Inring theory, a branch ofmathematics, anidempotent element or simplyidempotent of aring is an elementa such thata2 =a.[1][a] That is, the element isidempotent under the ring's multiplication.Inductively then, one can also conclude thata =a2 =a3 =a4 = ... =an for any positiveintegern. For example, an idempotent element of amatrix ring is precisely anidempotent matrix.
For general rings, elements idempotent under multiplication are involved in decompositions ofmodules, and connected tohomological properties of the ring. InBoolean algebra, the main objects of study are rings in which all elements are idempotent under both addition and multiplication.
One may consider thering of integers modulon, wheren issquare-free. By theChinese remainder theorem, this ring factors into theproduct of rings of integers modulo p, wherep isprime. Now each of these factors is afield, so it is clear that the factors' only idempotents will be0 and1. That is, each factor has two idempotents. So if there arem factors, there will be2m idempotents.
We can check this for the integersmod 6,R =Z / 6Z. Since6 has two prime factors (2 and3) it should have22 idempotents.
From these computations,0,1,3, and4 are idempotents of this ring, while2 and5 are not. This also demonstrates the decomposition properties described below: because3 + 4 ≡ 1 (mod 6), there is a ring decomposition3Z / 6Z ⊕ 4Z / 6Z. In3Z / 6Z the multiplicative identity is3 + 6Z and in4Z / 6Z the multiplicative identity is4 + 6Z.
Given a ringR and an elementf ∈R such thatf2 ≠ 0, thequotient ring
has the idempotentf. For example, this could be applied tox ∈Z[x], or anypolynomialf ∈k[x1, ...,xn].
There is acircle of idempotents in the ring ofsplit-quaternions. Split quaternions have the structure of areal algebra, so elements can be writtenw +xi +yj +zk over abasis {1, i, j, k}, with j2 = k2 = +1. For any θ,
The elements is called ahyperbolic unit and so far, the i-coordinate has been taken as zero. When this coordinate is non-zero, then there is ahyperboloid of one sheet ofhyperbolic units in split-quaternions. The same equality shows the idempotent property of wheres is on the hyperboloid.
A partial list of important types of idempotents includes:
Any non-trivial idempotenta is azero divisor (becauseab = 0 with neithera norb being zero, whereb = 1 −a). This shows thatintegral domains anddivision rings do not have such idempotents.Local rings also do not have such idempotents, but for a different reason. The only idempotent contained in theJacobson radical of a ring is0.
The idempotents ofR have an important connection to decomposition ofR-modules. IfM is anR-module andE = EndR(M) is itsring of endomorphisms, thenA ⊕B =M if and only if there is a unique idempotente inE such thatA =eM andB = (1 −e)M. Clearly then,M is directly indecomposable if and only if0 and1 are the only idempotents inE.[2]
In the case whenM =R (assumed unital), the endomorphism ringEndR(R) =R, where eachendomorphism arises as left multiplication by a fixed ring element. With this modification of notation,A ⊕B =R as right modules if and only if there exists a unique idempotente such thateR =A and(1 −e)R =B. Thus every direct summand ofR is generated by an idempotent.
Ifa is a central idempotent, then the corner ringaRa =Ra is a ring with multiplicative identitya. Just as idempotents determine the direct decompositions ofR as a module, the central idempotents ofR determine the decompositions ofR as adirect sum of rings. IfR is the direct sum of the ringsR1, ...,Rn, then the identity elements of the ringsRi are central idempotents inR, pairwise orthogonal, and their sum is1. Conversely, given central idempotentsa1, ...,an inR that are pairwise orthogonal and have sum1, thenR is the direct sum of the ringsRa1, ...,Ran. So in particular, every central idempotenta inR gives rise to a decomposition ofR as a direct sum of the corner ringsaRa and(1 −a)R(1 −a). As a result, a ringR is directly indecomposable as a ring if and only if the identity1 is centrally primitive.
Working inductively, one can attempt to decompose1 into a sum of centrally primitive elements. If1 is centrally primitive, we are done. If not, it is a sum of central orthogonal idempotents, which in turn are primitive or sums of more central idempotents, and so on. The problem that may occur is that this may continue without end, producing an infinite family of central orthogonal idempotents. The condition "R does not contain infinite sets of central orthogonal idempotents" is a type of finiteness condition on the ring. It can be achieved in many ways, such as requiring the ring to be rightNoetherian. If a decompositionR =c1R ⊕c2R ⊕ ... ⊕cnR exists with eachci a centrally primitive idempotent, thenR is a direct sum of the corner ringsciRci, each of which is ring irreducible.[3]
Forassociative algebras orJordan algebras over a field, thePeirce decomposition is a decomposition of an algebra as a sum of eigenspaces of commuting idempotent elements.
Ifa is an idempotent of a ringR, thenf = 1 − 2a equals its square. So, for every leftR-module, the multiplication byf is aninvolution ofM; that is, it is anR-module homomorphism such thatf2 is the identity endomorphism ofM.
If is an-bimodule, and, in particular, if, the left and the right multiplications with gives rise to two involutions of the module.
Conversely, ifb is an element of such that, then, and, if2 is aninvertible element inR,a=2−1(1 −b) is an idempotent such thatb = 1 − 2a. Thus, for a ring in which2 is invertible, the idempotent elements are inone-to-one correspondence with the elements whose square is 1.
Lifting idempotents also has major consequences for thecategory ofR-modules. All idempotents lift moduloI if and only if everyR direct summand ofR/I has aprojective cover as anR-module.[4] Idempotents always lift modulonil ideals and rings for whichR isI-adically complete.
Lifting is most important whenI = J(R), theJacobson radical ofR. Yet another characterization ofsemiperfect rings is that they aresemilocal rings whose idempotents lift moduloJ(R).[5]
One may define apartial order on the idempotents of a ring as follows: ifa andb are idempotents, we writea ≤b if and only ifab =ba =a. With respect to this order,0 is the smallest and1 the largest idempotent. For orthogonal idempotentsa andb,a +b is also idempotent, and we havea ≤a +b andb ≤a +b. Theatoms of this partial order are precisely the primitive idempotents.[6]
When the above partial order is restricted to the central idempotents ofR, alattice structure, or even aBoolean algebra structure, can be given. For two central idempotentse andf, thecomplement is given by
themeet is given by
and thejoin is given by
The ordering now becomes simplye ≤f if and only ifeR ⊆fR, and the join and meet satisfy(e ∨f)R =eR +fR and(e ∧f)R =eR ∩fR = (eR)(fR). It is shown inGoodearl 1991, p. 99 that ifR isvon Neumann regular and rightself-injective, then the lattice is acomplete lattice.