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1788–89 United States presidential election in Massachusetts

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Main article:1788–89 United States presidential election
1788–89 United States presidential election in Massachusetts

January 7, 17891792 →
 
NomineeGeorge WashingtonJohn Adams
PartyIndependentPro-Administration
Home stateVirginiaMassachusetts
Electoral vote1010
Popular vote4,609
Percentage100.00%

County results

Washington/Adams (Federalist)

  80-90%
  90-100%


President before election

Office established

Elected President

George Washington
Independent

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The1788–89 United States presidential election in Massachusetts took place on January 7, 1789, as part of the1788–1789 United States presidential election to elect the first President. Massachusetts was entitled to 10 electors, with two being appointed by the state legislature and the rest being chosen by state legislature from the two most popular candidates in each U.S. House district. Each elector voted once forPresident and again forVice President.[1]

Massachusetts unanimously voted for independent candidate and commander-in-chief of theContinental Army,George Washington, for president and Federalist candidate, former Minister to Great Britain, and delegate to the Continental Congress from MassachusettsJohn Adams for vice president. The total vote was composed of 4,477 forFederalist electors and 132 forAnti-Federalist electors, all of whom were supportive of Washington.[2] Several candidates of unknown affiliation also received votes.

Results

[edit]
1788–1789 United States presidential election in Massachusetts
PartyCandidateVotesPercentageElectoral votes
IndependentGeorge Washington4,609100.00%10
Totals17,740100.00%10

See also

[edit]

References

[edit]
  1. ^"The Electoral Count for the Presidential Election of 1789".The Papers of George Washington. Archived fromthe original on September 14, 2013. RetrievedMay 4, 2005.
  2. ^"A New Nation Votes".elections.lib.tufts.edu. RetrievedJuly 16, 2024.
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