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1840 United States presidential election in Pennsylvania

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Main article:1840 United States presidential election
1840 United States presidential election in Pennsylvania

← 1836October 30, 18401844 →
← OH
AR →
 
NomineeWilliam Henry HarrisonMartin Van Buren
PartyWhigDemocratic
Home stateOhioNew York
Running mateJohn Tylernone
Electoral vote300
Popular vote144,010143,676
Percentage49.99%49.88%

County Results

Harrison

  50–60%
  60–70%
  70–80%

Van Buren

  50–60%
  60–70%
  70–80%
  80–90%


President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

Elections in Pennsylvania
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Apresidential election was held inPennsylvania on October 30, 1840 as part of the1840 United States presidential election.[1] Voters chose 30 representatives, or electors to theElectoral College, who voted forPresident andVice President.

Pennsylvania voted forWhig challengerWilliam Henry Harrison overDemocratic incumbentMartin Van Buren by just 334 votes, a margin of 0.12%. It is the narrowest margin of victory in a presidential election in Pennsylvania history, withDonald Trump's2016 win following close behind at 0.72%.

Results

[edit]
1840 United States presidential election in Pennsylvania[2]
PartyCandidateVotesPercentageElectoral votes
WhigWilliam Henry Harrison144,01049.99%30
DemocraticMartin Van Buren (incumbent)143,67649.89%0
LibertyJames G. Birney3400.12%0
Totals288,026100.0%30

See also

[edit]

References

[edit]
  1. ^Dubin, Michael J. (2002).United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
  2. ^"1840 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. RetrievedAugust 4, 2012.
State and district results of the1840 United States presidential election
Electoral map, 1840 election


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