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1856 United States presidential election in Iowa

From Wikipedia, the free encyclopedia

1856United States presidential election in Iowa

← 1852November 4, 18561860 →
 
NomineeJohn C. FrémontJames BuchananMillard Fillmore
PartyRepublicanDemocraticKnow Nothing
Home stateCaliforniaPennsylvaniaNew York
Running mateWilliam L. DaytonJohn C. BreckinridgeAndrew J. Donelson
Electoral vote400
Popular vote45,07337,5689,669
Percentage48.83%40.70%10.47%

County Results

Frémont

  40–50%
  50–60%
  60–70%
  70–80%
  80–90%
  90–100%

Buchanan

  40–50%
  50–60%
  60–70%


President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

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The1856 United States presidential election in Iowa took place on November 4, 1856, as part of the1856 United States presidential election. Voters chose four representatives, or electors to theElectoral College, who voted forpresident andvice president.

Iowa voted for theRepublican candidate,John C. Frémont, overDemocratic candidate,James Buchanan andAmerican Party candidateMillard Fillmore. Frémont won Iowa by a margin of 8.13%.

Buchanan is the second of only 6 US presidents and the first of 4 Democratic presidents to have never won Iowa. He also didn't carryBuchanan County, which is named after him.

Results

[edit]
1856 United States presidential election in Iowa[1][2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
RepublicanJohn C. Frémont ofCaliforniaWilliam L. Dayton ofNew Jersey45,07348.83%4100.00%
DemocraticJames Buchanan ofPennsylvaniaJohn C. Breckinridge ofKentucky37,56840.70%00.00%
Know NothingMillard Fillmore ofNew YorkAndrew Jackson Donelson ofTennessee9,66910.47%00.00%
Total92,310100.00%4100.00%

See also

[edit]

References

[edit]
  1. ^"1856 Presidential General Election Results - Iowa". U.S. Election Atlas. RetrievedDecember 3, 2017.
  2. ^"1856 Presidential Election".The American Presidency Project. University of California Santa Barbara. RetrievedDecember 3, 2017.
Electoral map, 1856 election


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