.
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