Aneutronic fusion is any form offusion power in which very little of theenergy released is carried byneutrons. While the lowest-thresholdnuclear fusion reactions release up to 80% of their energy in the form ofneutrons, aneutronic reactions release energy in the form ofcharged particles, typicallyprotons oralpha particles. Successful aneutronic fusion would greatly reduce problems associated withneutron radiation such as damagingionizing radiation,neutron activation, reactor maintenance, and requirements for biological shielding, remote handling and safety.
Since it is simpler to convert the energy of charged particles into electrical power than it is to convert energy from uncharged particles, an aneutronic reaction would be attractive for power systems. Some proponents see a potential for dramatic cost reductions by converting energy directly to electricity, as well as in eliminating the radiation from neutrons, which are difficult to shield against.[1][2] However, the conditions required to harness aneutronic fusion are much more extreme than those required fordeuterium–tritium (D–T) fusion such as atITER.
The first experiments in the field started in 1939, and serious efforts have been continual since the early 1950s.
An early supporter wasRichard F. Post atLawrence Livermore. He proposed to capture thekinetic energy of charged particles as they were exhausted from a fusion reactor and convert this into voltage to drive current.[3] Post helped develop the theoretical underpinnings of direct conversion, later demonstrated by Barr and Moir. They demonstrated a 48 percent energy capture efficiency on theTandem Mirror Experiment in 1981.[4]
Polywell fusion was pioneered by the lateRobert W. Bussard in 1995 and funded by theUS Navy. Polywell usesinertial electrostatic confinement. He founded EMC2 to continue polywell research.[5][6]
A picosecond pulse of a 10-terawatt laser produced hydrogen–boron aneutronic fusions for a Russian team in 2005.[7] However, the number of the resulting α particles (around 103 per laser pulse) was low.
In 2006, theZ-machine atSandia National Laboratory, az-pinch device, reached 2 billion kelvins and 300 keV.[8]
In 2011,Lawrenceville Plasma Physics published initial results and outlined a theory and experimental program for aneutronic fusion with thedense plasma focus (DPF).[9][10] The effort was initially funded by NASA'sJet Propulsion Laboratory.[11] Support for other DPF aneutronic fusion investigations came from theAir Force Research Laboratory.[12]
A French research team fused protons and boron-11 nuclei using a laser-accelerated proton beam and high-intensity laser pulse.[13] In October 2013 they reported an estimated 80 million fusion reactions during a 1.5 nanosecond laser pulse.[13]
In 2016, a team at the ShanghaiChinese Academy of Sciences produced a laser pulse of 5.3 petawatts with theSuperintense Ultrafast Laser Facility (SULF) and expected to reach 10 petawatts with the same equipment.[14]
In 2021,TAE Technologiesfield-reversed configuration announced that its Norman device was regularly producing a stable plasma at temperatures over 50 million degrees.[15]
In 2021, a Russian team reported experimental results in a miniature device with electrodynamic (oscillatory)plasma confinement. It used a ~1–2 J nanosecond vacuum discharge with a virtual cathode. Its field accelerates boron ions and protons to ~ 100–300 keV under oscillating ions' collisions. α-particles of about5×104/4π (~ 10 α-particles/ns) were obtained during the 4 μs of applied voltage.[16]
Australianspin-off company HB11 Energy was created in September 2019.[17] In 2022, they claimed to be the first commercial company to demonstrate fusion.[18][19]
Fusion reactions can be categorized according to their neutronicity: the fraction of the fusion energy released as energetic neutrons. The State ofNew Jersey defined an aneutronic reaction as one in which neutrons carry no more than 1% of the total released energy,[20] although many papers on the subject[21] include reactions that do not meet this criterion.
TheCoulomb barrier is the minimum energy required for thenuclei in a fusion reaction to overcome their mutualelectrostatic repulsion. Repulsive force between a particle with chargeZ1 and one withZ2 is proportional to(Z1 ×Z2) /r2, wherer is the distance between them. The Coulomb barrier facing a pair of reacting, charged particles depends both on total charge and on how equally those charges are distributed; the barrier is lowest when a low-Z particle reacts with a high-Z one and highest when the reactants are of roughly equal charge. Barrier energy is thus minimized for those ions with the fewestprotons.
Once the nuclear potential wells of the two reacting particles are within two proton radii of each other, the two can begin attracting one another vianuclear force. Because this interaction is much stronger than electromagnetic interaction, the particles will be drawn together despite the ongoing electrical repulsion, releasing nuclear energy. Nuclear force is a very short-range force, though, so it is a little oversimplified to say it increases with the number ofnucleons. The statement is true when describing volume energy or surface energy of a nucleus, less true when addressing Coulomb energy, and does not speak to proton/neutron balance at all. Once reactants have gone past the Coulomb barrier, they're into a world dominated by a force that does not behave like electromagnetism.
In most fusion concepts, the energy needed to overcome the Coulomb barrier is provided by collisions with other fuel ions. In a thermalized fluid like a plasma, thetemperature corresponds to an energy spectrum according to theMaxwell–Boltzmann distribution. Gases in this state have some particles with high energy even if the average energy is much lower. Fusion devices rely on this distribution; even at bulk temperatures far below the Coulomb barrier energy, the energy released by the reactions is great enough that capturing some of that can supply sufficient high-energy ions to keep the reaction going.
Thus, steady operation of the reactor is based on a balance between the rate that energy is added to the fuel by fusion reactions and the rate energy is lost to the surroundings. This concept is best expressed as thefusion triple product, the product of the temperature, density and "confinement time", the amount of time energy remains in the fuel before escaping to the environment. The product of temperature and density gives the reaction rate for any given fuel. The rate of reaction is proportional to thenuclear cross section (σ).[1][22]
Any given device can sustain some maximum plasma pressure. An efficient device would continuously operate near this maximum. Given this pressure, the largest fusion output is obtained when the temperature is such thatσv/T2 is a maximum. This is also the temperature at which the value of the triple productnTτ required for ignition is a minimum, since that required value is inversely proportional toσv/T2. A plasma is "ignited" if the fusion reactions produce enough power to maintain the temperature without external heating.
Because the Coulomb barrier is proportional to the product of proton counts (Z1 × Z2) of the two reactants, varieties of heavy hydrogen,deuterium andtritium (D–T), give the fuel with the lowest total Coulomb barrier. All other potential fuels have higher Coulomb barriers, and thus require higher operational temperatures. Additionally, D–T fuels have the highest nuclear cross-sections, which means the reaction rates are higher than any other fuel. This makesD–T fusion the easiest to achieve.
Comparing the potential of other fuels to the D–T reaction: The table below shows the ignition temperature and cross-section for three of the candidate aneutronic reactions, compared to D–T:
Reaction | Ignition T [keV] | Cross-section σv/T2 [m3/s/keV2] |
---|---|---|
2 1D –3 1T | 13.6 | 1.24×10−24 |
2 1D –3 2He | 58 | 2.24×10−26 |
p+–6 3Li | 66 | 1.46×10−27 |
p+–11 5B | 123 | 3.01×10−27 |
The easiest to ignite of the aneutronic reactions, D–3He, has an ignition temperature over four times as high as that of the D–T reaction, and correspondingly lower cross-sections, while the p–11B reaction is nearly ten times more difficult to ignite.
Several fusion reactions produce no neutrons on any of their branches. Those with the largestcross sections are:
Isotopes | Reaction | ||||||||
---|---|---|---|---|---|---|---|---|---|
2 1D –3 2He | 2D | + | 3He | → | 4He | + | 1p | + 18.3MeV | |
2 1D –6 3Li | 2D | + | 6Li | → | 2 | 4He | + 22.4 MeV | ||
p–6 3Li | 1p | + | 6Li | → | 4He | + | 3He | + 4.0 MeV | |
3 2He –6 3Li | 3He | + | 6Li | → | 2 | 4He | + | 1p | + 16.9 MeV |
3 2He –3 2He | 3He | + | 3He | → | 4He | + | 21p | + 12.86 MeV | |
p–7 3Li | 1p | + | 7Li | → | 2 | 4He | + 17.2 MeV | ||
p–11 5B | 1p | + | 11B | → | 3 | 4He | + 8.7 MeV | ||
p–15 7N | 1p | + | 15N | → | 12C | + | 4He | + 5.0 MeV |
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The3He–D reaction has been studied as an alternative fusion plasma because it has the lowest energy threshold.
The p–6Li,3He–6Li, and3He–3He reaction rates are not particularly high in a thermal plasma. When treated as a chain, however, they offer the possibility of enhanced reactivity due to anon-thermal distribution. The product3He from the p–6Li reaction could participate in the second reaction before thermalizing, and the product p from3He–6Li could participate in the former before thermalizing. Detailed analyses, however, do not show sufficient reactivity enhancement to overcome the inherently low cross section.[citation needed]
The3He reaction suffers from a3He availability problem.3He occurs in only minuscule amounts on Earth, so it would either have to be bred from neutron reactions (counteracting the potential advantage of aneutronic fusion)[clarification needed] or mined from extraterrestrial sources.
The amount of3He needed for large-scale applications can also be described in terms of total consumption: according to theUS Energy Information Administration, "Electricity consumption by 107 million U.S. households in 2001 totalled 1,140 billion kW·h" (1.14×1015 W·h). Again assuming 100% conversion efficiency, 6.7 tonnes per year of3He would be required for that segment of the energy demand of the United States, 15 to 20 tonnes per year given a more realistic end-to-end conversion efficiency. Extracting that amount of pure3He would entail processing 2 billion tonnes of lunar material per year, even assuming a recovery rate of 100%.[citation needed]
In 2022,Helion Energy claimed that their 7th fusion prototype (Polaris; fully funded and under construction as of September 2022) will demonstrate "net electricity from fusion", and will demonstrate "helium-3 production through deuterium–deuterium fusion" by means of a "patented high-efficiency closed-fuel cycle".[23]
Although the deuterium reactions (deuterium +3He and deuterium +6lithium) do not in themselves release neutrons, in a fusion reactor the plasma would also produce D–D side reactions that result in reaction product of3He plus a neutron. Although neutron production can be minimized by running a plasma reaction hot and deuterium-lean, the fraction of energy released as neutrons is probably several percent, so that these fuel cycles, although neutron-poor, do not meet the 1% threshold. See3He. The D–3He reaction also suffers from the3He fuel availability problem, as discussed above.
Fusion reactions involving lithium are well studied due to the use of lithium for breeding tritium inthermonuclear weapons. They are intermediate in ignition difficulty between the reactions involving lower atomic-number species, H and He, and the11B reaction.
The p–7Li reaction, although highly energetic, releases neutrons because of the high cross section for the alternate neutron-producing reaction1p +7Li →7Be + n[24]
Many studies of aneutronic fusion concentrate on the p–11B reaction,[25][26] which uses easily available fuel. The fusion of the boron nucleus with a proton produces energetic alpha particles (helium nuclei).
Since igniting the p–11B reaction is much more difficult than D–T, alternatives to the usualtokamak fusion reactors are usually proposed, such asinertial confinement fusion.[27] One proposed method uses one laser to create a boron-11plasma and another to create a stream of protons that smash into the plasma. The proton beam produces a tenfold increase of fusion because protons and boron nuclei collide directly. Earlier methods used a solid boron target, "protected" by its electrons, which reduced the fusion rate.[28] Experiments suggest that a petawatt-scale laser pulse could launch an 'avalanche' fusion reaction,[27][29] although this remains controversial.[30] The plasma lasts about onenanosecond, requiring thepicosecond pulse of protons to be precisely synchronized. Unlike conventional methods, this approach does not require a magnetically confined plasma. The proton beam is preceded by an electron beam, generated by the same laser, that strips electrons in the boron plasma, increasing the protons' chance to collide with the boron nuclei and fuse.[28]
Calculations show that at least 0.1% of the reactions in a thermal p–11B plasma produce neutrons, although their energy accounts for less than 0.2% of the total energy released.[31]
These neutrons come primarily from the reaction:[32]
The reaction itself produces only 157 keV, but the neutron carries a large fraction of the alpha energy, close toEfusion/3 =2.9 MeV. Another significant source of neutrons is:
These neutrons are less energetic, with an energy comparable to the fuel temperature. In addition,11C itself is radioactive, but quickly decays to11B with a half life of only 20 minutes.
Since these reactions involve the reactants and products of the primary reaction, it is difficult to lower the neutron production by a significant fraction. A clever magnetic confinement scheme could in principle suppress the first reaction by extracting the alphas as they are created, but then their energy would not be available to keep the plasma hot. The second reaction could in principle be suppressed relative to the desired fusion by removing the high energy tail of the ion distribution, but this would probably be prohibited by the power required to prevent the distribution from thermalizing.
In addition to neutrons, large quantities of hardX-rays are produced bybremsstrahlung, and 4, 12, and 16 MeVgamma rays are produced by the fusion reaction
with a branching probability relative to the primary fusion reaction of about 10−4.[note 1]
The hydrogen must beisotopically pure and the influx of impurities into the plasma must be controlled to prevent neutron-producing side reactions such as:
The shielding design reduces the occupational dose of both neutron and gamma radiation to a negligible level. The primary components are water (to moderate the fast neutrons), boron (to absorb the moderated neutrons) and metal (to absorb X-rays). The total thickness is estimated to be about one meter, mostly water.[33]
HB11 Energy uses thousands of merged diode-pumped lasers. This allows mass-produced and less expensive kilojoule lasers to deliver megajoules to a target.[34] The resulting nanosecond and picosecond two-pulse laser system provides next-generation input. The approach uses pulsed power (shots). Fuel pellets burn at a rate of about 1 per second. The energy released drives a conventional steam cycle generator.[34]
Laser power has been increasing at about 103x/decade amid falling costs. Advancements include:[34]
Aneutronic fusion produces energy in the form of charged particles instead ofneutrons. This means that energy from aneutronic fusion could be captured directly instead of blasting neutrons at a target to boil something. Direct conversion can be either inductive, based on changes in magnetic fields, electrostatic, based on pitting charged particles against an electric field, or photoelectric, in which light energy is captured in a pulsed mode.[35]
Electrostatic conversion uses the motion of charged particles to createvoltage that produces current–electrical power. It is the reverse of phenomena that use a voltage to put a particle in motion. It has been described as alinear accelerator running backwards.[36]
Aneutronic fusion loses much of its energy as light. This energy results from the acceleration and deceleration of charged particles. These speed changes can be caused bybremsstrahlung radiation,cyclotron radiation,synchrotron radiation, or electric field interactions. The radiation can be estimated using theLarmor formula and comes in the X-ray, UV, visible, and IR spectra. Some of the energy radiated as X-rays may be converted directly to electricity. Because of thephotoelectric effect, X-rays passing through an array of conducting foils transfer some of their energy to electrons, which can then be captured electrostatically. Since X-rays can go through far greater material thickness than electrons, hundreds or thousands of layers are needed to absorb them.[37]
Many challenges confront the commercialization of aneutronic fusion.
The large majority of fusion research has gone toward D–T fusion, which is the easiest to achieve. Fusion experiments typically usedeuterium–deuterium fusion (D–D) because deuterium is cheap and easy to handle, being non-radioactive. Experimenting with D–T fusion is more difficult because tritium is expensive and radioactive, requiring additional environmental protection and safety measures.
The combination of lower cross-section and higher loss rates in D–3He fusion is offset to a degree because the reactants are mainly charged particles that deposit their energy in the plasma. This combination of offsetting features demands an operating temperature about four times that of a D–T system. However, due to the high loss rates and consequent rapid cycling of energy, the confinement time of a working reactor needs to be about fifty times higher than D–T, and the energy density about 80 times higher. This requires significant advances in plasma physics.[38]
Proton–boron fusion requires ion energies, and thus plasma temperatures, some nine times higher than those for D–T fusion. For any given density of the reacting nuclei, the reaction rate for proton-boron achieves its peak rate at around 600 keV (6.6 billion degrees Celsius or 6.6gigakelvins)[39] while D–T has a peak at around 66 keV (765 million degrees Celsius, or 0.765 gigakelvin). For pressure-limited confinement concepts, optimumoperating temperatures are about 5 times lower, but the ratio is still roughly ten-to-one.
The peak reaction rate of p–11B is only one third that for D–T, requiring better plasma confinement. Confinement is usually characterized by the time τ the energy is retained so that the power released exceeds that required to heat the plasma. Various requirements can be derived, most commonly the Lawson criterion, the product of the density,nτ, and the product with the pressurenTτ. Thenτ required for p–11B is 45 times higher than that for D–T. ThenTτ required is 500 times higher.[note 2] Since the confinement properties of conventional fusion approaches, such as thetokamak andlaser pellet fusion are marginal, most aneutronic proposals use radically different confinement concepts.
In most fusion plasmas, bremsstrahlung radiation is a major energy loss channel. (See alsobremsstrahlung losses in quasineutral, isotropic plasmas.) For the p–11B reaction, some calculations indicate that the bremsstrahlung power will be at least 1.74 times larger than the fusion power. The corresponding ratio for the3He–3He reaction is only slightly more favorable at 1.39. This is not applicable to non-neutral plasmas, and different in anisotropic plasmas.
In conventional reactor designs, whether based onmagnetic orinertial confinement, the bremsstrahlung can easily escape the plasma and is considered a pure energy loss term. The outlook would be more favorable if the plasma could reabsorb the radiation. Absorption occurs primarily viaThomson scattering on theelectrons,[40] which has a total cross section of σT = 6.65×10−29 m2. In a 50–50 D–T mixture this corresponds to a range of6.3 g/cm2.[41] This is considerably higher than the Lawson criterion ofρR > 1 g/cm2, which is already difficult to attain, but might be achievable in inertial confinement systems.[42]
Inmegatesla magnetic fields aquantum mechanical effect might suppress energy transfer from the ions to the electrons.[43] According to one calculation,[44] bremsstrahlung losses could be reduced to half the fusion power or less. In a strong magnetic fieldcyclotron radiation is even larger than the bremsstrahlung. In a megatesla field, an electron would lose its energy to cyclotron radiation in a few picoseconds if the radiation could escape. However, in a sufficiently dense plasma (ne >2.5×1030 m−3, a density greater than that of a solid[45]), thecyclotron frequency is less than twice theplasma frequency. In this well-known case, the cyclotron radiation is trapped inside the plasmoid and cannot escape, except from a very thin surface layer.
While megatesla fields have not yet been achieved, fields of 0.3 megatesla have been produced with high intensity lasers,[46] and fields of 0.02–0.04 megatesla have been observed with thedense plasma focus device.[47][48]
At much higher densities (ne >6.7×10−34 m−3), the electrons will beFermi degenerate, which suppresses bremsstrahlung losses, both directly and by reducing energy transfer from the ions to the electrons.[49] If necessary conditions can be attained, net energy production from p–11B or D–3He fuel may be possible. The probability of a feasible reactor based solely on this effect remains low, however, because thegain is predicted to be less than 20, while more than 200 is usually considered to be necessary.
In every published fusion power plant design, the part of the plant that produces the fusion reactions is much more expensive than the part that converts the nuclear power to electricity. In that case, as indeed in most power systems, power density is an important characteristic.[note 3] Doubling power density at least halves the cost of electricity. In addition, the confinement time required depends on the power density.
It is, however, not trivial to compare the power density produced by different fusion fuel cycles. The case most favorable to p–11B relative to D–T fuel is a (hypothetical) confinement device that only works well at ion temperatures above about 400 keV, in which the reaction rate parameterσv is equal for the two fuels, and that runs with low electron temperature. p–11B does not require as long a confinement time because the energy of its charged products is two and a half times higher than that for D–T. However, relaxing these assumptions, for example by considering hot electrons, by allowing the D–T reaction to run at a lower temperature or by including the energy of the neutrons in the calculation shifts the power density advantage to D–T.
The most common assumption is to compare power densities at the same pressure, choosing the ion temperature for each reaction to maximize power density, and with the electron temperature equal to the ion temperature. Although confinement schemes can be and sometimes are limited by other factors, most well-investigated schemes have some kind of pressure limit. Under these assumptions, the power density for p–11B is about2100 times smaller than that for D–T. Using cold electrons lowers the ratio to about 700. These numbers are another indication that aneutronic fusion power is not possible with mainline confinement concepts.