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1840 United States presidential election in Connecticut

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Main article:1840 United States presidential election
1840 United States presidential election in Connecticut

← 1836
November 2, 1840
1844 →
← AR
GA →
 
NomineeWilliam Henry HarrisonMartin Van Buren
PartyWhigDemocratic
Home stateOhioNew York
Running mateJohn Tylernone
Electoral vote80
Popular vote31,59825,281
Percentage55.55%44.45%

County Results
Municipality Results
Congressional district results

Harrison

  40–50%
  50–60%
  60–70%
  70–80%
  80–90%

Van Buren

  50–60%
  60–70%


President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

Elections in Connecticut
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Apresidential election was held inConnecticut on November 2, 1840 as part of the1840 United States presidential election.[1] Voters chose eight representatives, or electors to theElectoral College, who voted forPresident andVice President.

Connecticut voted for theWhig candidate,William Henry Harrison, overDemocratic candidateMartin Van Buren. Harrison won Connecticut by a margin of 11.1%.

Results

[edit]
1840 United States presidential election in Connecticut[2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
WhigWilliam Henry Harrison ofOhioJohn Tyler ofVirginia31,59855.55%8100.00%
DemocraticMartin Van Buren ofNew YorkRichard Mentor Johnson ofKentucky25,28144.45%00.00%
Total56,879100.00%8100.00%

See also

[edit]

References

[edit]
  1. ^Dubin, Michael J. (2002).United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
  2. ^"1840 Presidential General Election Results - Connecticut". U.S. Election Atlas. RetrievedDecember 23, 2013.
General
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State and district results of the1840 United States presidential election
Electoral map, 1840 election


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