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The1788–89 United States presidential election in Massachusetts took place on January 7, 1789, as part of the1788–1789 United States presidential election to elect the first President. Massachusetts was entitled to 10 electors, with two being appointed by the state legislature and the rest being chosen by state legislature from the two most popular candidates in each U.S. House district. Each elector voted once forPresident and again forVice President.[1]
Massachusetts unanimously voted for independent candidate and commander-in-chief of theContinental Army,George Washington, for president and Federalist candidate, former Minister to Great Britain, and delegate to the Continental Congress from MassachusettsJohn Adams for vice president. The total vote was composed of 4,477 forFederalist electors and 132 forAnti-Federalist electors, all of whom were supportive of Washington.[2] Several candidates of unknown affiliation also received votes.
| 1788–1789 United States presidential election in Massachusetts | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Independent | George Washington | 4,609 | 100.00% | 10 | |
| Totals | 17,740 | 100.00% | 10 | ||
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