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1788–89 United States presidential election in Georgia

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Main article:1788–89 United States presidential election
1788–89 United States presidential election in Georgia

January 7, 1789
1792 →
 
NomineeGeorge WashingtonJohn MiltonJames Armstrong
PartyIndependentFederalistFederalist
Home stateVirginiaGeorgiaGeorgia
Electoral vote521
Percentage100.00%

 
NomineeEdward TelfairBenjamin Lincoln
PartyAnti-FederalistFederalist
Home stateGeorgiaMassachusetts
Electoral vote11

President before election

Office established

Elected President

George Washington
Independent

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The1788–89 United States presidential election in Georgia took place on January 7, 1789, as part of the1788–89 United States presidential election. Thestate legislature chose 5 representatives, or electors to theElectoral College, who voted forPresident andVice President.

George Handley, John King,George Walton,Henry Osborne, andJohn Milton served as electors. The electors cast five votes forGeorge Washington, two for Milton, one forJames Armstrong, one forEdward Telfair, and one forBenjamin Lincoln.[1]

See also

[edit]

References

[edit]
  1. ^Jensen & Becker 1976, p. xxix.

Works cited

[edit]
U.S.
President
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State and district results of the1788–89 United States presidential election
Electoral map, 1788–89 election


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