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Conformal welding

From Wikipedia, the free encyclopedia
Process in geometric function theory

Inmathematics,conformal welding (sewing orgluing) is a process ingeometric function theory for producing aRiemann surface by joining together two Riemann surfaces, each with a disk removed, along their boundary circles. This problem can be reduced to that of finding univalent holomorphic mapsf,g of theunit disk and its complement into the extended complex plane, both admitting continuous extensions to the closure of their domains, such that the images are complementary Jordan domains and such that on the unit circle they differ by a givenquasisymmetric homeomorphism. Several proofs are known using a variety of techniques, including theBeltrami equation,[1] theHilbert transform on the circle[2] and elementary approximation techniques.[3]Sharon & Mumford (2006) describe the first two methods of conformal welding as well as providing numerical computations and applications to the analysis of shapes in the plane.

Welding using the Beltrami equation

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This method was first proposed byPfluger (1960).

Iff is a diffeomorphism of the circle, theAlexander extension gives a way of extendingf to a diffeomorphism of the unit diskD:

F(r,θ)=rexp[iψ(r)g(θ)+i(1ψ(r))θ],{\displaystyle \displaystyle {F(r,\theta )=r\exp[i\psi (r)g(\theta )+i(1-\psi (r))\theta ],}}

where ψ is a smooth function with values in [0,1], equal to 0 near 0 and 1 near 1, and

f(eiθ)=eig(θ),{\displaystyle \displaystyle {f(e^{i\theta })=e^{ig(\theta )},}}

withg(θ + 2π) =g(θ) + 2π.

The extensionF can be continued to any larger disk |z| <R withR > 1. Accordingly in the unit disc

μ<1,μ(z)=Fz¯/Fz.{\displaystyle \displaystyle {\|\mu \|_{\infty }<1,\,\,\,\mu (z)=F_{\overline {z}}/F_{z}.}}

Now extend μ to a Beltrami coefficient on the whole ofC by setting it equal to 0 for |z| ≥ 1. LetG be the corresponding solution of the Beltrami equation:

Gz¯=μGz.{\displaystyle \displaystyle {G_{\overline {z}}=\mu G_{z}.}}

LetF1(z) =G{\displaystyle \circ }F−1(z) for |z| ≤ 1 andF2(z) =G (z) for |z| ≥ 1. ThusF1 andF2 are univalent holomorphic maps of |z| < 1 and |z| > 1 onto the inside and outside of a Jordan curve. They extend continuously to homeomorphismsfi of the unit circle onto the Jordan curve on the boundary. By construction they satisfy theconformal welding condition:

f=f11f2.{\displaystyle \displaystyle {f=f_{1}^{-1}\circ f_{2}.}}

Welding using the Hilbert transform on the circle

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The use of the Hilbert transform to establish conformal welding was first suggested by the Georgian mathematicians D.G. Mandzhavidze and B.V. Khvedelidze in 1958. A detailed account was given at the same time by F.D. Gakhov and presented in his classic monograph (Gakhov (1990)).

Leten(θ) =einθ be the standardorthonormal basis of L2(T). Let H2(T) beHardy space, the closed subspace spanned by theen withn ≥ 0. LetP be the orthogonal projection onto Hardy space and setT = 2P -I. The operatorH =iT is theHilbert transform on the circle and can be written as asingular integral operator.

Given a diffeomorphismf of the unit circle, the task is to determine two univalent holomorphic functions

f(z)=a0+a1z+a2z2+,f+(z)=z+b1z1+b2z2+,{\displaystyle \displaystyle {f_{-}(z)=a_{0}+a_{1}z+a_{2}z^{2}+\cdots ,\,\,\,\,\,f_{+}(z)=z+b_{1}z^{-1}+b_{2}z^{-2}+\cdots ,}}

defined in |z| < 1 and |z| > 1 and both extending smoothly to the unit circle, mapping onto a Jordan domain and its complement, such that

f(eiθ)=f+(f(eiθ)).{\displaystyle \displaystyle {f_{-}(e^{i\theta })=f_{+}(f(e^{i\theta })).}}

LetF be the restriction off+ to the unit circle. Then

TF=F+2eiθ{\displaystyle \displaystyle {TF=-F+2e^{i\theta }}}

and

TFf=Ff.{\displaystyle \displaystyle {TF\circ f=F\circ f.}}

Hence

T(Ff)f1T(F)=2F2eiθ.{\displaystyle \displaystyle {T(F\circ f)\circ f^{-1}-T(F)=2F-2e^{i\theta }.}}

IfV(f) denotes the bounded invertible operator on L2 induced by the diffeomorphismf, then the operator

Kf=V(f)PV(f)1P{\displaystyle \displaystyle {K_{f}=V(f)PV(f)^{-1}-P}}

is compact, indeed it is given by an operator with smooth kernel becauseP andT are given by singular integral operators. The equation above then reduces to

(IKf)F=eiθ.{\displaystyle \displaystyle {(I-K_{f})F=e^{i\theta }.}}

The operatorIKf is aFredholm operator of index zero. It has zero kernel and is therefore invertible. In fact an element in the kernel would consist of a pair of holomorphic functions onD andDc which have smooth boundary values on the circle related byf. Since theholomorphic function onDc vanishes at ∞, the positive powers of this pair also provide solutions, which are linearly independent, contradicting the fact thatIKf is a Fredholm operator. The above equation therefore has a unique solutionF which is smooth and from whichf± can be reconstructed by reversing the steps above. Indeed, by looking at the equation satisfied by the logarithm of the derivative ofF, it follows thatF has nowhere vanishing derivative on the unit circle. MoreoverF is one-to-one on the circle since if it assumes the valuea at different pointsz1 andz2 then the logarithm ofR(z) = (F(z) −a)/(z -z1)(zz2) would satisfy anintegral equation known to have no non-zero solutions. Given these properties on the unit circle, the required properties off± then follow from theargument principle.[4]

Notes

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  1. ^Lehto 1987
  2. ^Sharon & Mumford 2006
  3. ^Lehto & Virtanen 1973
  4. ^See:

References

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