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      std::chrono::weekday::operator+=,std::chrono::weekday::operator-=

      From cppreference.com
      <cpp‎ |chrono‎ |weekday
       
       
      Date and time library
       
       
      constexprstd::chrono::weekday& operator+=(conststd::chrono::days& d)noexcept;
      (1)(since C++20)
      constexprstd::chrono::weekday& operator-=(conststd::chrono::days& d)noexcept;
      (2)(since C++20)

      Adds or subtractsd.count() from the weekday value, reducing the result modulo 7 to an integer in the range[06].

      1) Performs*this=*this+ d;.
      2) Performs*this=*this- d;.

      Contents

      [edit]Return value

      A reference to thisweekday after modification.

      [edit]Notes

      After a call to one of these functions,ok() is always true if no overflow occurred during the operation.

      [edit]Example

      Run this code
      #include <chrono>#include <iostream> int main(){std::cout<<std::boolalpha; std::chrono::weekday wd{5};// Friday is 5    wd+=std::chrono::days(2);std::cout<<(wd==std::chrono::weekday(0))<<' '<<(wd==std::chrono::Sunday)<<' ';     wd-=std::chrono::days(3);std::cout<<(wd==std::chrono::weekday(4))<<' '<<(wd==std::chrono::Thursday)<<' ';     wd=std::chrono::Wednesday;    wd+=std::chrono::days{8};// ((3 += 8 == 11) % 7) == 4;std::cout<<(wd==std::chrono::Thursday)<<' ';     wd-=(std::chrono::Sunday-std::chrono::Tuesday);// -= -2// (4 -= -2) == 6std::cout<<(wd==std::chrono::Saturday)<<'\n';}

      Output:

      true true true true true true

      [edit]See also

      increments or decrements the weekday
      (public member function)[edit]
      performs arithmetic onweekdays
      (function)[edit]
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/chrono/weekday/operator_arith&oldid=157220"

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