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1894 United States House of Representatives election in Wyoming

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1894 United States House of Representatives election in Wyoming

← 1892November 6, 1894 (1894-11-06)1896 →
 
NomineeFrank Wheeler MondellHenry A. CoffeenShakespeare E. Sealey
PartyRepublicanDemocraticPopulist
Popular vote10,0686,1522,906
Percentage52.64%32.17%15.19%

County results
Mondell:     40–50%     50–60%     60–70%
Coffeen:     30–40%
     No Data

U.S. Representative before election

Henry A. Coffeen
Democratic

Elected U.S. Representative

Frank Wheeler Mondell
Republican

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TheWyoming United States House election for 1894 was held on November 6, 1894. Republican Frank Wheeler Mondell defeated Democratic incumbent Henry A. Coffeen and Populist Shakespeare E. Sealey with 52.64% of the vote making Coffeen the second incumbent Representative from Wyoming to lose reelection.

Results

[edit]
United States House of Representatives election in Wyoming, 1894[1]
PartyCandidateVotes%
RepublicanFrank Wheeler Mondell10,06852.64%
DemocraticHenry A. Coffeen (inc.)6,15232.17%
PopulistShakespeare E. Sealey2,90615.19%
Total votes19,126100%

References

[edit]
  1. ^"United States House of Representatives election in Wyoming, 1894".
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