Inmathematics, analgebraic extension is afield extensionL/K such that every element of the largerfieldL isalgebraic over the smaller fieldK; that is, every element ofL is a root of a non-zeropolynomial with coefficients inK.[1][2] A field extension that is not algebraic, is said to betranscendental, and must containtranscendental elements, that is, elements that are not algebraic.[3][4]
The algebraic extensions of the field of therational numbers are calledalgebraic number fields and are the main objects of study ofalgebraic number theory. Another example of a common algebraic extension is the extension of thereal numbers by thecomplex numbers.
All transcendental extensions are of infinitedegree. This in turn implies that all finite extensions are algebraic.[5] Theconverse is not true however: there are infinite extensions which are algebraic.[6] For instance, the field of allalgebraic numbers is an infinite algebraic extension of the rational numbers.[7]
LetE be an extension field ofK, anda ∈E. The smallest subfield ofE that containsK anda is commonly denoted Ifa is algebraic overK, then the elements ofK(a) can be expressed as polynomials ina with coefficients inK; that is,, the smallestring containingK anda. In this case, is a finite extension ofK and all its elements are algebraic overK. In particular, is aK-vector space with basis, whered is the degree of theminimal polynomial ofa.[8] These properties do not hold ifa is not algebraic. For example, and they are both infinite dimensional vector spaces over[9]
Analgebraically closed fieldF has no proper algebraic extensions, that is, no algebraic extensionsE withF <E.[10] An example is the field of complex numbers. Every field has an algebraic extension which is algebraically closed (called itsalgebraic closure), butproving this in general requires some form of theaxiom of choice.[11]
An extensionL/K is algebraicif and only if every subK-algebra ofL is a field.
The following three properties hold:[12]
These finitary results can be generalized using transfinite induction:
This fact, together withZorn's lemma (applied to an appropriately chosenposet), establishes the existence ofalgebraic closures.
Model theory generalizes the notion of algebraic extension to arbitrary theories: anembedding ofM intoN is called analgebraic extension if for everyx inN there is aformulap with parameters inM, such thatp(x) is true and the set
is finite. It turns out that applying this definition to the theory of fields gives the usual definition of algebraic extension. TheGalois group ofN overM can again be defined as thegroup ofautomorphisms, and it turns out that most of the theory of Galois groups can be developed for the general case.
Given a fieldk and a fieldK containingk, one defines therelative algebraic closure ofk inK to be the subfield ofK consisting of all elements ofK that are algebraic overk, that is all elements ofK that are a root of some nonzero polynomial with coefficients ink.