Fractals/Iterations in the complex plane/tip misiurewicz
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Parts ofthe parameter plane
"the external argument can be calculated as the limit of the arguments of the structural components of the branches 1, 11, 111,..., with periods 4, 5, 6,..., that is, the limit of .(0011), .(00111), .(001111),..., or the limit of .(0100), .(01000), .(010000), .... Hence, ftip(1/3) = .00(1) = .01(0), that are two equal values. "[3]
Method byClaude
Steps of the algorithm:
3 angles landing on M:
0.001(010) 0.001(100) 0.010(001)
The tip of each spoke is the longest matching prefix of neighbouring angles, with 1 appended
0.001(010) // 9/56 = 0.160(714285) 0.0011 // ltip = 3/16 = 0.1875 0.001(100) // 11/56 = 0.196(428571) 0.01 // ftip = 1/4 = 0.25 0.010(001) // 15/56 = 0.267(857142)
Check with program Mandel :
The angle 3/16 or 0011 has preperiod = 4 and period = 1. Entropy: e^h = 2^B = λ = 1.59898328The corresponding parameter ray lands at a Misiurewicz point of preperiod 4 and period dividing 1. Do you want to draw the ray and to shift c to the landing point?
c = -0.017187977338350 +1.037652343793215 i period = 0
The angle 1/4 or 01 has preperiod = 2 and period = 1.Entropy: e^h = 2^B = λ = 1.69562077The corresponding parameter ray lands at a Misiurewicz point of preperiod 2 and period dividing 1.Do you want to draw the ray and to shift c to the landing point?
M_{2,1) = c = -0.228155493653962 +1.115142508039937 iThe angle 1/6 or 0p01 has preperiod = 1 and period = 2.The corresponding parameter ray lands at a Misiurewicz point of preperiod 1 and period dividing 2.Do you want to draw the ray and to shift c to the landing point?
c = -0.000000000000000 +1.000000000000000 i period = 10000
Tips
The angle 1/4 or 01 has preperiod = 2 and period = 1.Entropy: e^h = 2^B = λ = 1.69562077The corresponding parameter ray lands at a Misiurewicz point of preperiod 2 and period dividing 1.Do you want to draw the ray and to shift c to the landing point?c = -0.228155493653962 +1.115142508039937 i The angle 1/4 or 01 has preperiod = 2 and period = 1.The corresponding dynamic ray lands at a preperiodic point of preperiod 2 and period dividing 1.Do you want to draw the ray and to shift z to the landing point?z = -0.228155493653962 +1.115142508039937 iThe angle 4/7 or p100 has preperiod = 0 and period = 3. The dynamic ray lands at a repelling or parabolic point of period dividing 3.Do you want to draw the ray and to shift z to the landing point?z = -0.419643377607081 +0.606290729207199 iThe angle 1/8 or 001 has preperiod = 3 and period = 1.The corresponding dynamic ray lands at a preperiodic point of preperiod 3 and period dividing 1.Do you want to draw the ray and to shift z to the landing point?z = 0.000000000159395 +0.000000000076028 iThe angle 3/16 or 0011 has preperiod = 4 and period = 1.Entropy: e^h = 2^B = λ = 1.59898328 The corresponding parameter ray lands at a Misiurewicz point of preperiod 4 and period dividing 1.Do you want to draw the ray and to shift c to the landing point?c = -0.017187977338350 +1.037652343793215 i period = 0The angle 1/6 or 0p01 has preperiod = 1 and period = 2.The corresponding parameter ray lands at a Misiurewicz point of preperiod 1 and period dividing 2.Do you want to draw the ray and to shift c to the landing point?c = -0.000000000000000 +1.000000000000000 i period = 10000
m-exray-out 100 -0.7432918908524301 0.1312405523087976 8 1000 24 4
result :
.010101010101010101010100(1010)
which is
.01010101010101010101010(01)
All rays landing at the same periodic point have the same period: the common period of the rays is a (possibly proper) multiple of the period of their landing point; therefore one distinguishes:the ray period fromthe orbit period.[4]