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Apresidential election was held inConnecticut on November 7, 1836 as part of the1836 United States presidential election.[1] Voters chose eight representatives, or electors to theElectoral College, who voted forPresident andVice President.
Connecticut voted for theDemocratic candidate,Martin Van Buren, overWhig candidateWilliam Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
| 1836 United States presidential election in Connecticut[2] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
| Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
| Totals | 38,093 | 100.0% | 8 | ||
State and district results of the1836 United States presidential election | ||
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