The1867 United States Senate election in Wisconsin was held in the20th Wisconsin Legislature onJanuary 23, 1867. Incumbent Republican U.S. senatorTimothy O. Howe was re-elected on the first ballot.[1]
At the start of the 1867 term, Republicans held large majorities in both chambers of theWisconsin Legislature, bolstered by theNational Union Party coalition, and were easily able to re-elect their incumbent U.S. senator. His re-election was considered a foregone conclusion in newspapers, and there doesn't appear to have been any other candidates for the Republican nomination.
The20th Wisconsin Legislature met in joint session on January 23, 1867, to elect a U.S. senator. The voting was almost entirely along party lines, with one Republican and four Democratic members absent. Of the 128 in attendance, Timothy O. Howe received the votes of all but one of the Republican and Union legislators, winning the election.[1][2]
^Howe received the votes of all National Union (Republican) members except representativesJoseph A. Frost (who was absent) andJoseph Wedig (who voted for Eldredge); he also received one cross-over vote from Democratic senatorMatthew J. Meade.
^Eldredge received the votes of all Democrats except senatorsMatthew J. Meade andGerrit T. Thorn and representativeHarrison Carroll Hobart (who voted for others), and representatives George W. Clason, Charles D. Gage, Charles H. Miller, and Thomas Robinson (who were absent); he also received one cross-over vote from Republican representativeJoseph Wedig.
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