Movatterモバイル変換


[0]ホーム

URL:


Jump to content
WikipediaThe Free Encyclopedia
Search

1867 Iowa gubernatorial election

From Wikipedia, the free encyclopedia

1867 Iowa gubernatorial election

← 1865October 8, 18671869 →
 
NomineeSamuel MerrillCharles Mason
PartyRepublicanDemocratic
Popular vote90,20462,966
Percentage58.88%41.10%

County results
Merrill:     50-60%     60-70%     70-80%     80-90%     90-100%
Mason:     50-60%     60-70%
No Data/Votes:     

Governor before election

William M. Stone
Republican

Elected Governor

Samuel Merrill
Republican

The1867 Iowa gubernatorial election was held on October 8, 1867.Republican nomineeSamuel Merrill defeatedDemocratic nomineeCharles Mason with 58.88% of the vote.

General election

[edit]

Candidates

[edit]
  • Samuel Merrill, Republican
  • Charles Mason, Democratic

Results

[edit]
1867 Iowa gubernatorial election[1]
PartyCandidateVotes%±%
RepublicanSamuel Merrill90,20458.88%
DemocraticCharles Mason62,96641.10%
Majority27,238
Turnout
RepublicanholdSwing

References

[edit]
  1. ^Kalb, Deborah (December 24, 2015).Guide to U.S. Elections.ISBN 9781483380353. RetrievedJune 5, 2021.
Retrieved from "https://en.wikipedia.org/w/index.php?title=1867_Iowa_gubernatorial_election&oldid=1271248472"
Categories:
Hidden categories:

[8]ページ先頭

©2009-2025 Movatter.jp