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Fractals/Mathematics/Numbers

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<Fractals
"Many questions concerning (discrete) dynamical systems are of a number theoretic or combinatorial nature." Christian Krattenthaler
The set of real numbers

Intro

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Number types

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Number can be used as :

  • a numerical values used in numerical computations
  • a symbols used in symbolic computations

Number ( for exampleangle in turns ) can be:[1]


dimension

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way to represent real numbers using a finite number of bits

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expansion/representation

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  • finite = terminating
  • infinite = non-terminating
    • periodic = infite repeating
    • preperiodic = eventually periodic
    • non-periodic: binary numerals which neither terminate nor recur represent irrational numbers

base

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radix or base of a positional numeral system[14]

form/notation

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Notation[15]

6.022e23=6.0221023{\displaystyle 6.022e23=6.022*10^{23}}
1.2345e3=1.2345+103{\displaystyle 1.2345e-3=1.2345+10^{-3}}
363=3261=121=0.04761904761904762{\displaystyle {\tfrac {3}{63}}={\tfrac {3}{2^{6}-1}}={\tfrac {1}{21}}=0.04761904761904762}

A computer number formats ( storage forms)

  • floating point form ( expansion) : the number's radix point can "float" anywhere to the left, right, or between the significant digits of the number.
  • fixed point format

Round brackets

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brackets with exponent ( superscript) denotes how many times the series repeats[19]

0.11(11101010)=0.11(11(10)3){\displaystyle 0.11(11101010)=0.11(11(10)^{3})}


Trailing zeros

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Trailing zeros to the right of a decimal point, as in 12.3400, do not affect the value of a number and may be omitted if all that is of interest is its numerical value. This is true even if the zeros recur infinitely. For example, in pharmacy, trailing zeros are omitted from dose values to prevent misreading. However, trailing zeros may be useful for indicating the number of significant figures, for example in a measurement. In such a context, "simplifying" a number by removing trailing zeros would be incorrect.

The number of trailing zeros in a non-zero base-b integer n equals the exponent of the highest power of b that divides n. For example, 14000 has three trailing zeros and is therefore divisible by 1000 = 103, but not by 104. This property is useful when looking for small factors in integer factorization. Some computer architectures have a count trailing zeros operation in their instruction set for efficiently determining the number of trailing zero bits in a machine word.

Examples of binary expansions

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First check if the ratio is in the lowest terms ( reducible)

Binary expansion can be :

Conversions

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Conversion between :

  • bases ( from binary to decimal, ...)
  • forms ( rational to expansion, ...)[20]
    • Recognizing Rational Numbers From Their Decimal Expansion:[21] "to compute the simple continued fraction of the approximation, and truncate it before a large partial quotient a_n, then compute the value of the truncated continued fraction."
    • converting-repeating-decimals-to-fractions[22]
    • fraction to recurring decimal[23]
      • use of Floyd's Cycle Detection Algorithm for finding of the first repetitive remainder
      • recursive division and collection of remainders (associated with pieces of decimal fraction)
    • convert-repeating-fractions-to-different-bases[24]

Using :

Algorithms

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  • Find
    • strictly repeating patterns (that you do not know in advance) in a binary string/sequence[30] "If there is a pattern => its length must divide the string length "AnotherGeek[31]
    • non-repeating and strictly repeating patterns (that you do not know in advance) in a binary string/sequence
  • convert a number with a repeating fractional part


Reducing Fractions to Lowest Terms

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A fraction that is reducible can be reduced by dividing both the numerator and denominator by a common factor. It can be fully reduced to lowest terms if both are divided by their greatest common divisor

Algorithms for finding the greatest common divisor:

  • the Euclidean algorithm
  • prime factorization

The Euclidean algorithm is commonly preferred because it allows one to reduce fractions with numerators and denominators too large to be easily factored

Examples:

convert decimal fraction to binary

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"... we repeatedly multiply the decimal fraction by 2. If the result is greater than or equal to 1, we add a 1 to our answer. If the result is less than 1, we add a 0 to our answer." (from Virginia Tech Online CS module[35])

Algorithm:[36]

  • Multiply the input decimal fraction by two
  • from above result
    • take integer part as the binary digit
    • take the fractional part as the starting point for the next step
  • repeat until you either get to 0 or a periodic number
  • read the number starting from the top - the first binary digit is the first digit after the comma

Example of conversion 0.1 decimal fraction to binary fraction :

   0.1 * 2 = 0.2 -> 0   0.2 * 2 = 0.4 -> 0   0.4 * 2 = 0.8 -> 0   0.8 * 2 = 1.6 -> 1   0.6 * 2 = 1.2 -> 1   0.2 * 2 = 0.4 -> 0   0.4 * 2 = 0.8 -> 0   0.8 * 2 = 1.6 -> 1   0.6 * 2 = 1.2 -> 1   0.2 * 2 = 0.4 -> 0   0.4 * 2 = 0.8 -> 0   0.8 * 2 = 1.6 -> 1   0.6 * 2 = 1.2 -> 1   0.2 * 2 = 0.4 -> 0

Result:

0.110=0.0(0011)2{\displaystyle 0.1_{10}=0.0(0011)_{2}}

Repeating fractions :[37]

0.(567) = 567/999 = 189/333 = 63/1110.(0011) = 0011 / 1111 =(in decimal) 3/15 = 1/5
Graphical conversion

Code

Convert binary fraction to decimal ratio

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Geometric series

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(Pre)periodicbinary fraction can be split into 2 fractions:

  • finite
  • infinite: periodic with empty or filled with zeros preperiodic part
0.b...bt(b...bp)=0.b...bt+0.0...0t(b...bp){\displaystyle 0.\overbrace {b...b} ^{t}(\overbrace {b...b} ^{p})=0.\overbrace {b...b} ^{t}+0.\overbrace {0...0} ^{t}(\overbrace {b...b} ^{p})}


Formula for the geometric series when |r|<1 :[38]

a+ar+ar2+ar3+ar4+=k=0ark=a1r{\displaystyle a+ar+ar^{2}+ar^{3}+ar^{4}+\cdots =\sum _{k=0}^{\infty }ar^{k}={\frac {a}{1-r}}}

For the infinite periodic binary fraction with empty or filled with zeros preperiodic part this formula is[39]

0.0...0t(b...bp)=a1r{\displaystyle 0.\overbrace {0...0} ^{t}(\overbrace {b...b} ^{p})={\frac {a}{1-r}}}

where :


0.b...bt(b...bp)=0.b...bt+a1r=0.b...bt+0.0...0tb...bp2p12p{\displaystyle 0.\overbrace {b...b} ^{t}(\overbrace {b...b} ^{p})=0.\overbrace {b...b} ^{t}+{\frac {a}{1-r}}=0.\overbrace {b...b} ^{t}+{\frac {0.\overbrace {0...0} ^{t}\overbrace {b...b} ^{p}}{\frac {2^{p}-1}{2^{p}}}}}


Full formula is now:

0.b...bt(b...bp)=0.b...bt+0.0...0tb...bp2p12p{\displaystyle 0.\overbrace {b...b} ^{t}(\overbrace {b...b} ^{p})=0.\overbrace {b...b} ^{t}+{\frac {0.\overbrace {0...0} ^{t}\overbrace {b...b} ^{p}}{\frac {2^{p}-1}{2^{p}}}}}


Examples :

0.0101(11001)=0.0101+0.00001100125125=516+25/51231/32=516+25496=45124{\displaystyle 0.0101(11001)=0.0101+{\frac {0.000011001}{\frac {2^{5}-1}{2^{5}}}}={\frac {5}{16}}+{\frac {25/512}{31/32}}={\frac {5}{16}}+{\frac {25}{496}}={\frac {45}{124}}}

code examples

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bc

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Conversion from decimal ratio to binary[40] usingbc – arbitrary–precision arithmetic language

bc 1.06Copyright 1991-1994, 1997, 1998, 2000 Free Software Foundation, Inc.This is free software with ABSOLUTELY NO WARRANTY.For details type `warranty'. obase=23/14.00110110110110110110110110110110110110110110110110110110110110110101/5.0011001100110011001100110011001100110011001100110011001100110011001

C

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itoa

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itoa function[42]

/* itoa example http://www.cplusplus.com/reference/cstdlib/itoa/*/#include<stdio.h>#include<stdlib.h>intmain(){inti;charbuffer[33];printf("Enter a number: ");scanf("%d",&i);itoa(i,buffer,10);printf("decimal: %s\n",buffer);itoa(i,buffer,16);printf("hexadecimal: %s\n",buffer);itoa(i,buffer,2);printf("binary: %s\n",buffer);return0;}

Binary integer constant

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Binary integer constant[43]

"Integer constants can be written as binary constants, consisting of a sequence of ‘0’ and ‘1’ digits, prefixed by ‘0b’ or ‘0B’. This is particularly useful in environments that operate a lot on the bit level (like microcontrollers).

The following statements are identical:

i=42;i=0x2a;i=052;i=0b101010;

The type of these constants follows the same rules as for octal or hexadecimal integer constants, so suffixes like ‘L’ or ‘UL’ can be applied."

gmp

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GMP library[44]

/*C programme using gmpgcc r.c -lgmp -Wallhttp://gmplib.org/manual/Rational-Number-Functions.html#Rational-Number-Functions*/#include<stdio.h>#include<gmp.h>intmain(){// input = binary fraction as a stringchar*sbr="01001010010010100101001001010010010100101001001010010100100101001001010010100100101001010/11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111";mpq_tq;// rational number;intb=2;// base of numeral systemmpz_tn;mpz_td;mpf_tf;// init and set variablesmpq_init(q);// Initialize r and set it to 0/1.mpq_set_str(q,sbr,b);mpq_canonicalize(q);// It is the responsibility of the user to canonicalize the assigned variable before any arithmetic operations are performed on that variable.mpq_canonicalize(q);// It is the responsibility of the user to canonicalize the assigned variable before any arithmetic operations are performed on that variable.// n , dmpz_inits(n,d,NULL);mpq_get_num(n,q);mpq_get_den(d,q);//mpf_init2(f,100);// http://stackoverflow.com/questions/12804362/gmp-division-precision-or-printing-issuempf_set_q(f,q);// There is no rounding, this conversion is exact.// printgmp_printf("decimal fraction =  %Zd / %Zd\ndecimal canonical form =  %Qd\n",n,d,q);//gmp_printf("binary fraction  = %s\n",sbr);//gmp_printf("decimal floating point number : %.30Ff\n",f);//// clear memorympq_clear(q);mpz_clear(n);mpz_clear(d);mpf_clear(f);return0;}

Output :

decimal fraction =  179622968672387565806504266 / 618970019642690137449562111 decimal canonical form =  179622968672387565806504266/618970019642690137449562111binary fraction  = 01001010010010100101001001010010010100101001001010010100100101001001010010100100101001010/11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 decimal floating point number : 0.290196557138708685358212602171

Haskell

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Code by Claude Heiland-Allen:[45]

--  http://mathr.co.uk/blog/2014-10-13_converting_fractions_to_strings_of_digits.htmlimportData.Fixed(mod')importData.List(nub)importData.Ratio((%),denominator)importData.Numbers.Primes(primeFactors)importSystem.Environment(getArgs)dataDigits=Digits{dNegative::Bool,dInteger,dPreperiodic,dPeriodic::[Int]}derivingShowpreperiod::Digits->Intpreperiod=length.dPreperiodicperiod::Digits->Intperiod=length.dPeriodicdigitsAtBase::Int->Rational->DigitsdigitsAtBasebaserational=Digits{dNegative=rational<0,dInteger=int,dPreperiodic=pre,dPeriodic=per}whereinteger::Integerfraction::Rational(integer,fraction)=properFraction(absrational)int|integer==0=[0]|otherwise=goIntinteger[]goIntids|i==0=ds|otherwise=goInti'(fromIntegerd:ds)where(i',d)=i`divMod`baseZfactors::[Integer]factors=mapfromIntegral.nub.primeFactors$baseisPreperiodic::Rational->BoolisPreperiodicx=any(`divides`denominatorx)factorsbaseZ::IntegerbaseZ=fromIntegralbasebaseQ::RationalbaseQ=fromIntegralbase(pre,per)=goPrefractionwheregoPre::Rational->([Int],[Int])goPrex|isPreperiodicx=first(d:)(goPrex')|otherwise=([],d:goPerxx')where(d,x')=properFraction(baseQ*x)goPer::Rational->Rational->[Int]goPerx0x|x0==x=[]|otherwise=d:goPerx0x'where(d,x')=properFraction(baseQ*x)first::(a->c)->(a,b)->(c,b)firstf(a,b)=(fa,b)divides::Integer->Integer->Boolfactor`divides`number=number`mod`factor==0digitsToString::[String]->Digits->StringdigitsToStringdigitsDigits{dNegative=sign,dInteger=int,dPreperiodic=pre,dPeriodic=per}=(ifsignthen"-"else"")++dint++"."++dpre++"("++dper++")"whered=concatMap(digits!!)atBase::Int->Rational->StringatBasebaserational=digitsToStringds(digitsAtBasebaserational)whereds|base<=62=map(:[])$['0'..'9']++['A'..'Z']++['a'..'z']|otherwise=["<"++showd++">"|d<-[0..base-1]]main::IO()main=do[sbase,sfraction]<-getArgslet(snum,_:sden)=break('/'==)sfractionbase=readsbasenum=readsnumden=readsdenrational=num%denputStrLn(atBasebaserational)

Python

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# https://wiki.python.org/moin/BitManipulation# binary string to integer>>>int('00100001',2)33# conversion from binary string to  hex string>>>print"0x%x"%int('11111111',2)0xff>>>print"0x%x"%int('0110110110',2)0x1b6>>>print"0x%x"%int('0010101110101100111010101101010111110101010101',2)0xaeb3ab57d55

Other methods[46]

How to use numbers in computer programs ?

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First read:

integer

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  • types
  • limits and overflow

Limit

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/*gcc l.c -lm -Wall./a.outhttp://stackoverflow.com/questions/29592898/do-long-long-and-long-have-same-range-in-c-in-64-bit-machine*/#include<stdio.h>#include<math.h> // M_PI; needs -lm also#include<limits.h> // INT_MAX, http://pubs.opengroup.org/onlinepubs/009695399/basedefs/limits.h.htmlintmain(){doublelMax;lMax=log2(INT_MAX);printf("INT_MAX\t= %25d ; lMax = log2(INT_MAX)\t= %.0f\n",INT_MAX,lMax);lMax=log2(UINT_MAX);printf("UINT_MAX\t= %25u ; lMax = log2(UINT_MAX)\t= %.0f\n",UINT_MAX,lMax);lMax=log2(LONG_MAX);printf("LONG_MAX\t= %25ld ; lMax = log2(LONG_MAX)\t= %.0f\n",LONG_MAX,lMax);lMax=log2(ULONG_MAX);printf("ULONG_MAX\t= %25lu ; lMax = log2(ULONG_MAX)\t= %.0f\n",ULONG_MAX,lMax);lMax=log2(LLONG_MAX);printf("LLONG_MAX\t= %25lld ; lMax = log2(LLONG_MAX)\t= %.0f\n",LLONG_MAX,lMax);lMax=log2(ULLONG_MAX);printf("ULLONG_MAX\t= %25llu ; lMax = log2(ULLONG_MAX)\t= %.0f\n",ULLONG_MAX,lMax);return0;}

Results :

INT_MAX =                2147483647 ; lMax = log2(INT_MAX) = 31 UINT_MAX =                4294967295 ; lMax = log2(UINT_MAX) = 32 LONG_MAX =       9223372036854775807 ; lMax = log2(LONG_MAX) = 63 ULONG_MAX =      18446744073709551615 ; lMax = log2(ULONG_MAX) = 64 LLONG_MAX =       9223372036854775807 ; lMax = log2(LLONG_MAX) = 63 ULLONG_MAX =      18446744073709551615 ; lMax = log2(ULLONG_MAX) = 64

For example Wolf Jung inprogram Mandel makes a silent bounds check:[48]

// mndynamo.h  by Wolf Jung (C) 2007-2014typedefunsignedlonglongintqulonglong;// mndcombi.cpp  by Wolf Jung (C) 2007-2014qulonglongmndAngle::wake(intk,intr,qulonglong&n){if(k<=0||k>=r||r>64)return0LL;

If r is to big for unsigned long long int type it returns 0 to prevent integer overflow.

GMP library has arbitrary precision rationals.

floating point

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precision

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Precision

  • GMP : The mantissa of each float has a user-selectable precision ( variable prec type mp_bitcnt_t ). Counts of bits of a multi-precision number are represented in the C type mp_bitcnt_t. Currently this is always an unsigned long
  • MPFR : The precision is the number of bits used to represent the significand ( mantissa) of a floating-point number; the corresponding C data type is mpfr_prec_t.

Rational

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The rational points on a circle correspond, under stereographic projection, to the rational points of the line.

"Any number with a finite decimal expansion is a rational number. " In other words  : "any floating point number can be converted to a rational number."[49]

So in numerical computations one can use only integer of floating points numbers ( rational ).

Decimal

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Binary

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Numbers

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InC one can use :

  • bitwise operators[50]

InMaxima CAS one can use :

(%i1) ibase;(%o1) 10(%i2) obase;(%o2) 10(%i3) ibase:2;(%o3) 2(%i4) x=1001110;(%o4) x=78

String

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Calculation of binary numbers with as a string with replicating parts inHaskell (ghci):

-- by Claude Heiland-Allen-- http://mathr.co.uk/blog/haskell.htmlPrelude>letrepns=concat(replicatens)Prelude>putStrLn$".("++rep88"001"++"010)".(001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001010)putStrLn$".("++rep87"001"++"010001)".(001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001010001)Prelude>putStrLn$".("++rep88"001"++"0001)".(0010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010001)Prelude>putStrLn$".("++rep88"001"++"0010)".(0010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010010)

InPython :

>>>bin(173)'0b10101101'>>>int('01010101111',2)687

Literal

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In python one can use binary literals :[51]

pythonPython2.7.5+(default,Feb272014,19:37:08)[GCC4.8.1]onlinux2Type"help","copyright","credits"or"license"formoreinformation.>>>0b10111147

Irrational = not rational

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Irrational numbers
The problem is that we are exploring environments based upon irrational numbers through computer machinery which works with finite rationals ! ( Alessandro Rosa )

Expansion is non terminating and non repeating

Types:

  • Algebraic Numbers = roots of Algebraic Equations. Example : sqrt(2),
  • transcendental numbers = non algebraic


If one wants use irrational number then should check :

  • symbolic computations :
    • exact number can be used as a symbol, but "you cannot print the whole irrational number"
    • infinite continued fraction
  • numerical computations : close rational approximations to irrational numbers[52] (the Diophantine Approximation[53])
    • ratio of integers
    • floating point number
    • finite continued fractions

Inverse golden mean

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The most irrational number[54] In a continued fraction all numbers are 1 = the slowest convergence of all the irrational numbers


Using Maxima CAS :

(%i10) print(float(%phi-1));(%o10).6180339887498949(%i11) rationalize(float(%phi-1));(%o11) 347922205179541/562949953421312

and  :


(%i14) print(float(1/%phi));(%o14) .6180339887498948(%i15) rationalize(float(1/%phi));(%o15) 5566755282872655/9007199254740992

where denominator :

562949953421312=1+249{\displaystyle 562949953421312=1+2^{49}}

complex

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  • the multi-valued nature of complex powers can cause big troubles ( artifacts of branch cuts, arbitrary principal value of arg)
  • domain coloring[55][56]


Examples

How to find number type

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Note that in numerical computations with finite precision ( on computer) :

  • if number is represented as a ratio ( of integers) then it is a rational number
  • if number has a floating point representation the it is also a rational number because of limited precision = finite expansion
/*Maxima CAS batch file*/remvalue(all);kill(all);/*input = ratio, which automatically changed to lowest terms by Maxima CASoutput = string describing a type of decimal expansion---------------------------------------------------------------------------------" The rules that determine whether a fraction has recurring decimals or not are really quite simple.1. First represent the fraction in its simplest form, by dividing both numerator and denominator by common factors.2. Now, look at the denominator.3.3.1 If the prime factorization of the denominator contains only the factors 2 and 5, then the decimal fraction of that fraction will not have recurring digits. In other words : Terminating decimals represent rational numbers of the form k/(2^n*5^m)3.2  A fraction in lowest terms with a prime denominator other than 2 or 5 (i.e. coprime to 10) always produces a repeating decimal.3.2.1  If the prime factorization yields factors like 3, 7, 11 or other primes (other than 2 and 5), then that fraction will have a decimal representation that includes recurring digits.3.2.2   Moreover, if the denominator's prime factors include 2 and/or 5 in addition to other prime factors like 3, 7, etc., the decimal representation of the fraction will start with a few non-recurring decimals before the recurring part."http://blogannath.blogspot.com/2010/04/vedic-mathematics-lesson-49-recurring.htmlcheck :http://www.knowledgedoor.com/2/calculators/convert_a_ratio_of_integers.htmlwikipedia: Repeating_decimal" A fraction in lowest terms with a prime denominator other than 2 or 5 (i.e. coprime to 10) always produces a repeating decimal.The length of the repetend (period of the repeating decimal) of 1/p is equal to the order of 10 modulo p. If 10 is a primitive root modulo p, the repetend length is equal to p − 1; if not, the repetend length is a factor of p − 1. This result can be deduced from Fermat's little theorem, which states that 10p−1 = 1 (mod p)."---------------------------------------------------------------------------------------*/GiveRatioType(ratio):=block(   [denominator:denom(ratio),    FactorsList ,    Factor,    Has25:false,    HasAlsoOtherPrimes:false,    type ], /* type of decimal expansion of the ratio of integers */   /* compute list of prime factors ofd denominator */   FactorsList:ifactors(denominator),   FactorsList:map(first,FactorsList),   print(denominator, FactorsList),   /* check factors type :          only 2 or 5          also other primes then 2 or 5  */   if (member(2,FactorsList) or member(5,FactorsList)) then Has25:true,   for Factor in FactorsList do    if (not member(Factor,[2,5])) then          HasAlsoOtherPrimes:true,   print(Has25, HasAlsoOtherPrimes),   /* find type of decimal expansion */   if (not Has25 and HasAlsoOtherPrimes)     then type:"periodic",   if (Has25 and HasAlsoOtherPrimes)     then type:"preperiodic",   if (Has25 and not HasAlsoOtherPrimes) then type:"finite",   return(type))$compile(all)$/* input numbers*/a:1 $b:3 $r:a/b$type :  GiveRatioType(r);

tools

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More

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Cardinality

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In mathematic ( theory) :

  • "... the rational numbers are a countable set whereas the irrational numbers are an uncountable set. In other words, there are more irrational numbers than there are rational. "[59]
  • "... in the set of real numbers there is continuum of irrational numbers and only aleph-zero rational numbers. Thus probability that any random number is irrational is 1;" ( Bartek Ogryczak)[60] "To be pedantically correct you should have said almost certainly is 1. " – David Hammen


height of a rational number in lowest term

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Thomae function = 1/q
  "a “height function” is some real-valued function that defines the “arithmetic complexity” of a point ... " Brian Lawrence[61]

Types of the height functions defined on the set of rational numbersQ{\displaystyle \mathbb {Q} }:

where:

  • p/q is a rational number in lowest term


  "How complicated is a rational number? Its size is not a very good indicator for this. For instance, 1987985792837/1987985792836 is approximately 1, but so much more complicated than 1. We'll explain how to measure the complexity of a rational number using various notions of height. We'll  then see how heights are used to prove some basic finiteness theorems in number theory. One example will be the Mordell-Weil theorem: that on any rational elliptic curve, the group of rational points is finitely generated. " Alina Bucur (UCSD): Size Doesn't Matter: Heights in Number Theory


Key words:

  • number field
  • Height Functions in Number Theory

Paritition

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  • paritition function : "partition numbers behave like fractals, possessing an infinitely-repeating structure"[64]

Random number

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The probability that any random number :

  • is irrational is almost 1 ( in theory because of cardinality )
  • is rational is 1 ( in numerical computations because of limited precision )

Fields

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  • generalisation : scalar / vector / tensor
  • fields : scalar ,vector, tensor

References

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  1. exploring binary: nine-ways-to-display-a-floating-point-number
  2. wikipedia : Number base
  3. math.stackexchange question: are-there-real-numbers-that-are-neither-rational-nor-irrational
  4. HOW TO WORK WITH ONE-DI MENSIONAL QUADRATIC MAPS G. Pastor , M. Romera, G. Álvarez, and F. Montoya
  5. What Every Programmer Should Know About Floating-Point Arithmetic
  6. Stackoverflow : Why Are Floating Point Numbers Inaccurate?
  7. home school math  : The fascinating irrational numbers
  8. Tutorial: Floating-Point Binary by Kip Irvine
  9. Dual Numbers & Automatic Differentiation
  10. videos: Imaginary Numbers are Real from Welch Labs
  11. math stackexchange question: is-there-a-third-dimension-of-numbers
  12. Beating Floating Point at its Own Game: Posit Arithmetic by John L. Gustafson , Isaac Yonemoto
  13. fractalforums.org : posits
  14. wikipedia: Radix
  15. Survey of Floating-Point Formats Robert Munafo's home pages on AWS   © 1996-2022 Robert P. Munafo.  
  16. Physics 132 Lab Manual: how-to-write-numbers-significant-figures by Brokk Toggerson and Aidan Philbin
  17. HOW TO WORK WITH ONE-DI MENSIONAL QUADRATIC MAPS G. Pastor , M. Romera, G. Álvarez, and F. Montoya
  18. calculatorsoup: scientific-notation-converter
  19. A Method to Solve the Limitations in Drawing External Rays of the Mandelbrot Set M. Romera,1 G. Pastor, A. B. Orue,1 A. Martin, M.-F. Danca,and F. Montoya
  20. Converting fractions to strings of digits by Claude Heiland-Allen
  21. Rational Numbers From Their Decimal Expansion by William Stein
  22. basic-mathematics : converting-repeating-decimals-to-fractions
  23. Recurring decimal of a rational number by Yurii Lahodiuk
  24. quora : How-do-you-convert-repeating-fractions-to-different-bases
  25. knowledgedoor calculators: convert_a_ratio_of_integers
  26. R.Knott : Fractions – Decimals Calculator
  27. Base Number - Decimal Number Conversion
  28. Decimal to Floating-Point Converter By Rick Regan
  29. wolframalpha binary to decimal conversion
  30. stackoverflow question : best-algorithm-to-find-a-repeating-pattern
  31. stackoverflow questions : method-to-find-repeated-pattern-in-string-apart-from-regex?noredirect=1&lq=1
  32. stackoverflow question: finding-a-repeated-pattern-in-a-string
  33. stackoverflow question: finding-a-pattern-in-a-binary-string
  34. jsfiddle by Jan Turoń
  35. Virginia Tech Online CS module
  36. Stackoverflow : How do you convert a fraction to binary ?
  37. Converting a repeating binary number to decimal (express as a series?)
  38. wikipedia :Geometric_series
  39. stackoverflow question: converting-a-repeating-binary-number-to-decimal-express-as-a-series
  40. math.stackexchange question: find-a-fraction-given-the-repeating-binary-expansions
  41. Where is the itoa function in Linux?
  42. itoa with GCC by Stuart
  43. gcc - Binary-constants
  44. Programowanie_w_systemie_UNIX: GMP in polish wikibooks
  45. Converting fractions to strings of digits by Claude Heiland-Allen
  46. stackoverflow : python int to binary
  47. What Every Computer Scientist Should Know About Floating-Point Arithmetic by DAVID GOLDBERG
  48. wikipedia : Bounds checking
  49. stackoverflow questions : check-if-a-number-is-rational-in-python
  50. Joe McCullough : bitwise operators
  51. Stackoverflow : How do you express binary literals in Python?
  52. John D Cook : best-rational-approximation
  53. DISCOVERING EXACTLY WHEN A RATIONAL IS A BEST APPROXIMATE OF AN IRRATIONAL By KARI LOCK
  54. ams : The Most Irrational Number
  55. complex beauties : math-calendar
  56. David Bau : complex function viewer
  57. Complex Numbers in VBA by Pfadintegral
  58. dumpfp: A Tool to Inspect Floating-Point Numbers by Joshua Haberman
  59. home school math : The fascinating irrational numbers
  60. stackoverflow questions : irrational-number-check-function
  61. Introduction to Heights by Brian Lawrence
  62. sagemath : Rational.global_height
  63. Height Functions by Michael Tepper
  64. Fractal Structure to Partition Function.

See also

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