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The1868 United States presidential election in Kentucky took place on November 3, 1868, as part of the1868 United States presidential election. Voters chose 11 representatives, or electors to theElectoral College, who voted forpresident andvice president.
Kentucky voted for theDemocratic nominee,Horatio Seymour over theRepublican nominee,Ulysses S. Grant. Seymour won the state by a margin of 49.1%.
With 74.55% of the popular vote, Kentucky would be Seymour's strongest victory in terms of percentage in the popular vote.[1] As of the2020 presidential election, this remains the strongest-ever performance by a presidential nominee in Kentucky who had a major-party opponent since theFirst Party System, whenDemocratic-Republicans regularly routedFederalists with over 90% of the vote. It was also the last time thatClinton County orCumberland County would vote for a Democratic presidential candidate.[2]
| 1868 United States presidential election in Kentucky[3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Horatio Seymour ofNew York | Francis Preston Blair Jr. ofMissouri | 115,889 | 74.55% | 11 | 100.00% | ||
| Republican | Ulysses S. Grant ofIllinois | Schuyler Colfax ofIndiana | 39,566 | 25.44% | 0 | 0.00% | ||
| Total | 155,455 | 100.00% | 11 | 100.00% | ||||
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