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Garfield's proof of the Pythagorean theorem

From Wikipedia, the free encyclopedia
1876 mathematical proof by the US president
Garfield in 1881

Garfield's proof of the Pythagorean theorem is an original proof of thePythagorean theorem discovered byJames A. Garfield (November 19, 1831 – September 19, 1881), the 20thpresident of the United States. The proof appeared in print in theNew-England Journal of Education (Vol. 3, No.14, April 1, 1876).[1][2] At the time of the publication of the proof Garfield was acongressman fromOhio. He assumed the office of President on March 4, 1881, and served in that position until his death on September 19, 1881, having succumbed to injuries sustained when he wasshot in an assassination in July.[3] Garfield is thus far the only President of the United States to have contributed anything original to mathematics. The proof is nontrivial and, according to the historian of mathematicsWilliam Dunham, "Garfield's is really a very clever proof."[4] The proof appears as the 231st proof inThe Pythagorean Proposition, a compendium of 370 different proofs of the Pythagorean theorem.[5]

The proof

[edit]
Diagram to explain Garfield's proof of the Pythagorean theorem

In the figure,ABC{\displaystyle ABC} is a right-angled triangle with right angle atC{\displaystyle C}. The side-lengths of the triangle area,b,c{\displaystyle a,b,c}. Pythagorean theorem asserts thatc2=a2+b2{\displaystyle c^{2}=a^{2}+b^{2}}.

To prove the theorem, Garfield drew a line throughB{\displaystyle B} perpendicular toAB{\displaystyle AB} and on this line chose a pointD{\displaystyle D} such thatBD=BA{\displaystyle BD=BA}. Then, fromD{\displaystyle D} he dropped a perpendicularDE{\displaystyle DE} upon the extended lineCB{\displaystyle CB}. From the figure, one can easily see that the trianglesABC{\displaystyle ABC} andBDE{\displaystyle BDE} are congruent. SinceAC{\displaystyle AC} andDE{\displaystyle DE} are both perpendicular toCE{\displaystyle CE}, they are parallel and so the quadrilateralACED{\displaystyle ACED} is a trapezoid. The theorem is proved by computing the area of this trapezoid in two different ways.

area of trapezoid ACED=height×average of parallel sides=CE×12(AC+DE)=(a+b)×12(a+b){\displaystyle {\begin{aligned}{\text{area of trapezoid }}ACED&={\text{height}}\times {\text{average of parallel sides}}\\&=CE\times {\tfrac {1}{2}}(AC+DE)=(a+b)\times {\tfrac {1}{2}}(a+b)\end{aligned}}}.
area of trapezoid ACED=area of ΔACB+area of ΔABD+area of ΔBDE=12(a×b)+12(c×c)+12(a×b){\displaystyle {\begin{aligned}{\text{area of trapezoid }}ACED&={\text{area of }}\Delta ACB+{\text{area of }}\Delta ABD+{\text{area of }}\Delta BDE\\&={\tfrac {1}{2}}(a\times b)+{\tfrac {1}{2}}(c\times c)+{\tfrac {1}{2}}(a\times b)\end{aligned}}}

From these one gets

(a+b)×12(a+b)=12(a×b)+12(c×c)+12(a×b){\displaystyle (a+b)\times {\tfrac {1}{2}}(a+b)={\tfrac {1}{2}}(a\times b)+{\tfrac {1}{2}}(c\times c)+{\tfrac {1}{2}}(a\times b)}

which on simplification yields

a2+b2=c2.{\displaystyle a^{2}+b^{2}=c^{2}.}

Relationship to other proofs

[edit]
Common proof of the Pythagorean theorem

Garfield's proof is a variant of one of thealgebraic proofs (pictured at right), but using only half of the diagram. The pictured version observes that the area of the outer square equals the area of the inner square plus four congruent triangles, which is to say

(a+b)×(a+b)=(c×c)+4×12(a×b){\displaystyle (a+b)\times (a+b)=(c\times c)+4\times {\tfrac {1}{2}}(a\times b)}

and simplifies the same way.

References

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  1. ^G., J. A. (1876)."PONS ASINORUM".New England Journal of Education.3 (14): 161.ISSN 2578-4145.JSTOR 44764657.
  2. ^Kolpas, Sid J."Mathematical Treasure: James A. Garfield's Proof of the Pythagorean Theorem".maa.org. Mathematical Association of America. Archived fromthe original on 8 December 2023. Retrieved29 November 2023. (The article appeared in the peer-reviewed online journalConvergence published by the Mathematical Association of America.)
  3. ^Del Arte, Alonso (February 2019)."A future president once published a mathematical proof".medium.com. Retrieved29 November 2023.
  4. ^Dunham, William (1994).The Mathematical Universe: An Alphabetical Journey Through the Great Proofs, Problems, and Personalities. New York: John Wiley & Sons. p. 99.ISBN 0-471-53656-3.
  5. ^Loomis, Elisha Scott (1940).The Pythagorean Proposition (2 ed.). Washington DC: National Council of Teachers of Mathematics. p. 109.ISBN 978-0-87353-036-1. Retrieved28 November 2023.{{cite book}}:ISBN / Date incompatibility (help) (A collection of 370 different proofs of the Pythagorean theorem.)
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