Doubles
2006 BCR Open Romania
Final
Champions	Mariusz Fyrstenberg Marcin Matkowski
Runners-up	Martín García Luis Horna
Score	6–7(5–7), 7–6(7–5), [10–8]
Details
Draw	16 (2WC)
Seeds	4
Events
Singles Doubles
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The Men’sDoubles tournament of the2006 BCR Open Romania tennis championship took place inBucharest, Romania, between 11 and 17 September 2006. 16 pairs from 13 countries competed in the 4-round tournament.

José Acasuso andSebastián Prieto were the defending champions, but Acasuso opted to rest in order to compete at theDavis Cup the following week. Prieto teamed up withFrantišek Čermák and lost in the quarterfinals toMartín García andLuis Horna.

Mariusz Fyrstenberg andMarcin Matkowski won the title by defeating García and Horna 6–7^(5–7), 7–6^(7–5), [10–8] in the final.^[1]

	First round							Quarterfinals							Semifinals							Final
	1	M Fyrstenberg M Matkowski	6	6
		F Serra G Simon	3	1				1	M Fyrstenberg M Matkowski	6	6
		S Greul B Pašanski	1	2					M Mertiňák P Pála	2	0
		M Mertiňák P Pála	6	6											1	M Fyrstenberg M Matkowski	6	6
	4	M Kohlmann A Waske	6	6												PH Mathieu C Rochus	1	2
		J Mónaco M Zabaleta	4	4				4	M Kohlmann A Waske	69	4
		PH Mathieu C Rochus	6	7					PH Mathieu C Rochus	711	6
		A di Mauro F Volandri	0	5																		1	M Fyrstenberg M Matkowski	65	77	[10]
		M García L Horna	7	6																			M García L Horna	77	65	[8]
	WC	A Pavel H Tecău	5	3					M García L Horna	3	6	[10]
		G García López C Kas	6	66	[3]			3	F Čermák S Prieto	6	3	[4]
	3	F Čermák S Prieto	4	78	[10]											M García L Horna	6	6
	WC	V Crivoi V Ioniță	5	2											2	J Knowle J Melzer	2	0
		L Azzaro S Roitman	7	6					L Azzaro S Roitman	5	5
		R Ramírez Hidalgo M Vassallo Argüello	2	3				2	J Knowle J Melzer	7	7
	2	J Knowle J Melzer	6	6

• Main draw (ATP)
• ITF tournament profile

• Romanian Open
• 2006 in Romanian tennis
• 2006 ATP Tour

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• Short description matches Wikidata