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1928 United States presidential election in Rhode Island

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Main article:1928 United States presidential election
1928 United States presidential election in Rhode Island

← 1924
November 6, 1928
1932 →
 
NomineeAl SmithHerbert Hoover
PartyDemocraticRepublican
Home stateNew YorkCalifornia
Running mateJoseph Taylor RobinsonCharles Curtis
Electoral vote50
Popular vote118,973117,522
Percentage50.16%49.55%

County Results
Municipality Results

Smith

  50–60%
  60–70%

Hoover

  50–60%
  60–70%
  70–80%
  80–90%


President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

Elections in Rhode Island
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The1928 United States presidential election in Rhode Island took place on November 6, 1928, as part of the1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to theElectoral College, who voted forpresident andvice president.

Rhode Island voted for theDemocratic nominee,GovernorAlfred E. Smith ofNew York, over theRepublican nominee, formerSecretary of CommerceHerbert Hoover ofCalifornia. Smith's running mate wasSenatorJoseph Taylor Robinson ofArkansas, while Hoover's running mate wasSenate Majority LeaderCharles Curtis ofKansas.

Smith won Rhode Island by a very narrow margin of 0.61%, making him the first Democratic presidential candidate sinceWoodrow Wilson in1912 to carry the state, as well as the first to win an absolute majority of the vote sinceFranklin Pierce in1852. Although Hoover won more counties than Smith, key to Smith's victory was his appeal to "ethnic white"Roman Catholic voters inProvidence County andBristol County. Rhode Island was the only state save adjacentMassachusetts (another state with a large Catholic population) outside the Democratic "Solid South" that voted for Smith in 1928. This was the second of three times that the state voted differently thanMinnesota, along with 1912 and 1984.

Despite winning in alandslide nationally, Hoover became the first Republican to ever win the presidency without carrying Rhode Island. Given the scale of Hoover's win, Rhode Island weighed in as 18 percentage points more Democratic than the United States at large. Hoover also became the first Republican to ever win without carrying Providence and Bristol counties. Beginning in 1928, Rhode Island would transition from a strongly Yankee Republican state into a Democratic-leaning state. Since then, Republicans have only carried the state four times, all in Republican landslide years: 1952, 1956, 1972, and 1984.

Results

[edit]
1928 United States presidential election in Rhode Island[1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
DemocraticAl Smith ofNew YorkJoseph Taylor Robinson ofArkansas118,97350.16%5100.00%
RepublicanHerbert Hoover ofCaliforniaCharles Curtis ofKansas117,52249.55%00.00%
Socialist LaborVerne L. Reynolds ofMichiganJeremiah D. Crowley ofNew York4160.18%00.00%
CommunistWilliam Z. Foster ofMassachusettsBenjamin Gitlow ofNew York2830.12%00.00%
Total237,194100.00%5100.00%

By county

[edit]
1928 United States presidential election in Rhode Island (by county)[2]
CountyAl Smith

Democratic

Herbert Hoover

Republican

Other candidates

Various parties

Total
%#%#%##
Bristol51.8%4,08048.0%3,7800.2%137,873
Kent39.3%7,46060.4%11,4870.3%5819,005
Newport43.9%6,74855.8%8,5780.2%3315,359
Providence52.9%97,18546.8%85,8840.3%568183,637
Washington30.9%3,50068.8%7,7930.2%2711,320

See also

[edit]

References

[edit]
  1. ^"1928 Presidential General Election Results - Rhode Island". U.S. Election Atlas. RetrievedDecember 23, 2013.
  2. ^"RI.gov: Election Results".www.ri.gov. RetrievedFebruary 11, 2024.
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