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Generating set of a group

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Abstract algebra concept
The 5throots of unity in the complex plane form agroup under multiplication. Each non-identity element generates the group.

Inabstract algebra, agenerating set of a group is asubset of the group set such that every element of thegroup can be expressed as a combination (under the group operation) of finitely many elements of the subset and theirinverses.

In other words, ifS{\displaystyle S} is a subset of a groupG{\displaystyle G}, thenS{\displaystyle \langle S\rangle }, thesubgroup generated byS{\displaystyle S}, is the smallestsubgroup ofG{\displaystyle G} containing every element ofS{\displaystyle S}, which is equal to the intersection over all subgroups containing the elements ofS{\displaystyle S}; equivalently,S{\displaystyle \langle S\rangle } is the subgroup of all elements ofG{\displaystyle G} that can be expressed as the finite product of elements inS{\displaystyle S} and their inverses. (Note that inverses are only needed if the group is infinite; in a finite group, the inverse of an element can be expressed as a power of that element.)

IfG=S{\displaystyle G=\langle S\rangle }, then we say thatS{\displaystyle S}generatesG{\displaystyle G}, and the elements inS{\displaystyle S} are calledgenerators orgroup generators. IfS{\displaystyle S} is the empty set, thenS{\displaystyle \langle S\rangle } is thetrivial group{e}{\displaystyle \{e\}}, since we consider theempty product to be the identity.

When there is only a single elementx{\displaystyle x} inS{\displaystyle S},S{\displaystyle \langle S\rangle } is usually written asx{\displaystyle \langle x\rangle }. In this case,x{\displaystyle \langle x\rangle } is thecyclic subgroup of the powers ofx{\displaystyle x}, acyclic group, and we say this group is generated byx{\displaystyle x}. Equivalent to saying an elementx{\displaystyle x} generates a group is saying thatx{\displaystyle \langle x\rangle } equals the entire groupG{\displaystyle G}. Forfinite groups, it is also equivalent to saying thatx{\displaystyle x} hasorder|G|{\displaystyle |G|}.

A group may need an infinite number of generators. For example the additive group ofrational numbersQ{\displaystyle \mathbb {Q} } is not finitely generated. It is generated by the inverses of all the integers, but any finite number of these generators can be removed from the generating set without it ceasing to be a generating set. In a case like this, all the elements in a generating set are nevertheless "non-generating elements", as are in fact all the elements of the whole group − seeFrattini subgroup below.

IfG{\displaystyle G} is atopological group then a subsetS{\displaystyle S} ofG{\displaystyle G} is called a set oftopological generators ifS{\displaystyle \langle S\rangle } isdense inG{\displaystyle G}, i.e. theclosure ofS{\displaystyle \langle S\rangle } is the whole groupG{\displaystyle G}.

Finitely generated group

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Main article:Finitely generated group

IfS{\displaystyle S} is finite, then a groupG=S{\displaystyle G=\langle S\rangle } is calledfinitely generated. The structure offinitely generated abelian groups in particular is easily described. Many theorems that are true for finitely generated groups fail for groups in general. It has been proven that if a finite group is generated by a subsetS{\displaystyle S}, then each group element may be expressed as a word from the alphabetS{\displaystyle S} of length less than or equal to the order of the group.

Every finite group is finitely generated sinceG=G{\displaystyle \langle G\rangle =G}. Theintegers under addition are an example of aninfinite group which is finitely generated by both 1 and −1, but the group ofrationals under addition cannot be finitely generated. Nouncountable group can be finitely generated. For example, the group of real numbers under addition,(R,+){\displaystyle (\mathbb {R} ,+)}.

Different subsets of the same group can be generating subsets. For example, ifp{\displaystyle p} andq{\displaystyle q} are integers withgcd(pq) = 1, then{p,q}{\displaystyle \{p,q\}} also generates the group of integers under addition byBézout's identity.

While it is true that everyquotient of afinitely generated group is finitely generated (the images of the generators in the quotient give a finite generating set), asubgroup of a finitely generated group need not be finitely generated. For example, letG{\displaystyle G} be thefree group in two generators,x{\displaystyle x} andy{\displaystyle y} (which is clearly finitely generated, sinceG={x,y}{\displaystyle G=\langle \{x,y\}\rangle }), and letS{\displaystyle S} be the subset consisting of all elements ofG{\displaystyle G} of the formynxyn{\displaystyle y^{n}xy^{-n}} for somenatural numbern{\displaystyle n}.S{\displaystyle \langle S\rangle } isisomorphic to the free group in countably infinitely many generators, and so cannot be finitely generated. However, every subgroup of a finitely generatedabelian group is in itself finitely generated. In fact, more can be said: the class of all finitely generated groups is closed underextensions. To see this, take a generating set for the (finitely generated)normal subgroup and quotient. Then the generators for the normal subgroup, together with preimages of the generators for the quotient, generate the group.

Examples

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  • On the other hand,Sn, thesymmetric group of degreen, is not generated by any one element (is notcyclic) whenn > 2. However, in these casesSn can always be generated by two permutations which are written incycle notation as (1 2) and(1 2 3 ... n). For example, the 6 elements ofS3 can be generated from the two generators, (1 2) and (1 2 3), as shown by the right hand side of the following equations (composition is left-to-right):
e = (1 2)(1 2)
(1 2) = (1 2)
(1 3) = (1 2)(1 2 3)
(2 3) = (1 2 3)(1 2)
(1 2 3) = (1 2 3)
(1 3 2) = (1 2)(1 2 3)(1 2)
  • Infinite groups can also have finite generating sets. The additive group of integers has 1 as a generating set. The element 2 is not a generating set, as the odd numbers will be missing. The two-element subset{3, 5} is a generating set, since(−5) + 3 + 3 = 1 (in fact, any pair ofcoprime numbers is, as a consequence ofBézout's identity).
  • Thedihedral group of ann-gon (which hasorder2n) is generated by the set{r,s}, wherer represents rotation by2π/n ands is any reflection across a line of symmetry.[1]
  • Apresentation of a group is defined as a set of generators and a collection of relations between them, so any of the examples listed on that page contain examples of generating sets.[3]

Free group

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Main article:Free group

The most general group generated by a setS{\displaystyle S} is the groupfreely generated byS{\displaystyle S}. Every group generated byS{\displaystyle S} isisomorphic to aquotient of this group, a feature which is utilized in the expression of a group'spresentation.

Frattini subgroup

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An interesting companion topic is that ofnon-generators. An elementx{\displaystyle x} of the groupG{\displaystyle G} is a non-generator if every setS{\displaystyle S} containingx{\displaystyle x} that generatesG{\displaystyle G}, still generatesG{\displaystyle G} whenx{\displaystyle x} is removed fromS{\displaystyle S}. In the integers with addition, the only non-generator is 0. The set of all non-generators forms a subgroup ofG{\displaystyle G}, theFrattini subgroup.

Semigroups and monoids

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IfG{\displaystyle G} is asemigroup or amonoid, one can still use the notion of a generating setS{\displaystyle S} ofG{\displaystyle G}.S{\displaystyle S} is a semigroup/monoid generating set ofG{\displaystyle G} ifG{\displaystyle G} is the smallest semigroup/monoid containingS{\displaystyle S}.

The definitions of generating set of a group using finite sums, given above, must be slightly modified when one deals with semigroups or monoids. Indeed, this definition should not use the notion of inverse operation anymore. The setS{\displaystyle S} is said to be a semigroup generating set ofG{\displaystyle G} if each element ofG{\displaystyle G} is a finite sum of elements ofS{\displaystyle S}. Similarly, a setS{\displaystyle S} is said to be a monoid generating set ofG{\displaystyle G} if each non-zero element ofG{\displaystyle G} is a finite sum of elements ofS{\displaystyle S}.

For example, {1} is a monoid generator of the set ofnatural numbersN{\displaystyle \mathbb {N} }. The set {1} is also a semigroup generator of the positive natural numbersN>0{\displaystyle \mathbb {N} _{>0}}. However, the integer 0 can not be expressed as a (non-empty) sum of 1s, thus {1} is not a semigroup generator of the natural numbers.

Similarly, while {1} is a group generator of the set ofintegersZ{\displaystyle \mathbb {Z} }, {1} is not a monoid generator of the set of integers. Indeed, the integer −1 cannot be expressed as a finite sum of 1s.

See also

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Notes

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  1. ^Dummit, David S.; Foote, Richard M. (2004).Abstract algebra (3rd ed.). Wiley. p. 25.ISBN 9780471452348.OCLC 248917264.
  2. ^Dummit & Foote 2004, p. 54
  3. ^Dummit & Foote 2004, p. 26

References

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External links

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