std::chrono::operator==,<=>(std::chrono::year_month_day)

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std::chrono::year_month_day

Member functions
year_month_day::year_month_day
year_month_day::operator+=year_month_day::operator-=
year_month_day::yearyear_month_day::monthyear_month_day::day
year_month_day::operator sys_daysyear_month_day::operator local_days
year_month_day::ok
Nonmember functions
operator==operator<=>
operator+operator-
operator<<
from_stream
Helper classes
formatter<std::chrono::year_month_day>
hash<std::chrono::year_month_day> (C++26)

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Defined in header`<chrono>`
constexprbool operator==(conststd::chrono::year_month_day& x, conststd::chrono::year_month_day& y)noexcept;	(1)	(since C++20)
constexprstd::strong_ordering operator<=>(conststd::chrono::year_month_day& x, conststd::chrono::year_month_day& y)noexcept;	(2)	(since C++20)

Compares the twoyear_month_day valuesx andy. This is a lexicographical comparison: theyear() is compared first, thenmonth(), thenday().

The<,<=,>,>=, and!= operators aresynthesized fromoperator<=> andoperator== respectively.

[edit]Return value

1)x.year()== y.year()&& x.month()== y.month()&& x.day()== y.day()

2) Ifx.year()<=> y.year!=0,x.year()<=> y.year; otherwise ifx.month()<=> y.month()!=0,x.month()<=> y.month(); otherwisex.day()<=> y.day().

[edit]Notes

If bothx andy represent valid dates (x.ok()&& y.ok()==true), the result of the lexicographical comparison is consistent with the calendar order.

[edit]Example

Run this code

#include <chrono> int main(){constexprauto ymd1{std::chrono::day(13)/7/1337};constexprauto ymd2{std::chrono::year(1337)/7/13};    static_assert(ymd1== ymd2);    static_assert(ymd1<= ymd2);    static_assert(ymd1>= ymd2);    static_assert(ymd1<=> ymd2==0);}

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std::chrono::operator==,<=>(std::chrono::year_month_day)

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