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      std::bitset<N>::operator<<,<<=,>>,>>=

      From cppreference.com
      <cpp‎ |utility‎ |bitset
       
       
      Utilities library
       
       
      bitset operator<<(std::size_t pos)const;
      (1)(noexcept since C++11)
      (constexpr since C++23)
      bitset& operator<<=(std::size_t pos);
      (2)(noexcept since C++11)
      (constexpr since C++23)
      bitset operator>>(std::size_t pos)const;
      (3)(noexcept since C++11)
      (constexpr since C++23)
      bitset& operator>>=(std::size_t pos);
      (4)(noexcept since C++11)
      (constexpr since C++23)

      Performs binary shift left (towards higher index positions) and binary shift right (towards lower index positions). Zeroes are shifted in, and bits that would go to an index out of range are dropped (ignored).

      1,2) Performs binary shift left. The(2) version is destructive, i.e. performs the shift to the current object.
      3,4) Performs binary shift right. The(4) version is destructive, i.e. performs the shift to the current object.

      Contents

      [edit]Parameters

      pos - number of positions to shift the bits

      [edit]Return value

      1,3) New bitset object containing the shifted bits.
      2,4)*this

      [edit]Example

      Run this code
      #include <bitset>#include <iostream> int main(){std::bitset<8> b{0b01110010};std::cout<< b<<" (initial value)\n"; for(; b.any(); b>>=1){while(!b.test(0))            b>>=1;std::cout<< b<<'\n';} std::cout<< b<<" (final value)\n";}

      Output:

      01110010 (initial value)0011100100000111000000110000000100000000 (final value)

      [edit]See also

      (C++20)
      computes the result of bitwise left-rotation
      (function template)[edit]
      (C++20)
      computes the result of bitwise right-rotation
      (function template)[edit]
      performs binary AND, OR, XOR and NOT
      (public member function)[edit]
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/utility/bitset/operator_ltltgtgt&oldid=171732"

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