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In theChicago mayoral election of 1860, Democratic nomineeJohn Wentworth defeated Republican nomineeWalter S. Gurnee.
Both candidates had served as mayor before. Incidentally, each had previously been mayor under the opposite party affiliation. Gurnee had served two terms as a Democrat, having been elected in1851 and1852, Wentworth had previously served one term as a Republican, having been elected in1857.
The election was held on March 3.[1]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | John Wentworth | 9,998 | 53.36 | |
| Republican | Walter S. Gurnee | 8,739 | 46.64 | |
| Turnout | 18,737 | |||
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| Elections |
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1 tenure as acting officeholder. 2 Election declared null and void. | ||
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