Movatterモバイル変換


[0]ホーム

URL:


Jump to content
WikipediaThe Free Encyclopedia
Search

nth root

From Wikipedia, the free encyclopedia
Arithmetic operation, inverse of nth power
This article is about nth-roots of real and complex numbers. For other uses, seeRoot (disambiguation) § Mathematics.

Modern notation for thenth root of thevariablex

Inmathematics, annth root of anumber is the numberr which, when multiplied by itselfn times, yields x:rn=r×r××rn factors=x.{\displaystyle r^{n}=\underbrace {r\times r\times \dotsb \times r} _{n{\text{ factors}}}=x.} Thepositive integern is called theindex ordegree, and the numberx of which the root is taken is theradicand. A root of degree 2 is called asquare root and a root of degree 3, acube root. Roots of higher degree are referred by usingordinal numbers, as infourth root,twentieth root, etc. The computation of annth root is aroot extraction.

Thenth root ofx is written asxn{\displaystyle {\sqrt[{n}]{x}}} using theradical symbolx{\displaystyle {\sqrt {\phantom {x}}}}. The square root is usually written asx{\displaystyle {\sqrt {x}}}, with the degree omitted. Taking thenth root of a number, for fixedn{\displaystyle n}, is theinverse of raising a number to thenth power,[1] and can be written as afractional exponent:

xn=x1/n.{\displaystyle {\sqrt[{n}]{x}}=x^{1/n}.}

For a positive real numberx,x{\displaystyle {\sqrt {x}}} denotes the positive square root ofx andxn{\displaystyle {\sqrt[{n}]{x}}} denotes the positive realnth root. For example,3 is a square root of9, since32 = 9, and−3 is also a square root of9, since(−3)2 = 9.[2] A negative real numberx has no real-valued square roots, but whenx is treated as a complex number it has twoimaginary square roots,+ix{\displaystyle +i{\sqrt {x}}} andix{\displaystyle -i{\sqrt {x}}}, wherei is theimaginary unit.

In general, any non-zerocomplex number hasn distinct complex-valuednth roots, equally distributed around a complex circle of constantabsolute value. (Thenth root of0 is zero withmultiplicityn, and this circle degenerates to a point.) Extracting thenth roots of a complex numberx can thus be taken to be amultivalued function. By convention theprincipal value of this function, called theprincipal root and denotedxn{\displaystyle {\sqrt[{n}]{x}}}, is taken to be thenth root with the greatest real part and in the special case whenx is a negative real number, the one with a positiveimaginary part. The principal root of a positive real number is thus also a positive real number. As afunction, the principal root iscontinuous in the wholecomplex plane, except along the negative real axis. Thenth roots of 1 are calledroots of unity and play a fundamental role in various areas of mathematics, such asnumber theory,theory of equations, andFourier transform.

An unresolved root, especially one using the radical symbol, is sometimes referred to as asurd[3] or aradical.[4] Any expression containing a radical, whether it is a square root, a cube root, or a higher root, is called aradical expression, and if it contains notranscendental functions ortranscendental numbers it is called analgebraic expression.

Arithmetic operations
Addition (+)
term+termsummand+summandaddend+addendaugend+addend}={\displaystyle \scriptstyle \left.{\begin{matrix}\scriptstyle {\text{term}}\,+\,{\text{term}}\\\scriptstyle {\text{summand}}\,+\,{\text{summand}}\\\scriptstyle {\text{addend}}\,+\,{\text{addend}}\\\scriptstyle {\text{augend}}\,+\,{\text{addend}}\end{matrix}}\right\}\,=\,}sum{\displaystyle \scriptstyle {\text{sum}}}
Subtraction (−)
termtermminuendsubtrahend}={\displaystyle \scriptstyle \left.{\begin{matrix}\scriptstyle {\text{term}}\,-\,{\text{term}}\\\scriptstyle {\text{minuend}}\,-\,{\text{subtrahend}}\end{matrix}}\right\}\,=\,}difference{\displaystyle \scriptstyle {\text{difference}}}
Multiplication (×)
factor×factormultiplier×multiplicand}={\displaystyle \scriptstyle \left.{\begin{matrix}\scriptstyle {\text{factor}}\,\times \,{\text{factor}}\\\scriptstyle {\text{multiplier}}\,\times \,{\text{multiplicand}}\end{matrix}}\right\}\,=\,}product{\displaystyle \scriptstyle {\text{product}}}
Division (÷)
dividenddivisornumeratordenominator}={\displaystyle \scriptstyle \left.{\begin{matrix}\scriptstyle {\frac {\scriptstyle {\text{dividend}}}{\scriptstyle {\text{divisor}}}}\\[1ex]\scriptstyle {\frac {\scriptstyle {\text{numerator}}}{\scriptstyle {\text{denominator}}}}\end{matrix}}\right\}\,=\,}{fractionquotientratio{\displaystyle \scriptstyle \left\{{\begin{matrix}\scriptstyle {\text{fraction}}\\\scriptstyle {\text{quotient}}\\\scriptstyle {\text{ratio}}\end{matrix}}\right.}
Exponentiation
baseexponentbasepower}={\displaystyle \scriptstyle \left.{\begin{matrix}\scriptstyle {\text{base}}^{\text{exponent}}\\\scriptstyle {\text{base}}^{\text{power}}\end{matrix}}\right\}\,=\,}power{\displaystyle \scriptstyle {\text{power}}}
nth root (√)
radicanddegree={\displaystyle \scriptstyle {\sqrt[{\text{degree}}]{\scriptstyle {\text{radicand}}}}\,=\,}root{\displaystyle \scriptstyle {\text{root}}}
Logarithm (log)
logbase(anti-logarithm)={\displaystyle \scriptstyle \log _{\text{base}}({\text{anti-logarithm}})\,=\,}logarithm{\displaystyle \scriptstyle {\text{logarithm}}}

History

[edit]
Main articles:Square root § History, andCube root § History

The Babylonians, as early as 1800 BCE, demonstrated numerical approximations of irrational quantities such as thesquare root of 2 on clay tablets, with an accuracy analogous to six decimal places, as in the tabletYBC 7289.[5] Cuneiform tablets fromLarsa include tables of square and cube roots of integers.[6] The first to prove the irrationality of √2 was most likely thePythagoreanHippasus.[7]Plato in hisTheaetetus, then describes howTheodorus of Cyrene (c. 400 BC) proved the irrationality of3{\displaystyle {\sqrt {3}}},5{\displaystyle {\sqrt {5}}}, etc. up to17{\displaystyle {\sqrt {17}}}.[8] In the first century AD,Heron of Alexandria devised an iterative method tocompute the square root, which is actually a special case of the more generalNewton's method.[9]

The termsurd traces back toAl-Khwarizmi (c. 825), who referred to rational and irrational numbers as "audible" and "inaudible", respectively. This later led to the Arabic wordأصم (asamm, meaning "deaf" or "dumb") for "irrational number" being translated into Latin assurdus (meaning "deaf" or "mute").Gerard of Cremona (c. 1150),Fibonacci (1202), and thenRobert Recorde (1551) all used the term to refer to "unresolved irrational roots", that is, expressions of the formrn{\displaystyle {\sqrt[{n}]{r}}}, in whichn{\displaystyle n} andr{\displaystyle r} are integer numerals and the whole expression denotes an irrational number.[10] Irrational numbers of the form±a,{\displaystyle \pm {\sqrt {a}},} wherea{\displaystyle a} is rational, are called "pure quadratic surds"; irrational numbers of the forma±b{\displaystyle a\pm {\sqrt {b}}}, wherea{\displaystyle a} andb{\displaystyle b} are rational, are calledmixed quadratic surds.[11] An archaic term from the late 15th century for the operation of takingnth roots isradication,[12][13] and an unresolved root is aradical.[4]

In the fourteenth century,Jamshid al-Kashi used an iterative technique now called theRuffini-Horner method to extractnth roots for an arbitraryn. This technique has been used since antiquity to determine square roots, then by China andKushyar ibn Labban during the tenth century to determine cube roots.[14] In 1665,Isaac Newton discovered the generalbinomial theorem, which can convert annth root into aninfinite series.[15] Based on approach developed byFrançois Viète, Newton devised aniterative method for solving anon-linear function of the formf(x)=0{\displaystyle f(x)=0}, which can be used to extract annth root. This technique was further refined byJoseph Raphson and became known as theNewton–Raphson method.[16] In 1690,Michel Rolle introduced the notationan{\displaystyle {\sqrt[{n}]{a}}} for thenth root of the valuea.[17]

In 1629,Albert Girard proposed thefundamental theorem of algebra, but failed to produce a proof.[18] This theorem states that every single-variablepolynomial of degreen hasn roots.[19] Further, a polynomial with complex coefficients has at least one complex root. Equivalently, the theorem states that thefield ofcomplex numbers isalgebraically closed. Among the notable mathematicians who worked on a proof during the 18th and 19th centuries wered'Alembert,Gauss,Bolzano, andWeierstrass, with Gauss usually being credited with the first correct proof. A consequence of this proof is that anynth root of a real orcomplex number will be on thecomplex plane.[20][21]

Theancient Greek mathematicians knew how touse compass and straightedge to construct a length equal to the square root of a given length, when an auxiliary line of unit length is given. In 1837Pierre Wantzel proved that annth root of a given length cannot be constructed ifn is not a power of 2.[22]

Definition and notation

[edit]
A unit circle on the complex plane with roots at 45 degree angles to the axes
The four 4th roots of −1, none of which are real
A unit circle on the complex plane with roots at 60 degrees to the positive x axis, and a third root at negative one
The three 3rd roots of −1, one of which is a negative real

Annth root of a numberx, wheren is a positive integer, is any of then real or complex numbersr whosenth power isx:

rn=x.{\displaystyle r^{n}=x.}

Every positivereal numberx has a single positiventh root, called theprincipalnth root, which is writtenxn{\displaystyle {\sqrt[{n}]{x}}}.[23] Forn equal to 2 this is called the principal square root and then is omitted. Thenth root can also be represented usingexponentiation asx1/n.[2]

For even values ofn, positive numbers also have a negativenth root, while negative numbers do not have a realnth root. For odd values ofn, every negative numberx has a real negativenth root.[23] For example, −2 has a real 5th root,25=1.148698354{\displaystyle {\sqrt[{5}]{-2}}=-1.148698354\ldots } but −2 does not have any real 6th roots.

Every non-zero numberx, real orcomplex, hasn different complex numbernth roots.[24] (In the casex is real, this count includes any realnth roots.) The only complex root of 0 is 0.

Thenth roots of almost all numbers (all integers except thenth powers, and all rationals except the quotients of twonth powers) areirrational.[25] For example,

2=1.414213562{\displaystyle {\sqrt {2}}=1.414213562\ldots }

Allnth roots of rational numbers arealgebraic numbers, and allnth roots of integers arealgebraic integers.

Square roots

[edit]
Main article:Square root
The graphy=±x{\displaystyle y=\pm {\sqrt {x}}}.

Asquare root of a numberx is a numberr which, whensquared, becomesx:

r2=x.{\displaystyle r^{2}=x.}

Every positive real number has two square roots, one positive and one negative. For example, the two square roots of 25 are 5 and −5. The positive square root is also known as theprincipal square root,[2] and is denoted with a radical sign:

25=5.{\displaystyle {\sqrt {25}}=5.}

Since the square of every real number is nonnegative, negative numbers do not have real square roots.[26] However, for every negative real number there are twoimaginary square roots. For example, the square roots of −25 are 5i and −5i, wherei represents a number whose square is−1.

Cube roots

[edit]
Main article:Cube root
The graphy=x3{\displaystyle y={\sqrt[{3}]{x}}}.

Acube root of a numberx is a numberr whosecube isx:

r3=x.{\displaystyle r^{3}=x.}

Every real numberx has exactly one real cube root,[2] writtenx3{\displaystyle {\sqrt[{3}]{x}}}. For example,

83=283=2.{\displaystyle {\begin{aligned}{\sqrt[{3}]{8}}&=2\\{\sqrt[{3}]{-8}}&=-2.\end{aligned}}}

Every real number has two additionalcomplex cube roots.[27][28]

Identities and properties

[edit]

Expressing the degree of annth root in its exponent form, as inx1/n{\displaystyle x^{1/n}}, makes it easier to manipulate powers and roots. Ifa{\displaystyle a} is anon-negative real number,[26]

amn=(am)1/n=am/n=(a1/n)m=(an)m.{\displaystyle {\sqrt[{n}]{a^{m}}}=(a^{m})^{1/n}=a^{m/n}=(a^{1/n})^{m}=({\sqrt[{n}]{a}})^{m}.}

Every non-negative number has exactly one non-negative realnth root, and so the rules for operations with surds involving non-negative radicandsa{\displaystyle a} andb{\displaystyle b} are straightforward within the real numbers:[26]

abn=anbnabn=anbn{\displaystyle {\begin{aligned}{\sqrt[{n}]{ab}}&={\sqrt[{n}]{a}}{\sqrt[{n}]{b}}\\{\sqrt[{n}]{\frac {a}{b}}}&={\frac {\sqrt[{n}]{a}}{\sqrt[{n}]{b}}}\end{aligned}}}

Subtleties can occur when taking thenth roots of negative orcomplex numbers. For instance:

1×11×1=1,{\displaystyle {\sqrt {-1}}\times {\sqrt {-1}}\neq {\sqrt {-1\times -1}}=1,\quad }

but, rather,

1×1=i×i=i2=1.{\displaystyle \quad {\sqrt {-1}}\times {\sqrt {-1}}=i\times i=i^{2}=-1.}

Since the rulean×bn=abn{\displaystyle {\sqrt[{n}]{a}}\times {\sqrt[{n}]{b}}={\sqrt[{n}]{ab}}} strictly holds for non-negative real radicands only, its application leads to the inequality in the first step above.[29]

Simplified form of a radical expression

[edit]

Anon-nested radical expression is said to be insimplified form if no factor of the radicand can be written as a power greater than or equal to the index; there are no fractions inside the radical sign; and there are no radicals in the denominator.[30]

For example, to write the radical expression32/5{\displaystyle \textstyle {\sqrt {32/5}}} in simplified form, we can proceed as follows. First, look for a perfect square under the square root sign and remove it:

325=1625=1625=425{\displaystyle {\sqrt {\frac {32}{5}}}={\sqrt {\frac {16\cdot 2}{5}}}={\sqrt {16}}\cdot {\sqrt {\frac {2}{5}}}=4{\sqrt {\frac {2}{5}}}}

Next, there is a fraction under the radical sign, which we change as follows:

425=425{\displaystyle 4{\sqrt {\frac {2}{5}}}={\frac {4{\sqrt {2}}}{\sqrt {5}}}}

Finally, we remove the radical from the denominator as follows:

425=42555=4105=4510{\displaystyle {\frac {4{\sqrt {2}}}{\sqrt {5}}}={\frac {4{\sqrt {2}}}{\sqrt {5}}}\cdot {\frac {\sqrt {5}}{\sqrt {5}}}={\frac {4{\sqrt {10}}}{5}}={\frac {4}{5}}{\sqrt {10}}}

When there is a denominator involving surds it is always possible to find a factor to multiply both numerator and denominator by to simplify the expression.[31][32] For instance using thefactorization of the sum of two cubes:

1a3+b3=a23ab3+b23(a3+b3)(a23ab3+b23)=a23ab3+b23a+b.{\displaystyle {\frac {1}{{\sqrt[{3}]{a}}+{\sqrt[{3}]{b}}}}={\frac {{\sqrt[{3}]{a^{2}}}-{\sqrt[{3}]{ab}}+{\sqrt[{3}]{b^{2}}}}{\left({\sqrt[{3}]{a}}+{\sqrt[{3}]{b}}\right)\left({\sqrt[{3}]{a^{2}}}-{\sqrt[{3}]{ab}}+{\sqrt[{3}]{b^{2}}}\right)}}={\frac {{\sqrt[{3}]{a^{2}}}-{\sqrt[{3}]{ab}}+{\sqrt[{3}]{b^{2}}}}{a+b}}.}

Simplifying radical expressions involvingnested radicals can be quite difficult. In particular, denesting is not always possible, and when possible, it may involve advancedGalois theory. Moreover, when complete denesting is impossible, there is no generalcanonical form such that the equality of two numbers can be tested by simply looking at their canonical expressions.

For example, it is not obvious that

3+22=1+2.{\displaystyle {\sqrt {3+2{\sqrt {2}}}}=1+{\sqrt {2}}.}

The above can be derived through:

3+22=1+22+2=12+22+22=(1+2)2=1+2{\displaystyle {\sqrt {3+2{\sqrt {2}}}}={\sqrt {1+2{\sqrt {2}}+2}}={\sqrt {1^{2}+2{\sqrt {2}}+{\sqrt {2}}^{2}}}={\sqrt {\left(1+{\sqrt {2}}\right)^{2}}}=1+{\sqrt {2}}}

Letr=p/q{\displaystyle r=p/q}, withp andq coprime and positive integers. Thenrn=pn/qn{\displaystyle {\sqrt[{n}]{r}}={\sqrt[{n}]{p}}/{\sqrt[{n}]{q}}} is rational if and only if bothpn{\displaystyle {\sqrt[{n}]{p}}} andqn{\displaystyle {\sqrt[{n}]{q}}} are integers, which means that bothp andq arenth powers of some integer.

Infinite series

[edit]

The radical or root may be represented by thegeneralized binomial theorem:

(1+x)s/t=m=0xmm!k=0m1(stk){\displaystyle (1+x)^{s/t}=\sum _{m=0}^{\infty }{\frac {x^{m}}{m!}}\prod _{k=0}^{m-1}\left({\frac {s}{t}}-k\right)}

with|x|<1{\displaystyle |x|<1}. This expression can be derived from thebinomial series.[33] For thenth root, this becomes

(1+x)1n=m=0xmm!k=0m1(1nk){\displaystyle (1+x)^{\frac {1}{n}}=\sum _{m=0}^{\infty }{\frac {x^{m}}{m!}}\prod _{k=0}^{m-1}\left({\frac {1}{n}}-k\right)}

For numbersr2{\displaystyle r\geq 2}, choose a valuep{\displaystyle p} such that

rpn1=x, where |x|<1{\displaystyle {\frac {r}{p^{n}}}-1=x',{\text{ where }}|x'|<1}

then per above, solve for

r1n=p(1+x)1n{\displaystyle r^{\frac {1}{n}}=p(1+x')^{\frac {1}{n}}}

As an example, forr=30{\displaystyle r=30} andn=2{\displaystyle n=2}, choosep=5{\displaystyle p=5}[33]

30521=525=.2{\displaystyle {\frac {30}{5^{2}}}-1={\frac {5}{25}}=.2}

30=51+.2=5[1+12(.2)118(.2)2+116(.2)3]5.4775{\displaystyle {\sqrt {30}}=5{\sqrt {1+.2}}=5\left[1+{\frac {1}{2}}(.2)^{1}-{\frac {1}{8}}(.2)^{2}+{\frac {1}{16}}(.2)^{3}-\cdots \right]\approx 5.4775}

Nth roots are used to check for convergence of apower series with theroot test.[34]

Computing principal roots

[edit]

Using Newton's method

[edit]

Thenth root of a positive real numberA can be computed withNewton's method, which starts with an initial guessx0, which is also a positive real number, and then iterates using therecurrence relation[35]

xk+1=xkxknAnxkn1{\displaystyle x_{k+1}=x_{k}-{\frac {x_{k}^{n}-A}{nx_{k}^{n-1}}}}

until the desired precision is reached. For computational efficiency, the recurrence relation can be rewritten[35]

xk+1=1n[(n1)xk+Axkn1].{\displaystyle x_{k+1}={\frac {1}{n}}\left[(n-1)\,x_{k}+\,{\frac {A}{x_{k}^{n-1}}}\right].}

This allows the relation to only have oneexponentiation, which is computed once for each iteration. Thenth root ofx can then be defined as thelimit ofxk{\displaystyle x_{k}} ask approaches infinity.

For example, to find the fifth root of 34, we plug inn = 5,A = 34 andx0 = 2 (initial guess). The first 5 iterations are, approximately:

x0 = 2
x1 = 2.025
x2 = 2.02439 7...
x3 = 2.02439 7458...
x4 = 2.02439 74584 99885 04251 08172...
x5 = 2.02439 74584 99885 04251 08172 45541 93741 91146 21701 07311 8...

(All correct digits shown.)

The approximationx4 is accurate to 25 decimal places andx5 is good for 51.

Newton's method can be modified to produce variousgeneralized continued fractions for thenth root. For example,[citation needed]

zn=xn+yn=x+ynxn1+(n1)y2x+(n+1)y3nxn1+(2n1)y2x+(2n+1)y5nxn1+(3n1)y2x+.{\displaystyle {\sqrt[{n}]{z}}={\sqrt[{n}]{x^{n}+y}}=x+{\cfrac {y}{nx^{n-1}+{\cfrac {(n-1)y}{2x+{\cfrac {(n+1)y}{3nx^{n-1}+{\cfrac {(2n-1)y}{2x+{\cfrac {(2n+1)y}{5nx^{n-1}+{\cfrac {(3n-1)y}{2x+\ddots }}}}}}}}}}}}.}

A suitable initial guess for Newton's method may need to be identified using thebisection method ormethod of false position.[36] For large values ofn and higher requirements for precision, a more rapid algorithm than Newton's method for finding thenth root is to use a truncatedTaylor series with aPadé approximant.[37]

Using the Viète technique

[edit]
Pascal's triangle showingP(4,1)=4{\displaystyle P(4,1)=4}.

The technique of François Viète, published c. 1600, can be used to perform digit-by-digit calculation of principal roots of decimal (base 10) numbers.[38] This method is based on thebinomial theorem and is essentially an inverse algorithm solving(10x+y)n=k=0nP(n,k)(10x)nkyk{\displaystyle (10x+y)^{n}=\sum _{k=0}^{n}P(n,k)(10x)^{n-k}y^{k}}whereP(n,k){\displaystyle P(n,k)}, thebinomial coefficient, is thekth entry on thenth row ofPascal's triangle.

To compute the root of a numberC, choose a series of approximationsxin,i=0,1, with x0=0{\displaystyle x_{i}^{n},i=0,1,\ldots {\text{ with }}x_{0}=0}that satisfyxinC{\displaystyle x_{i}^{n}\leq C}, where the difference betweenxi+1{\displaystyle x_{i+1}} andxi{\displaystyle x_{i}} is the next digit in the approximation. Thedecimal fractionyi{\displaystyle y_{i}} is chosen to be the largest number with a singlesignificant digit that satisfies10xi+yi=10xi+1, where xi+1nC{\displaystyle 10x_{i}+y_{i}=10x_{i+1},{\text{ where }}x_{i+1}^{n}\leq C}then per the binomial theorem(10xi+y)n(10xi)n=k=0n1P(n,k)(10xi)nkyik10n(Cxin){\displaystyle (10x_{i}+y)^{n}-(10x_{i})^{n}=\sum _{k=0}^{n-1}P(n,k)(10x_{i})^{n-k}y_{i}^{k}\leq 10^{n}(C-x_{i}^{n})}The term10n(Cxin){\displaystyle 10^{n}(C-x_{i}^{n})} is just a10n{\displaystyle 10^{n}} multiple of theith remainder,Cxin{\displaystyle C-x_{i}^{n}}.

Using this expression, any positive principal root can be computed, digit-by-digit, as follows.

Write the original number in decimal form. The numbers are written similar to thelong division algorithm, and, as in long division, the root will be written on the line above. Now separate the digits into groups of digits equating to the root being taken, starting from the decimal point and going both left and right. The decimal point of the root will be above the decimal point of the radicand. One digit of the root will appear above each group of digits of the original number.

Beginning with the left-most group of digits, do the following procedure for each group:

  1. Starting on the left, bring down the most significant (leftmost) group of digits not yet used (if all the digits have been used, write "0" the number of times required to make a group) and write them to the right of the remainder from the previous step (on the first step, there will be no remainder). In other words, multiply the remainder by10n{\displaystyle 10^{n}} and add the digits from the next group. This will be thecurrent valuec.
  2. Findp andx, as follows:
  3. Subtracty{\displaystyle y} fromc{\displaystyle c} to form a new remainder.
  4. If the remainder is zero and there are no more digits to bring down, then the algorithm has terminated. Otherwise go back to step 1 for another iteration.

Examples

[edit]
Find the square root of 152.2756
[edit]

For clarity, the value of the chosen digitx is inred while the current digital tally is inblue.

12.34
0152.2756(Results)(Explanation)
01x = 1:(1·100·00·12 + 2·101·01·11) ≤1< (1·100·00·22 + 2·101·01·21)
01y = 1:y = 1·100·00·12 + 2·101·01·11 = 1 + 0 =1
52.x = 2:(1·100·10·22 + 2·101·11·21) ≤52< (1·100·10·32 + 2·101·11·31)
44.y = 44:y = 1·100·10·22 + 2·101·11·21 = 4 + 40 =44
08.27x = 3:(1·100·120·32 + 2·101·121·31) ≤827< (1·100·120·42 + 2·101·121·41)
07.29y = 729:y = 1·100·120·32 + 2·101·121·31 = 9 + 720 =729
9856x = 4:(1·100·1230·42 + 2·101·1231·41) ≤9856< (1·100·1230·52 + 2·101·1231·51)
9856y = 9856:y = 1·100·1230·42 + 2·101·1231·41 = 16 + 9840 =9856
0000.0000

Algorithm terminates: Answer is 12.34

Find the cube root of 4192 truncated to the nearest thousandth
[edit]
16.124
004192.000000000(Results)(Explanation)
004x = 1:(1·100·00·13 + 3·101·01·12 + 3·102·02·11) ≤4< (1·100·00·23 + 3·101·01·22 + 3·102·02·21)
001y = 1:y = 1·100·00·13 + 3·101·01·12 + 3·102·02·11 = 1 + 0 + 0 =1
003192x = 6:(1·100·10·63 + 3·101·11·62 + 3·102·12·61) ≤52< (1·100·10·73 + 3·101·11·72 + 3·102·12·71)
003096y = 3,096:y = 1·100·10·63 + 3·101·11·62 + 3·102·12·61 = 4 + 40 =3,096
096000x = 1:(1·100·160·13 + 3·101·161·12 + 3·102·162·11) ≤96,000< (1·100·160·23 + 3·101·161·22 + 3·102·162·21)
077281y = 77,281:y = 1·100·160·13 + 3·101·161·12 + 3·102·162·11 = 1 + 480 + 76,800 =77,281
018719000x = 2:(1·100·1610·23 + 3·101·1611·22 + 3·102·1612·21) ≤18,719,000< (1·100·1610·33 + 3·101·1611·32 + 3·102·1612·31)
015571928y = 15,571,928:y = 1·100·1610·23 + 3·101·1611·22 + 3·102·1612·21 = 8 + 19,320 + 15,552,600 =15,571,928
003147072000x = 4:(1·100·16120·43 + 3·101·16121·42 + 3·102·16122·41) ≤3,147,072,000< (1·100·16120·53 + 3·101·16121·52 + 3·102·16122·51)

The desired precision is achieved. The cube root of 4,192 is 16.124...

Logarithmic calculation

[edit]

The principalnth root of a positive number can be computed usinglogarithms. Starting from the equation that definesr as annth root ofx, namelyrn=x,{\displaystyle r^{n}=x,} withx positive and therefore its principal rootr also positive, one takes logarithms of both sides (anybase of the logarithm will do) to obtain

nlogbr=logbxhencelogbr=logbxn.{\displaystyle n\log _{b}r=\log _{b}x\quad \quad {\text{hence}}\quad \quad \log _{b}r={\frac {\log _{b}x}{n}}.}

The rootr is recovered from this by taking theantilog:[39]

r=b1nlogbx.{\displaystyle r=b^{{\frac {1}{n}}\log _{b}x}.}

(Note: That formula showsb raised to the power of the result of the division, notb multiplied by the result of the division.)

For the case in whichx is negative andn is odd, there is one real rootr which is also negative. This can be found by first multiplying both sides of the defining equation by −1 to obtain|r|n=|x|,{\displaystyle |r|^{n}=|x|,} then proceeding as before to find |r|, and usingr = −|r|.

Complex roots

[edit]

Everycomplex number other than 0 hasn differentnth roots.[24]

Square roots

[edit]
The square roots ofi

The two square roots of a complex number are always negatives of each other.[40] For example, the square roots of−4 are2i and−2i, and the square roots ofi are

12(1+i)and12(1+i).{\displaystyle {\tfrac {1}{\sqrt {2}}}(1+i)\quad {\text{and}}\quad -{\tfrac {1}{\sqrt {2}}}(1+i).}

If we express a complex number inpolar form, then the square root can be obtained by taking the square root of the radius and halving the angle:[41]

reiθ=±reiθ/2.{\displaystyle {\sqrt {re^{i\theta }}}=\pm {\sqrt {r}}\cdot e^{i\theta /2}.}

Aprincipal root of a complex number may be chosen in various ways, for example

reiθ=reiθ/2{\displaystyle {\sqrt {re^{i\theta }}}={\sqrt {r}}\cdot e^{i\theta /2}}

which introduces abranch cut in thecomplex plane along thepositive real axis with the condition0 ≤ θ < 2π, or along the negative real axis withπ < θ ≤ π.

Using the first(last) branch cut the principal square rootz{\displaystyle \scriptstyle {\sqrt {z}}} mapsz{\displaystyle \scriptstyle z} to the half plane with non-negative imaginary(real) part. The last branch cut is presupposed inmathematical software likeMatlab orScilab.

Roots of unity

[edit]
Main article:Root of unity
The three 3rd roots of 1

The number 1 hasn differentnth roots in the complex plane,[24] namely

1,ω,ω2,,ωn1,{\displaystyle 1,\;\omega ,\;\omega ^{2},\;\ldots ,\;\omega ^{n-1},}

where

ω=e2πin=cos(2πn)+isin(2πn).{\displaystyle \omega =e^{\frac {2\pi i}{n}}=\cos \left({\frac {2\pi }{n}}\right)+i\sin \left({\frac {2\pi }{n}}\right).}

These roots are evenly spaced around theunit circle in the complex plane, at angles which are multiples of2π/n{\displaystyle 2\pi /n}. For example, the square roots of unity are 1 and −1, and the fourth roots of unity are 1,i{\displaystyle i}, −1, andi{\displaystyle -i}. As a result of this symmetry, the sum of thenth roots of unity equals zero.[42]k=0n1e2πink=0{\displaystyle \sum _{k=0}^{n-1}e^{{\frac {2\pi i}{n}}k}=0}

nth roots

[edit]
Geometric representation of the 2nd to 6th roots of a complex numberz, in polar formre wherer = |z | andφ = argz. Ifz is real,φ = 0 orπ. Principal roots are shown in black.

Every complex number hasn differentnth roots in the complex plane.[24] These are

η,ηω,ηω2,,ηωn1,{\displaystyle \eta ,\;\eta \omega ,\;\eta \omega ^{2},\;\ldots ,\;\eta \omega ^{n-1},}

whereη is a singlenth root, and 1, ωω2, ... ωn−1 are thenth roots of unity. Thus, since they are all just multiplied by the same scalarη, the sum of thenth roots equals zero.[42] For example, the four different fourth roots of 2 are

24,i24,24,andi24.{\displaystyle {\sqrt[{4}]{2}},\quad i{\sqrt[{4}]{2}},\quad -{\sqrt[{4}]{2}},\quad {\text{and}}\quad -i{\sqrt[{4}]{2}}.}

Inpolar form, a singlenth root may be found fromDemoivre's theorem:[43]

z1n=reiθn=rneiθ/n=r1n(cos(θn)+isin(θn)){\displaystyle z^{\frac {1}{n}}={\sqrt[{n}]{re^{i\theta }}}={\sqrt[{n}]{r}}\cdot e^{i\theta /n}=r^{\frac {1}{n}}\cdot \left(\cos \left({\frac {\theta }{n}}\right)+i\sin \left({\frac {\theta }{n}}\right)\right)}

Herer is the magnitude (the modulus, also called theabsolute value) of the number whose root is to be taken; if the number can be written asa+ib{\displaystyle a+ib} thenr=a2+b2{\displaystyle r={\sqrt {a^{2}+b^{2}}}}. Theθ{\displaystyle \theta } is the angle formed as one pivots on the origin counterclockwise from the positive horizontal axis to a ray going from the origin to the number; it has the properties that

cosθ=ar,sinθ=br, and tanθ=ba.{\displaystyle \cos \theta ={\frac {a}{r}},\sin \theta ={\frac {b}{r}},{\text{ and }}\tan \theta ={\frac {b}{a}}.}

Thus findingnth roots in the complex plane can be segmented into two steps. First, the magnitude of all thenth roots is thenth root of the magnitude of the original number. Second, the angle between the positive horizontal axis and a ray from the origin to one of thenth roots isθ/n{\displaystyle \theta /n}, whereθ{\displaystyle \theta } is the angle defined in the same way for the number whose root is being taken. Furthermore, alln of thenth roots are at equally spaced angles from each other, as proven by thenth root theorem[44]

rn(cos(θ+2πkn)+isin(θ+2πkn)) for k=0,1,2,,n1.{\displaystyle {\sqrt[{n}]{r}}\cdot \left(\cos \left({\frac {\theta +2\pi k}{n}}\right)+i\sin \left({\frac {\theta +2\pi k}{n}}\right)\right){\text{ for }}k=0,1,2,\ldots ,n-1.}

Ifn is even, a complex number'snth roots, of which there are an even number, come inadditive inverse pairs, so that if a numberr1 is one of thenth roots thenr2 = −r1 is another. This is because raising the latter's coefficient −1 to thenth power for evenn yields 1: that is, (−r1)n = (−1)n ×r1n =r1n.

As with square roots, the formula above does not define acontinuous function over the entire complex plane, but instead has abranch cut at points whereθ / n is discontinuous.

Polynomial roots

[edit]

Aroot of apolynomialp(x){\displaystyle p(x)} is a numbera{\displaystyle a} such thatp(a)=0{\displaystyle p(a)=0}. Annth root of a numbera{\displaystyle a} is by definition a root of the polynomialxna{\displaystyle x^{n}-a}.Algebraic numbers are the numbers that are polynomial roots.

Thequadratic formula expresses the roots ofquadratic polynomials in terms of square roots. During the 16th century,Gerolamo Cardano and other Italian mathematicians discovered that, similarly, the roots of the polynomials of degree 3 and 4 can always be expressed in terms ofnth roots (seeCubic equation andQuartic equation).[45]

During the two next centuries, a considerable effort was devoted to the question of whether every algebraic number can be expressed in terms of radicals. In 1824, the proof of theAbel–Ruffini theorem showed that there is nogeneral formula for the degree 5.[46] This did not completely exclude the possibility of expressing polynomial roots in terms of radicals with formulas depending on each specific polynomial. For example, thequintic polynomial

p(x)=(xa1)(xa2)(xa3)(xa4)(xa5)=0{\displaystyle p(x)=(x-a_{1})(x-a_{2})(x-a_{3})(x-a_{4})(x-a_{5})=0}

has radical rootsa1,a2,...,a5.{\displaystyle a_{1},a_{2},...,a_{5}.}Galois theory, introduced in 1830 showed that there are polynomials of degree 5 and higher whose roots cannot be expressed in terms of radicals, the simplest example beingx5x1{\displaystyle \textstyle x^{5}-x-1}.[47] SeeQuintic function § Solvable quintics andGalois theory § A non-solvable quintic example. In summary, radicals are not always sufficient for expressing polynomial roots.

In spite of this obstacle,Demoivre's theorem demonstrates that annth root of a number can always be extracted, even for aquintic functionx5a{\displaystyle x^{5}-a}.[43] The two following results, proved in the 19th century resolve fundamental problems on polynomial roots that were set in the 17th century. Thefundamental theorem of algebra asserts that every polynomial hascomplex roots.[19] There are numbers, calledtranscendental numbers that are not polynomial roots. The numberπ is an example of such a transcendental number.[48]

It may be unclear why any numberan{\displaystyle a^{n}} hasn roots rather than just a primary root. To demonstrate this, for the principal roota of the variablex taken to thenth power, the following polynomial relation holds:p(x)=xnan=0{\displaystyle p(x)=x^{n}-a^{n}=0}This polynomial can befactored as follows:[49]p(x)=xnan=(xa)(xn1+axn2+a2xn3++an1)=(xa)(k=0n1xnk1ak){\displaystyle {\begin{aligned}p(x)&=x^{n}-a^{n}\\&=(x-a)(x^{n-1}+ax^{n-2}+a^{2}x^{n-3}+\cdots +a^{n-1})\\&=(x-a)\left(\sum _{k=0}^{n-1}x^{n-k-1}a^{k}\right)\\\end{aligned}}}Thus, the polynomialp(x){\displaystyle p(x)} is zero forx equal toa, or for anyx that solves the equation:[50]k=0n1xnk1ak=0{\displaystyle \sum _{k=0}^{n-1}x^{n-k-1}a^{k}=0}By the fundamental theorem of algebra, this series hasn1{\displaystyle n-1} roots, for a combined total ofn{\displaystyle n}.

As an example, letn=3{\displaystyle n=3} anda=1{\displaystyle a=1}, then find the cube roots of 1[51]

p(x)=x313=(x1)(x2+x1+1)=0{\displaystyle p(x)=x^{3}-1^{3}=(x-1)(x^{2}+x^{1}+1)=0}

Thus the first root isx=1{\displaystyle x=1}, and the other two roots can be derived using thequadratic equation witha=b=c=1{\displaystyle a=b=c=1}[52]

x=b±b24ac2a=1±1242=1±i32{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}={\frac {-1\pm {\sqrt {1^{2}-4}}}{2}}={\frac {-1\pm i{\sqrt {3}}}{2}}}

Proof of irrationality for non-perfectnth powerx

[edit]

Assume thatxn{\displaystyle {\sqrt[{n}]{x}}} is rational. That is, it can be reduced to a fractionab{\displaystyle {\frac {a}{b}}}, wherea andb are integers without a common factor.

This means thatx=anbn{\displaystyle x={\frac {a^{n}}{b^{n}}}}.

Sincex is an integer,an{\displaystyle a^{n}}andbn{\displaystyle b^{n}}must share a common factor ifb1{\displaystyle b\neq 1}. This means that ifb1{\displaystyle b\neq 1},anbn{\displaystyle {\frac {a^{n}}{b^{n}}}} is not in simplest form. Thusb should equal 1.

Since1n=1{\displaystyle 1^{n}=1} andn1=n{\displaystyle {\frac {n}{1}}=n},anbn=an{\displaystyle {\frac {a^{n}}{b^{n}}}=a^{n}}.

This means thatx=an{\displaystyle x=a^{n}} and thus,xn=a{\displaystyle {\sqrt[{n}]{x}}=a}. This implies thatxn{\displaystyle {\sqrt[{n}]{x}}} is an integer. Sincex is not a perfectnth power, this is impossible. Thusxn{\displaystyle {\sqrt[{n}]{x}}} is irrational.[25]

See also

[edit]

References

[edit]
  1. ^"Lesson Explainer: nth Roots: Integers". Retrieved22 July 2023.
  2. ^abcdZuckerman, Martin M. (1986).Intermediate Algebra: A Straightforward Approach. Bloomsbury Publishing PLC. pp. 249–251.ISBN 978-1-4616-3783-7.
  3. ^Bansal, R. K. (2006).New Approach to CBSE Mathematics IX. Laxmi Publications. p. 25.ISBN 978-81-318-0013-3.
  4. ^abSilver, Howard A. (1986).Algebra and trigonometry. Englewood Cliffs, New Jersey: Prentice-Hall.ISBN 978-0-13-021270-2.
  5. ^Fowler, David; Robson, Eleanor (November 1998). "Square Root Approximations in Old Babylonian Mathematics: YBC 7289 in Context".Historia Mathematica.25 (4). Elsevier:366–378.doi:10.1006/hmat.1998.2209.
  6. ^Cooke, Roger L. (2012).The History of Mathematics: A Brief Course (3rd ed.). John Wiley & Sons.ISBN 978-1-118-46029-0.
  7. ^Von Fritz, Kurt (April 1945). "The Discovery of Incommensurability by Hippasus of Metapontum".Annals of Mathematics.46 (2):242–264.doi:10.2307/1969021.JSTOR 1969021.
  8. ^Heath, T. L. (1921).A History of Greek Mathematics, Volume 1, From Thales to Euclid. p. 155.
  9. ^Brezinski, Claude (2012).History of Continued Fractions and Padé Approximants. Springer Series in Computational Mathematics. Vol. 12. Springer Science & Business Media.ISBN 978-3-642-58169-4.
  10. ^Miller, Jeff."Earliest Known Uses of Some of the Words of Mathematics".Mathematics Pages. Retrieved2008-11-30.
  11. ^Hardy, G. H. (1921).A Course of Pure Mathematics (3rd ed.). Cambridge. §1.13 "Quadratic Surds" – §1.14, pp. 19–23.
  12. ^"Definition of RADICATION".www.merriam-webster.com. Retrieved2025-11-10.
  13. ^"radication – Definition of radication in English by Oxford Dictionaries".Oxford Dictionaries. Archived fromthe original on April 3, 2018.
  14. ^Hogendijk, J. P. (2004)."Pure mathematics in Islamic civilization". In Grattan-Guiness, Ivor (ed.).Companion Encyclopedia of the History and Philosophy of the Mathematical Sciences. Vol. 1. Routledge.ISBN 978-1-134-88748-4.
  15. ^Stedall, Jacqueline (2008).Mathematics Emerging: A Sourcebook 1540 – 1900. OUP Oxford. pp. 190–191.ISBN 978-0-19-152771-5.
  16. ^Ypma, Tjalling (1995)."Historical Development of the Newton-Raphson Method"(PDF). Western Washington University. Retrieved2025-11-08.
  17. ^Anton, Howard; et al. (2021).Calculus: Early Transcendentals (12th ed.). John Wiley & Sons. p. 236.ISBN 978-1-119-77818-9.
  18. ^Struik, Dirk Jan (2014).A Source Book in Mathematics, 1200-1800. Princeton Legacy Library. Princeton University Press.ISBN 978-1-4008-5800-2.
  19. ^abClark, Allan (2012).Elements of Abstract Algebra. Dover Books on Mathematics. Courier Corporation. p. xi.ISBN 978-0-486-14035-3.
  20. ^Stillwell, John (2013).Mathematics and Its History. Undergraduate Texts in Mathematics (2nd ed.). Springer Science & Business Media. pp. 266–267.ISBN 978-1-4684-9281-1.
  21. ^Fine, Benjamin; et al. (2017).Algebra and Number Theory: A Selection of Highlights. De Gruyter Textbook. Walter de Gruyter GmbH & Co KG. pp. 203–209.ISBN 978-3-11-051614-2.
  22. ^Wantzel,M. L. (1837)."Recherches sur les moyens de reconnaître si un Problème de Géométrie peut se résoudre avec la règle et le compas".Journal de Mathématiques Pures et Appliquées.1 (2):366–372. Archived fromthe original on 2024-02-09. Retrieved2024-02-09.
  23. ^abBrink, Raymond W. (1951).College Algebra. The Appleton-Century Mathematics Series (2nd ed.). New York: Appleton-Century-Crofts. p. 124.
  24. ^abcdBeilina, Larisa; et al. (2017).Numerical Linear Algebra: Theory and Applications. Springer. p. 7.ISBN 978-3-319-57304-5.
  25. ^abFine, Benjamin; Rosenberger, Gerhard (2007).Number Theory: An Introduction via the Distribution of Primes. Springer Science & Business Media.ISBN 978-0-8176-4541-0.
  26. ^abcGullberg, Jan (1997).Mathematics From the Birth of Numbers. W. W. Norton & Company. pp. 138–139.ISBN 978-0-393-04002-9.
  27. ^Burnside, William Snow; Panton, Arthur William (1881).The Theory of Equations: With an Introduction to the Theory of Binary Algebraic Forms. Dublin University Press series. Hodges, Figgis & Company. p. 45.
  28. ^James, R. C. (1992)."root of a number".Mathematics Dictionary (5th ed.). Springer Science & Business Media.ISBN 978-0-412-99041-0.
  29. ^Martínez, Alberto A. (2006).Negative Math: How Mathematical Rules Can be Positively Bent. Princeton University Press. pp. 122–123.ISBN 978-0-691-12309-7.
  30. ^McKeague, Charles P. (2011).Elementary algebra. Cengage Learning. p. 470.ISBN 978-0-8400-6421-9.
  31. ^Caviness, B. F.; Fateman, R. J."Simplification of Radical Expressions"(PDF).Proceedings of the 1976 ACM Symposium on Symbolic and Algebraic Computation. p. 329.
  32. ^Richard, Zippel (1985). "Simplification of Expressions Involving Radicals".Journal of Symbolic Computation.1 (189–210):189–210.doi:10.1016/S0747-7171(85)80014-6.
  33. ^abRoberts, Fred S.; Tesman, Barry (2024).Applied Combinatorics. Discrete Mathematics and Its Applications (3rd ed.). CRC Press. p. 277.ISBN 978-1-040-12029-3.
  34. ^Herman, Russell L. (2016).An Introduction to Fourier Analysis. CRC Press. p. 12.ISBN 978-1-4987-7371-3.
  35. ^abLange, Kenneth (2013).Optimization. Springer Texts in Statistics. Springer Science & Business Media. p. 156.ISBN 978-1-4757-4182-7.
  36. ^Dobrushkin, Vladimir A. (2016).Methods in Algorithmic Analysis. Chapman & Hall/CRC Computer and Information Science Series. CRC Press. p. 242.ISBN 978-1-4200-6830-6.
  37. ^Chen, S.-G.; Hsieh, P. Y. (1989). "Fast computation of the Nth root".Computers & Mathematics with Applications.17 (10):1423–1427.doi:10.1016/0898-1221(89)90024-2.
  38. ^Herrero Piñeyro, P. J.; Linero Bas, A.; Massa Esteve, M. R.; Mellado Romero, A. (2023)."A problem on the approximation of n-roots based on the Viète's work"(PDF).MATerials MATemàtics.5:1–27. Retrieved2025-11-15. See p. 8.
  39. ^Tang, Kwong-Tin (2006).Complex Analysis, Determinants and Matrices. Mathematical Methods for Engineers and Scientists. Vol. 1. Springer Science & Business Media. pp. 13–14.ISBN 978-3-540-30274-2.
  40. ^Bird, John (2007).Engineering Mathematics (5th, revised ed.). Routledge. p. 326.ISBN 978-1-136-34697-2.
  41. ^Hassani, Sadri (2008).Mathematical Methods: For Students of Physics and Related Fields (2nd ed.). Springer Science & Business Media. p. 488.ISBN 978-0-387-09504-2.
  42. ^abStefanucci, Gianluca; van Leeuwen, Robert (2013).Nonequilibrium Many-Body Theory of Quantum Systems: A Modern Introduction. Cambridge University Press. p. 503.ISBN 978-1-107-35457-9.
  43. ^abBurd, Adrian (2019).Mathematical Methods in the Earth and Environmental Sciences. Cambridge University Press. p. 571.ISBN 978-1-108-63126-6.
  44. ^Smith, Karl (2013).Precalculus: A Functional Approach to Graphing and Problem Solving. The Jones & Bartlett learning series in mathematics. Jones & Bartlett Publishers. p. 418.ISBN 978-0-7637-5177-7.
  45. ^Hale, Margie (2003).Essentials of Mathematics: Introduction to Theory, Proof, and the Professional Culture. Classroom resource materials. Vol. 21. Mathematical Association of America. p. 138.ISBN 978-0-88385-729-8.
  46. ^Rosen, Michael I. (1995). "Niels Hendrik Abel and Equations of the Fifth Degree".American Mathematical Monthly.102 (6):495–505.doi:10.2307/2974763.JSTOR 2974763.MR 1336636.Zbl 0836.01015.
  47. ^Bhattacharya, P. B.; et al. (1994).Basic Abstract Algebra. Cambridge University Press.ISBN 978-0-521-46081-1.
  48. ^Beckmann, Petr (1971).A History of Pi. Griffin Books. Macmillan. pp. 167–169.ISBN 978-0-312-38185-1.
  49. ^Pender, William; et al. (2011).Cambridge 3 Unit Mathematics Year 11. Cambridge University Press.ISBN 978-1-107-63332-2.
  50. ^Cox, David A. (2012).Galois Theory. Pure and Applied Mathematics: A Wiley Series of Texts, Monographs and Tracts (2nd ed.). John Wiley & Sons. p. 526.ISBN 978-1-118-07205-9.
  51. ^Leung, K. T.; et al. (1992).Polynomials and Equations: A Chinese Merchant Elite in Colonial Hong Kong (with a new preface). Hong Kong University Press.ISBN 978-962-209-271-6.
  52. ^McNamee, J. M.; Pan, Victor (2013).Numerical Methods for Roots of Polynomials - Part II. Studies in Computational Mathematics. Vol. 16. Newnes. p. 533.ISBN 978-0-08-093143-2.

External links

[edit]
Look upsurd in Wiktionary, the free dictionary.
Look upradical in Wiktionary, the free dictionary.
Primary
Leftinverse
Rightinverse
Related
articles
Retrieved from "https://en.wikipedia.org/w/index.php?title=Nth_root&oldid=1339314862"
Categories:
Hidden categories:

[8]ページ先頭

©2009-2026 Movatter.jp