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1880 United States presidential election in Florida

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Main article:1880 United States presidential election
1880 United States presidential election in Florida

← 1876November 2, 18801884 →
Turnout19.15% of the total populationDecrease 5.77pp[1]
 
NomineeWinfield S. HancockJames A. Garfield
PartyDemocraticRepublican
Home statePennsylvaniaOhio
Running mateWilliam H. EnglishChester A. Arthur
Electoral vote40
Popular vote27,96423,654
Percentage54.17%45.83%

County Results

Hancock

  50–60%
  60–70%
  70–80%
  80–90%
  90–100%

Garfield

  50–60%
  60–70%
  70–80%


President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

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The1880 United States presidential election in Florida took place on November 2, 1880, as part of the1880 United States presidential election. Florida voters chose four representatives, or electors, to theElectoral College, who voted forpresident andvice president.[2]

Florida was won by GeneralWinfield Scott Hancock (DPennsylvania), running with formerRepresentativeWilliam Hayden English, with 54.17% of the popular vote, againstRepresentativeJames Garfield (R-Ohio), running with the 10th chairman of theNew York State Republican Executive CommitteeChester A. Arthur, with 41.05% of the vote.[2]

Results

[edit]
United States presidential election in Florida, 1880[2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
DemocraticWinfield Scott Hancock ofPennsylvaniaWilliam Hayden English ofIndiana27,96454.17%4100.00%
RepublicanJames Garfield ofOhioChester A. Arthur ofNew York23,65445.83%00.00%
Total51,618100.00%4100.00%

See also

[edit]

References

[edit]
  1. ^"1884 Presidential Election Results Florida Total Population Turnout".
  2. ^abc"1880 Presidential Election Results Florida".
State and district results of the1880 United States presidential election
Electoral map, 1880 election


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