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1824 United States presidential election in Connecticut

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Main article:1824 United States presidential election
1824 United States presidential election in Connecticut

← 1820October 26 – December 2, 18241828 →
 
NomineeJohn Quincy AdamsWilliam H. Crawford
PartyDemocratic-RepublicanDemocratic-Republican
AllianceAdams-Clay RepublicanOld Republican
Home stateMassachusettsGeorgia
Running mateJohn C. CalhounNathaniel Macon
Electoral vote80
Popular vote7,4941,965
Percentage70.39%18.46%

County Results
Adams
  60–70%
  70–80%
  80–90%
  90–100%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

Elections in Connecticut
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The1824 United States presidential election in Connecticut took place between October 26 and December 2, 1824, as part of the1824 United States presidential election. Voters chose eight representatives, or electors to theElectoral College, who voted forPresident andVice President.

During this election, theDemocratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency.Connecticut voted forJohn Quincy Adams overWilliam H. Crawford,Andrew Jackson, andHenry Clay. Adams won Connecticut by a margin of 51.93%.

Results

[edit]
1824 United States presidential election in Connecticut[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJohn Quincy Adams7,49470.39%8
Democratic-RepublicanWilliam H. Crawford1,96518.46%0
N/AOther1,18811.16%0
Totals10,647100.0%8

See also

[edit]

References

[edit]
  1. ^"1824 Presidential General Election Results - Connecticut". U.S. Election Atlas. RetrievedFebruary 27, 2013.
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State and district results of the1824 United States presidential election
Electoral map, 1824 election
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