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Dense set

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Subset whose closure is the whole space
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Intopology and related areas ofmathematics, asubsetA of atopological spaceX is said to bedense inX if every point ofX either belongs toA or else is arbitrarily "close" to a member ofA — for instance, therational numbers are a dense subset of thereal numbers because every real number either is a rational number or has a rational number arbitrarily close to it (seeDiophantine approximation). Formally,A{\displaystyle A} is dense inX{\displaystyle X} if the smallestclosed subset ofX{\displaystyle X} containingA{\displaystyle A} isX{\displaystyle X} itself.[1]

Thedensity of a topological spaceX{\displaystyle X} is the leastcardinality of a dense subset ofX.{\displaystyle X.}

Definition

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A subsetA{\displaystyle A} of atopological spaceX{\displaystyle X} is said to be adense subset ofX{\displaystyle X} if any of the following equivalent conditions are satisfied:

  1. The smallestclosed subset ofX{\displaystyle X} containingA{\displaystyle A} isX{\displaystyle X} itself.
  2. Theclosure ofA{\displaystyle A} inX{\displaystyle X} is equal toX.{\displaystyle X.} That is,clXA=X.{\displaystyle \operatorname {cl} _{X}A=X.}
  3. Theinterior of thecomplement ofA{\displaystyle A} is empty. That is,intX(XA)=.{\displaystyle \operatorname {int} _{X}(X\setminus A)=\varnothing .}
  4. Every point inX{\displaystyle X} either belongs toA{\displaystyle A} or is alimit point ofA.{\displaystyle A.}
  5. For everyxX,{\displaystyle x\in X,} everyneighborhoodU{\displaystyle U} ofx{\displaystyle x}intersectsA;{\displaystyle A;} that is,UA.{\displaystyle U\cap A\neq \varnothing .}
  6. A{\displaystyle A} intersects every non-empty open subset ofX.{\displaystyle X.}

and ifB{\displaystyle {\mathcal {B}}} is abasis of open sets for the topology onX{\displaystyle X} then this list can be extended to include:

  1. For everyxX,{\displaystyle x\in X,} everybasicneighborhoodBB{\displaystyle B\in {\mathcal {B}}} ofx{\displaystyle x}intersectsA.{\displaystyle A.}
  2. A{\displaystyle A} intersects every non-emptyBB.{\displaystyle B\in {\mathcal {B}}.}

Density in metric spaces

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An alternative definition of dense set in the case ofmetric spaces is the following. When thetopology ofX{\displaystyle X} is given by ametric, theclosureA¯{\displaystyle {\overline {A}}} ofA{\displaystyle A} inX{\displaystyle X} is theunion ofA{\displaystyle A} and the set of alllimits of sequences of elements inA{\displaystyle A} (itslimit points),A¯=A{limnan:anA for all nN}{\displaystyle {\overline {A}}=A\cup \left\{\lim _{n\to \infty }a_{n}:a_{n}\in A{\text{ for all }}n\in \mathbb {N} \right\}}

ThenA{\displaystyle A} is dense inX{\displaystyle X} ifA¯=X.{\displaystyle {\overline {A}}=X.}

If{Un}{\displaystyle \left\{U_{n}\right\}} is a sequence of denseopen sets in a complete metric space,X,{\displaystyle X,} thenn=1Un{\textstyle \bigcap _{n=1}^{\infty }U_{n}} is also dense inX.{\displaystyle X.} This fact is one of the equivalent forms of theBaire category theorem.

Examples

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Thereal numbers with the usual topology have therational numbers as acountable dense subset which shows that thecardinality of a dense subset of a topological space may be strictly smaller than the cardinality of the space itself. Theirrational numbers are another dense subset which shows that a topological space may have severaldisjoint dense subsets (in particular, two dense subsets may be each other's complements), and they need not even be of the same cardinality. Perhaps even more surprisingly, both the rationals and the irrationals have empty interiors, showing that dense sets need not contain any non-empty open set. The intersection of two dense open subsets of a topological space is again dense and open.[proof 1] Theempty set is a dense subset of itself. But every dense subset of a non-empty space must also be non-empty.

By theWeierstrass approximation theorem, any givencomplex-valuedcontinuous function defined on aclosed interval[a,b]{\displaystyle [a,b]} can beuniformly approximated as closely as desired by apolynomial function. In other words, the polynomial functions are dense in the spaceC[a,b]{\displaystyle C[a,b]} of continuous complex-valued functions on the interval[a,b],{\displaystyle [a,b],} equipped with thesupremum norm.

Everymetric space is dense in itscompletion.

Properties

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Everytopological space is a dense subset of itself. For a setX{\displaystyle X} equipped with thediscrete topology, the whole space is the only dense subset. Every non-empty subset of a setX{\displaystyle X} equipped with thetrivial topology is dense, and every topology for which every non-empty subset is dense must be trivial.

Denseness istransitive: Given three subsetsA,B{\displaystyle A,B} andC{\displaystyle C} of a topological spaceX{\displaystyle X} withABCX{\displaystyle A\subseteq B\subseteq C\subseteq X} such thatA{\displaystyle A} is dense inB{\displaystyle B} andB{\displaystyle B} is dense inC{\displaystyle C} (in the respectivesubspace topology) thenA{\displaystyle A} is also dense inC.{\displaystyle C.}

Theimage of a dense subset under asurjectivecontinuous function is again dense. The density of a topological space (the least of thecardinalities of its dense subsets) is atopological invariant.

A topological space with aconnected dense subset is necessarily connected itself.

Continuous functions intoHausdorff spaces are determined by their values on dense subsets: if two continuous functionsf,g:XY{\displaystyle f,g:X\to Y} into aHausdorff spaceY{\displaystyle Y} agree on a dense subset ofX{\displaystyle X} then they agree on all ofX.{\displaystyle X.}

For metric spaces there are universal spaces, into which all spaces of given density can beembedded: a metric space of densityα{\displaystyle \alpha } is isometric to a subspace ofC([0,1]α,R),{\displaystyle C\left([0,1]^{\alpha },\mathbb {R} \right),} the space of real continuous functions on theproduct ofα{\displaystyle \alpha } copies of theunit interval.[2]

Related notions

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A pointx{\displaystyle x} of a subsetA{\displaystyle A} of a topological spaceX{\displaystyle X} is called alimit point ofA{\displaystyle A} (inX{\displaystyle X}) if every neighbourhood ofx{\displaystyle x} also contains a point ofA{\displaystyle A} other thanx{\displaystyle x} itself, and anisolated point ofA{\displaystyle A} otherwise. A subset without isolated points is said to bedense-in-itself.

A subsetA{\displaystyle A} of a topological spaceX{\displaystyle X} is callednowhere dense (inX{\displaystyle X}) if there is no neighborhood inX{\displaystyle X} on whichA{\displaystyle A} is dense. Equivalently, a subset of a topological space is nowhere denseif and only if the interior of its closure is empty. The interior of the complement of a nowhere dense set is always dense. The complement of a closed nowhere dense set is a dense open set. Given a topological spaceX,{\displaystyle X,} a subsetA{\displaystyle A} ofX{\displaystyle X} that can be expressed as the union of countably many nowhere dense subsets ofX{\displaystyle X} is calledmeagre. The rational numbers, while dense in the real numbers, are meagre as a subset of the reals.

A topological space with a countable dense subset is calledseparable. A topological space is aBaire space if and only if the intersection of countably many dense open sets is always dense. A topological space is calledresolvable if it is the union of two disjoint dense subsets. More generally, a topological space is called κ-resolvable for acardinal κ if it contains κ pairwise disjoint dense sets.

Anembedding of a topological spaceX{\displaystyle X} as a dense subset of acompact space is called acompactification ofX.{\displaystyle X.}

Alinear operator betweentopological vector spacesX{\displaystyle X} andY{\displaystyle Y} is said to bedensely defined if itsdomain is a dense subset ofX{\displaystyle X} and if itsrange is contained withinY.{\displaystyle Y.} See alsoContinuous linear extension.

A topological spaceX{\displaystyle X} ishyperconnected if and only if every nonempty open set is dense inX.{\displaystyle X.} A topological space issubmaximal if and only if every dense subset is open.

If(X,dX){\displaystyle \left(X,d_{X}\right)} is a metric space, then a non-empty subsetY{\displaystyle Y} is said to beε{\displaystyle \varepsilon }-dense ifxX,yY such that dX(x,y)ε.{\displaystyle \forall x\in X,\;\exists y\in Y{\text{ such that }}d_{X}(x,y)\leq \varepsilon .}

One can then show thatD{\displaystyle D} is dense in(X,dX){\displaystyle \left(X,d_{X}\right)} if and only if it is ε-dense for everyε>0.{\displaystyle \varepsilon >0.}

See also

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References

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  1. ^Steen, L. A.; Seebach, J. A. (1995),Counterexamples in Topology, Dover,ISBN 0-486-68735-X
  2. ^Kleiber, Martin; Pervin, William J. (1969)."A generalized Banach-Mazur theorem".Bull. Austral. Math. Soc.1 (2):169–173.doi:10.1017/S0004972700041411.

proofs

  1. ^Suppose thatA{\displaystyle A} andB{\displaystyle B} are dense open subset of a topological spaceX.{\displaystyle X.} IfX={\displaystyle X=\varnothing } then the conclusion that the open setAB{\displaystyle A\cap B} is dense inX{\displaystyle X} is immediate, so assume otherwise. LetU{\displaystyle U} is a non-empty open subset ofX,{\displaystyle X,} so it remains to show thatU(AB){\displaystyle U\cap (A\cap B)} is also not empty. BecauseA{\displaystyle A} is dense inX{\displaystyle X} andU{\displaystyle U} is a non-empty open subset ofX,{\displaystyle X,} their intersectionUA{\displaystyle U\cap A} is not empty. Similarly, becauseUA{\displaystyle U\cap A} is a non-empty open subset ofX{\displaystyle X} andB{\displaystyle B} is dense inX,{\displaystyle X,} their intersectionUAB{\displaystyle U\cap A\cap B} is not empty.{\displaystyle \blacksquare }

General references

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