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The1808 United States presidential election in Rhode Island took place as part of the1808 United States presidential election. Voters chose 4 representatives, or electors to theElectoral College who voted forpresident andvice president.
Rhode Island voted for theFederalist candidate,Charles Cotesworth Pinckney, over theDemocratic-Republican candidate,James Madison. Pinckney won Rhode Island by a margin of 53.30%.
| 1808 United States presidential election in Rhode Island[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | Charles Cotesworth Pinckney | 3,072 | 53.30% | 4 | |
| Democratic-Republican | James Madison | 2,692 | 46.70% | – | |
| Totals | 5,764 | 100.00% | 4 | ||
| Candidates |  | |
|---|---|---|
| General articles | ||
| Local results | ||
| Other 1808 elections | ||
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