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1832 United States presidential election in Tennessee

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Main article:1832 United States presidential election
1832 United States presidential election in Tennessee
← 1828November 2 – December 5, 18321836 →
 
NomineeAndrew JacksonHenry Clay
PartyDemocraticNational Republican
Home stateTennesseeKentucky
Running mateMartin Van BurenJohn Sergeant
Electoral vote150
Popular vote28,0781,347
Percentage95.42%4.58%

County results

Jackson

  60–70%
  80–90%
  90–100%

Clay

  50–60%


Precinct before election

Andrew Jackson
Democratic

Elected Precinct

Andrew Jackson
Democratic

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The1832 United States presidential election in Tennessee took place between November 2 and December 5, 1832, as part of the1832 United States presidential election. Voters chose 15 representatives, or electors to theElectoral College, who voted forPresident andVice President.

Tennessee voted for theDemocratic Party candidate, state nativeAndrew Jackson, over theNational Republican candidate,Henry Clay. Jackson won Tennessee by a large margin of 90.84%. This is the most recent election in whichBlount County,Carter County,Cocke County,Grainger County,Jefferson County, andSevier County voted for a Democratic presidential candidate on a presidential level.

Results

[edit]
1832 United States presidential election in Tennessee[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)28,07895.42%15
National RepublicanHenry Clay1,3474.58%0
Totals29,425100.00%15

See also

[edit]

References

[edit]
  1. ^"1832 Presidential General Election Results — Tennessee". U.S. Election Atlas. RetrievedApril 12, 2013.
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State and district results of the1832 United States presidential election
Electoral map, 1832 election
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