IfC is a normal cone inX andB is a bounded subset ofX then is bounded; in particular, every interval is bounded.[2] IfX is Hausdorff then every normal cone inX is a proper cone.[2]
LetX be anordered vector space over the reals that is finite-dimensional. Then the order ofX is Archimedean if and only if the positive cone ofX is closed for the unique topology under whichX is a Hausdorff TVS.[1]
LetX be an ordered vector space over the reals with positive coneC. Then the following are equivalent:[1]
the order ofX is regular.
C is sequentially closed for some Hausdorff locally convex TVS topology onX and distinguishes points inX
the order ofX is Archimedean andC is normal for some Hausdorff locally convex TVS topology onX.