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1872 United States presidential election in New Jersey

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Main article:1872 United States presidential election
1872 United States presidential election in New Jersey

← 1868November 5, 18721876 →
 
NomineeUlysses S. GrantHorace Greeley
PartyRepublicanLiberal Republican
Home stateIllinoisNew York
Running mateHenry WilsonBenjamin G. Brown
Electoral vote90
Popular vote91,65676,456
Percentage54.52%45.48%

County Results

Grant

  50–60%
  60–70%

Greeley

  50–60%


President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

Elections in New Jersey
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The1872 United States presidential election in New Jersey took place on November 5, 1872. All contemporary 37 states were part of the1872 United States presidential election. The state voters chose nine electors to theElectoral College, which selected thepresident andvice president.

New Jersey was won by theRepublican nominees, incumbentPresidentUlysses S. Grant ofIllinois and his running mateSenatorHenry Wilson ofMassachusetts. Grant and Wilson defeated theLiberal Republican andDemocratic nominees, formerCongressmanHorace Greeley ofNew York and his running mate formerSenator andGovernorBenjamin Gratz Brown ofMissouri by a margin of 9.04%.

This was the first time the Republicans won all the electoral votes of New Jersey, (see1860 election in New Jersey for more information) as well as the popular vote. They would not win either again until1896, 24 years later.

Results

[edit]
1872 United States presidential election in New Jersey[1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
RepublicanUlysses S. Grant ofIllinoisHenry Wilson ofMassachusetts91,65654.52%9100.00%
Liberal RepublicanHorace Greeley ofNew YorkBenjamin Gratz Brown ofMissouri76,45645.48%00.00%
Total168,112100.00%9100.00%

See also

[edit]

References

[edit]
  1. ^"1872 Presidential General Election Results - New Jersey".
State and district results of the1872 United States presidential election
Electoral map, 1872 election


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