Afieldk has Krull dimension 0; more generally,k[x1, ...,xn] has Krull dimensionn. Aprincipal ideal domain that is not a field has Krull dimension 1. Alocal ring has Krull dimension 0 if and only if every element of itsmaximal ideal isnilpotent.
There are several other ways that have been used to define the dimension of a ring. Most of them coincide with the Krull dimension for Noetherian rings, but can differ for non-Noetherian rings.
We say that a chain of prime ideals of the formhaslengthn. That is, the length is the number of strict inclusions, not the number of primes; these differ by 1. We define theKrull dimension of to be the supremum of the lengths of all chains of prime ideals in.
Given a prime ideal inR, we define theheight of, written, to be the supremum of the lengths of all chains of prime ideals contained in, meaning that.[1] In other words, the height of is the Krull dimension of thelocalization ofR at. A prime ideal has height zero if and only if it is aminimal prime ideal. The Krull dimension of a ring is the supremum of the heights of all maximal ideals, or those of all prime ideals. The height is also sometimes called the codimension, rank, or altitude of a prime ideal.
In aNoetherian ring, every prime ideal has finite height. Nonetheless, Nagata gave an example of a Noetherian ring of infinite Krull dimension.[2] A ring is calledcatenary if any inclusion of prime ideals can be extended to a maximal chain of prime ideals between and, and any two maximal chains betweenand have the same length. A ring is calleduniversally catenary if any finitely generated algebra over it is catenary. Nagata gave an example of a Noetherian ring which is not catenary.[3]
In a Noetherian ring, a prime ideal has height at mostn if and only if it is aminimal prime ideal over an ideal generated byn elements (Krull's height theorem and its converse).[4] It implies that thedescending chain condition holds for prime ideals in such a way the lengths of the chains descending from a prime ideal are bounded by the number of generators of the prime.[5]
More generally, the height of an idealI is the infimum of the heights of all prime ideals containingI. In the language ofalgebraic geometry, this is thecodimension of the subvariety of Spec() corresponding toI.[1]
It follows readily from the definition of thespectrum of a ring Spec(R), the space of prime ideals ofR equipped with theZariski topology, that the Krull dimension ofR is equal to the dimension of its spectrum as atopological space, meaning the supremum of the lengths of all chains ofirreducible closed subsets. This follows immediately from theGalois connection between ideals ofR and closed subsets of Spec(R) and the observation that, by the definition of Spec(R), each prime ideal ofR corresponds to a generic point of the closed subset associated to by the Galois connection.
The dimension of apolynomial ring over a fieldk[x1, ...,xn] is the number of variablesn. In the language ofalgebraic geometry, this says that the affine space of dimensionn over a field has dimensionn, as expected. In general, ifR is aNoetherian ring of dimensionn, then the dimension ofR[x] isn + 1. If the Noetherian hypothesis is dropped, thenR[x] can have dimension anywhere betweenn + 1 and 2n + 1.
For example, the ideal has height 2 since we can form the maximal ascending chain of prime ideals.
Given an irreducible polynomial, the ideal is not prime (since, but neither of the factors are), but we can easily compute the height since the smallest prime ideal containing is just.
The ring of integersZ has dimension 1. More generally, anyprincipal ideal domain that is not a field has dimension 1.
LetR be an algebra over a fieldk that is an integral domain. Then the Krull dimension ofR is less than or equal to the transcendence degree of the field of fractions ofR overk.[6] The equality holds ifR is finitely generated as an algebra (for instance by theNoether normalization lemma).
LetR be a Noetherian ring,I an ideal and be theassociated graded ring (geometers call it the ring of thenormal cone ofI). Then is the supremum of the heights of maximal ideals ofR containingI.[7]
A commutative Noetherian ring of Krull dimension zero is a direct product of a finite number (possibly one) oflocal rings of Krull dimension zero.
For a commutative Noetherian ring the three following conditions are equivalent: being areduced ring of Krull dimension zero, being a field or adirect product of fields, beingvon Neumann regular.
IfR is a commutative ring, andM is anR-module, we define the Krull dimension ofM to be the Krull dimension of the quotient ofR makingM afaithful module. That is, we define it by the formula:
where AnnR(M), theannihilator, is the kernel of the natural map R → EndR(M) ofR into the ring ofR-linear endomorphisms ofM.
The Krull dimension of a module over a possibly non-commutative ring is defined as thedeviation of the poset of submodules ordered by inclusion. For commutative Noetherian rings, this is the same as the definition using chains of prime ideals.[9] The two definitions can be different for commutative rings which are not Noetherian.