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Almost open map

From Wikipedia, the free encyclopedia
Map that satisfies a condition similar to that of being an open map
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Infunctional analysis and related areas ofmathematics, analmost open map betweentopological spaces is amap that satisfies a condition similar to, but weaker than, the condition of being anopen map. As described below, for certain broad categories oftopological vector spaces,allsurjective linear operators are necessarily almost open.

Definitions

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Given a surjective mapf:XY,{\displaystyle f:X\to Y,} a pointxX{\displaystyle x\in X} is called apoint of openness forf{\displaystyle f} andf{\displaystyle f} is said to beopen atx{\displaystyle x} (oran open map atx{\displaystyle x}) if for every open neighborhoodU{\displaystyle U} ofx,{\displaystyle x,}f(U){\displaystyle f(U)} is aneighborhood off(x){\displaystyle f(x)} inY{\displaystyle Y} (note that the neighborhoodf(U){\displaystyle f(U)} is not required to be anopen neighborhood).

A surjective map is called anopen map if it is open at every point of its domain, while it is called analmost open map if each of itsfibers has some point of openness. Explicitly, a surjective mapf:XY{\displaystyle f:X\to Y} is said to bealmost open if for everyyY,{\displaystyle y\in Y,} there exists somexf1(y){\displaystyle x\in f^{-1}(y)} such thatf{\displaystyle f} is open atx.{\displaystyle x.} Every almost open surjection is necessarily apseudo-open map (introduced byAlexander Arhangelskii in 1963), which by definition means that for everyyY{\displaystyle y\in Y} and every neighborhoodU{\displaystyle U} off1(y){\displaystyle f^{-1}(y)} (that is,f1(y)IntXU{\displaystyle f^{-1}(y)\subseteq \operatorname {Int} _{X}U}),f(U){\displaystyle f(U)} is necessarily a neighborhood ofy.{\displaystyle y.}

Almost open linear map

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A linear mapT:XY{\displaystyle T:X\to Y} between twotopological vector spaces (TVSs) is called anearly open linear map or analmost open linear map if for any neighborhoodU{\displaystyle U} of0{\displaystyle 0} inX,{\displaystyle X,} the closure ofT(U){\displaystyle T(U)} inY{\displaystyle Y} is a neighborhood of the origin. Importantly, some authors use a different definition of "almost open map" in which they instead require that the linear mapT{\displaystyle T} satisfy: for any neighborhoodU{\displaystyle U} of0{\displaystyle 0} inX,{\displaystyle X,} the closure ofT(U){\displaystyle T(U)} inT(X){\displaystyle T(X)} (rather than inY{\displaystyle Y}) is a neighborhood of the origin; this article will not use this definition.[1]

If a linear mapT:XY{\displaystyle T:X\to Y} is almost open then becauseT(X){\displaystyle T(X)} is a vector subspace ofY{\displaystyle Y} that contains a neighborhood of the origin inY,{\displaystyle Y,} the mapT:XY{\displaystyle T:X\to Y} is necessarilysurjective. For this reason many authors require surjectivity as part of the definition of "almost open".

IfT:XY{\displaystyle T:X\to Y} is a bijective linear operator, thenT{\displaystyle T} is almost open if and only ifT1{\displaystyle T^{-1}} isalmost continuous.[1]

Relationship to open maps

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Every surjectiveopen map is an almost open map but in general, the converse is not necessarily true. If a surjectionf:(X,τ)(Y,σ){\displaystyle f:(X,\tau )\to (Y,\sigma )} is an almost open map then it will be an open map if it satisfies the following condition (a condition that doesnot depend in any way onY{\displaystyle Y}'s topologyσ{\displaystyle \sigma }):

wheneverm,nX{\displaystyle m,n\in X} belong to the samefiber off{\displaystyle f} (that is,f(m)=f(n){\displaystyle f(m)=f(n)}) then for every neighborhoodUτ{\displaystyle U\in \tau } ofm,{\displaystyle m,} there exists some neighborhoodVτ{\displaystyle V\in \tau } ofn{\displaystyle n} such thatF(V)F(U).{\displaystyle F(V)\subseteq F(U).}

If the map is continuous then the above condition is also necessary for the map to be open. That is, iff:XY{\displaystyle f:X\to Y} is a continuous surjection then it is an open map if and only if it is almost open and it satisfies the above condition.

Open mapping theorems

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Main article:open mapping theorem (functional analysis)
Theorem:[1] IfT:XY{\displaystyle T:X\to Y} is a surjective linear operator from alocally convex spaceX{\displaystyle X} onto abarrelled spaceY{\displaystyle Y} thenT{\displaystyle T} isalmost open.
Theorem:[1] IfT:XY{\displaystyle T:X\to Y} is a surjective linear operator from a TVSX{\displaystyle X} onto aBaire spaceY{\displaystyle Y} thenT{\displaystyle T} isalmost open.

The two theorems above donot require the surjective linear map to satisfyany topological conditions.

Theorem:[1] IfX{\displaystyle X} is a completepseudometrizable TVS,Y{\displaystyle Y} is a Hausdorff TVS, andT:XY{\displaystyle T:X\to Y} is a closed andalmost open linear surjection, thenT{\displaystyle T} is an open map.
Theorem:[1] SupposeT:XY{\displaystyle T:X\to Y} is a continuous linear operator from a completepseudometrizable TVSX{\displaystyle X} into a Hausdorff TVSY.{\displaystyle Y.} If the image ofT{\displaystyle T} is non-meager inY{\displaystyle Y} thenT:XY{\displaystyle T:X\to Y} is a surjective open map andY{\displaystyle Y} is a complete metrizable space.

See also

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References

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  1. ^abcdefNarici & Beckenstein 2011, pp. 466–468.

Bibliography

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